1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
|
/**
* Class used to communicate logging information; compatible with
* the C++ ACE ACE_Log_Record class.
*
* @author Chris Cleeland
*/
//package ACE.SimpleLogger;
import java.util.Date;
import java.io.DataOutputStream;
import java.io.DataInputStream;
import java.io.PrintStream;
import java.io.IOException;
public class LogRecord
{
final public int MAXLOGMSGLEN = 4 * 1024;
private int type_;
private int length_;
private int timeStamp_;
private int pid_;
private byte[] msgData_ = new byte[MAXLOGMSGLEN];
private final static int numIntMembers = 4;
private final static int sizeofIntInBytes = 4;
/**
* Create a default instance.
*/
public LogRecord()
{
this(0, (int) ((new Date()).getTime()/1000), 0);
}
/**
* Create a LogRecord. This is the designated initializer.
* @param priority a numeric specification of the priority (ascending)
* @param time_stamp time attached to the log entry in Unix <pre>time_t</pre> format
* @param pid the process ID; not currently used
*/
public LogRecord(int priority,
int timeStamp,
int pid)
{
type(priority);
timeStamp(timeStamp);
length(0);
pid(pid);
}
/**
* Conversion to string. Only includes the <pre>msgData_</pre> member.
*/
public String toString()
{
return new String(msgData_, 0);
}
/**
* Place a textual representation of the record on a PrintStream.
* @param hostname name of the host generating this record
* @param verbose if <b>true</b>, print information in the form, (give example)
* @param ps A PrintStream instance to which the output should go.
* @see PrintStream,String
*/
public void print(String hostname,
boolean verbose,
PrintStream ps)
{
String toprint;
if (verbose)
{
long cur = (long)timeStamp() * (long)1000;
Date now = new Date(cur);
/* 01234567890123456789012345 */
/* Wed Oct 18 14:25:36 1989n0 */
toprint = now.toString().substring(4) + "@"
+ hostname + "@" + pid_ + "@" + type_ + "@"
+ this.toString();
}
else
{
toprint = this.toString();
}
ps.println(toprint);
}
/**
* Streaming methods
*/
public void streamInFrom(DataInputStream dis) throws IOException
{
// Order here must match layout order in the C++ class.
// This, of course, is VERY fragile, and ought not be used as
// a model for anything except how NOT to do anything.
type(dis.readInt());
length(dis.readInt());
timeStamp(dis.readInt());
pid(dis.readInt());
// Does readFully() allocate space for the buffer? Either
// way, we won't have memory leaks :-)
int dataLength = (int) (length_ - numIntMembers * sizeofIntInBytes);
msgData_ = new byte[dataLength];
dis.readFully(msgData_, 0, dataLength);
}
public void streamOutTo(DataOutputStream dos) throws IOException
{
dos.writeInt(type());
dos.writeInt(length());
dos.writeInt(timeStamp());
dos.writeInt(pid());
int dataLength = (int) (length_ - numIntMembers * sizeofIntInBytes);
dos.write(msgData_, 0, dataLength);
}
/**
* Accessor methods
*/
public int type() { return type_; }
public void type(int t) { type_ = t; }
public int length() { return length_; }
public void length(int l) { length_ = l; }
private void setLen(int msgLen)
{ length(msgLen + numIntMembers * sizeofIntInBytes); }
public int timeStamp() { return timeStamp_; }
public void timeStamp(int t){ timeStamp_ = t; }
public int pid() { return pid_; }
public void pid(int p) { pid_ = p; }
public byte[] msgData() { return msgData_; }
public void msgData(byte[] m){ msgData_ = m; setLen(m.length); }
public void msgData(String m)
{
m.getBytes(0, m.length(), msgData_, 0);
setLen(m.length());
}
};
|
