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-rw-r--r--babel/numbers.py6
1 files changed, 4 insertions, 2 deletions
diff --git a/babel/numbers.py b/babel/numbers.py
index 8baf110..6c9ab24 100644
--- a/babel/numbers.py
+++ b/babel/numbers.py
@@ -426,7 +426,7 @@ def format_compact_decimal(number, *, format_type="short", locale=LC_NUMERIC, fr
>>> format_compact_decimal(12345, format_type="long", locale='en_US')
u'12 thousand'
>>> format_compact_decimal(12345, format_type="short", locale='en_US', fraction_digits=2)
- u'12.35K'
+ u'12.34K'
>>> format_compact_decimal(1234567, format_type="short", locale="ja_JP")
u'123δΈ‡'
>>> format_compact_decimal(2345678, format_type="long", locale="mk")
@@ -454,6 +454,8 @@ def _get_compact_format(number, compact_format, locale, fraction_digits=0):
The algorithm is described here:
https://www.unicode.org/reports/tr35/tr35-45/tr35-numbers.html#Compact_Number_Formats.
"""
+ if not isinstance(number, decimal.Decimal):
+ number = decimal.Decimal(str(number))
format = None
for magnitude in sorted([int(m) for m in compact_format["other"]], reverse=True):
if abs(number) >= magnitude:
@@ -465,7 +467,7 @@ def _get_compact_format(number, compact_format, locale, fraction_digits=0):
break
# otherwise, we need to divide the number by the magnitude but remove zeros
# equal to the number of 0's in the pattern minus 1
- number = number / (magnitude / (10 ** (pattern.count("0") - 1)))
+ number = number / (magnitude // (10 ** (pattern.count("0") - 1)))
# round to the number of fraction digits requested
number = round(number, fraction_digits)
# if the remaining number is singular, use the singular format