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+[library python
+ [version 2.0]
+ [authors [de Guzman, Joel], [Abrahams, David]]
+ [copyright 2002 2003 2004 2005 Joel de Guzman, David Abrahams]
+ [category inter-language support]
+ [purpose
+ Reflects C++ classes and functions into Python
+ ]
+ [license
+ Distributed under the Boost Software License, Version 1.0.
+ (See accompanying file LICENSE_1_0.txt or copy at
+ <ulink url="http://www.boost.org/LICENSE_1_0.txt">
+ http://www.boost.org/LICENSE_1_0.txt
+ </ulink>)
+ ]
+]
+
+[/ QuickBook Document version 0.9 ]
+
+[def __note__ [$images/note.png]]
+[def __alert__ [$images/alert.png]]
+[def __tip__ [$images/tip.png]]
+[def :-) [$images/smiley.png]]
+[def __jam__ [$images/jam.png]]
+
+[section QuickStart]
+
+The Boost Python Library is a framework for interfacing Python and
+C++. It allows you to quickly and seamlessly expose C++ classes
+functions and objects to Python, and vice-versa, using no special
+tools -- just your C++ compiler. It is designed to wrap C++ interfaces
+non-intrusively, so that you should not have to change the C++ code at
+all in order to wrap it, making Boost.Python ideal for exposing
+3rd-party libraries to Python. The library's use of advanced
+metaprogramming techniques simplifies its syntax for users, so that
+wrapping code takes on the look of a kind of declarative interface
+definition language (IDL).
+
+[h2 Hello World]
+
+Following C/C++ tradition, let's start with the "hello, world". A C++
+Function:
+
+ char const* greet()
+ {
+ return "hello, world";
+ }
+
+can be exposed to Python by writing a Boost.Python wrapper:
+
+ #include <boost/python.hpp>
+
+ BOOST_PYTHON_MODULE(hello_ext)
+ {
+ using namespace boost::python;
+ def("greet", greet);
+ }
+
+That's it. We're done. We can now build this as a shared library. The
+resulting DLL is now visible to Python. Here's a sample Python session:
+
+[python]
+
+ >>> import hello_ext
+ >>> print hello_ext.greet()
+ hello, world
+
+[c++]
+
+[:['[*Next stop... Building your Hello World module from start to finish...]]]
+
+[endsect]
+[section:hello Building Hello World]
+
+[h2 From Start To Finish]
+
+Now the first thing you'd want to do is to build the Hello World module and
+try it for yourself in Python. In this section, we will outline the steps
+necessary to achieve that. We will use the build tool that comes bundled
+with every boost distribution: [*bjam].
+
+[note [*Building without bjam]
+
+Besides bjam, there are of course other ways to get your module built.
+What's written here should not be taken as "the one and only way".
+There are of course other build tools apart from [^bjam].
+
+Take note however that the preferred build tool for Boost.Python is bjam.
+There are so many ways to set up the build incorrectly. Experience shows
+that 90% of the "I can't build Boost.Python" problems come from people
+who had to use a different tool.
+]
+
+We will skip over the details. Our objective will be to simply create
+the hello world module and run it in Python. For a complete reference to
+building Boost.Python, check out: [@../../../building.html
+building.html]. After this brief ['bjam] tutorial, we should have built
+the DLLs and run a python program using the extension.
+
+The tutorial example can be found in the directory:
+[^libs/python/example/tutorial]. There, you can find:
+
+* hello.cpp
+* hello.py
+* Jamroot
+
+The [^hello.cpp] file is our C++ hello world example. The [^Jamroot] is
+a minimalist ['bjam] script that builds the DLLs for us. Finally,
+[^hello.py] is our Python program that uses the extension in
+[^hello.cpp].
+
+Before anything else, you should have the bjam executable in your boost
+directory or somewhere in your path such that [^bjam] can be executed in
+the command line. Pre-built Boost.Jam executables are available for most
+platforms. The complete list of Bjam executables can be found
+[@http://sourceforge.net/project/showfiles.php?group_id=7586 here].
+
+[h2 Let's Jam!]
+__jam__
+
+[@../../../../example/tutorial/Jamroot Here] is our minimalist Jamroot
+file. Simply copy the file and tweak [^use-project boost] to where your
+boost root directory is and your OK.
+
+The comments contained in the Jamrules file above should be sufficient
+to get you going.
+
+[h2 Running bjam]
+
+['bjam] is run using your operating system's command line interpreter.
+
+[:Start it up.]
+
+A file called user-config.jam in your home directory is used to
+configure your tools. In Windows, your home directory can be found by
+typing:
+
+[pre
+ECHO %HOMEDRIVE%%HOMEPATH%
+]
+
+into a command prompt window. Your file should at least have the rules
+for your compiler and your python installation. A specific example of
+this on Windows would be:
+
+[pre
+# MSVC configuration
+using msvc : 8.0 ;
+
+# Python configuration
+using python : 2.4 : C:/dev/tools/Python/ ;
+]
+
+The first rule tells Bjam to use the MSVC 8.0 compiler and associated
+tools. The second rule provides information on Python, its version and
+where it is located. The above assumes that the Python installation is
+in [^C:/dev/tools\/Python/]. If you have one fairly "standard" python
+installation for your platform, you might not need to do this.
+
+Now we are ready... Be sure to [^cd] to [^libs/python/example/tutorial]
+where the tutorial [^"hello.cpp"] and the [^"Jamroot"] is situated.
+
+Finally:
+
+ bjam
+
+It should be building now:
+
+[pre
+cd C:\dev\boost\libs\python\example\tutorial
+bjam
+...patience...
+...found 1101 targets...
+...updating 35 targets...
+]
+
+And so on... Finally:
+
+[pre
+ Creating library /path-to-boost_python.dll/
+ Creating library /path-to-'''hello_ext'''.exp/
+'''**passed**''' ... hello.test
+...updated 35 targets...
+]
+
+Or something similar. If all is well, you should now have built the DLLs and
+run the Python program.
+
+[:[*There you go... Have fun!]]
+
+[endsect]
+[section:exposing Exposing Classes]
+
+Now let's expose a C++ class to Python.
+
+Consider a C++ class/struct that we want to expose to Python:
+
+ struct World
+ {
+ void set(std::string msg) { this->msg = msg; }
+ std::string greet() { return msg; }
+ std::string msg;
+ };
+
+We can expose this to Python by writing a corresponding Boost.Python
+C++ Wrapper:
+
+ #include <boost/python.hpp>
+ using namespace boost::python;
+
+ BOOST_PYTHON_MODULE(hello)
+ {
+ class_<World>("World")
+ .def("greet", &World::greet)
+ .def("set", &World::set)
+ ;
+ }
+
+Here, we wrote a C++ class wrapper that exposes the member functions
+[^greet] and [^set]. Now, after building our module as a shared library, we
+may use our class [^World] in Python. Here's a sample Python session:
+
+[python]
+
+ >>> import hello
+ >>> planet = hello.World()
+ >>> planet.set('howdy')
+ >>> planet.greet()
+ 'howdy'
+
+[section Constructors]
+
+Our previous example didn't have any explicit constructors.
+Since [^World] is declared as a plain struct, it has an implicit default
+constructor. Boost.Python exposes the default constructor by default,
+which is why we were able to write
+
+ >>> planet = hello.World()
+
+We may wish to wrap a class with a non-default constructor. Let us
+build on our previous example:
+
+[c++]
+
+ struct World
+ {
+ World(std::string msg): msg(msg) {} // added constructor
+ void set(std::string msg) { this->msg = msg; }
+ std::string greet() { return msg; }
+ std::string msg;
+ };
+
+This time [^World] has no default constructor; our previous
+wrapping code would fail to compile when the library tried to expose
+it. We have to tell [^class_<World>] about the constructor we want to
+expose instead.
+
+ #include <boost/python.hpp>
+ using namespace boost::python;
+
+ BOOST_PYTHON_MODULE(hello)
+ {
+ class_<World>("World", init<std::string>())
+ .def("greet", &World::greet)
+ .def("set", &World::set)
+ ;
+ }
+
+[^init<std::string>()] exposes the constructor taking in a
+[^std::string] (in Python, constructors are spelled
+"[^"__init__"]").
+
+We can expose additional constructors by passing more [^init<...>]s to
+the [^def()] member function. Say for example we have another World
+constructor taking in two doubles:
+
+ class_<World>("World", init<std::string>())
+ .def(init<double, double>())
+ .def("greet", &World::greet)
+ .def("set", &World::set)
+ ;
+
+On the other hand, if we do not wish to expose any constructors at
+all, we may use [^no_init] instead:
+
+ class_<Abstract>("Abstract", no_init)
+
+This actually adds an [^__init__] method which always raises a
+Python RuntimeError exception.
+
+[endsect]
+[section Class Data Members]
+
+Data members may also be exposed to Python so that they can be
+accessed as attributes of the corresponding Python class. Each data
+member that we wish to be exposed may be regarded as [*read-only] or
+[*read-write]. Consider this class [^Var]:
+
+ struct Var
+ {
+ Var(std::string name) : name(name), value() {}
+ std::string const name;
+ float value;
+ };
+
+Our C++ [^Var] class and its data members can be exposed to Python:
+
+ class_<Var>("Var", init<std::string>())
+ .def_readonly("name", &Var::name)
+ .def_readwrite("value", &Var::value);
+
+Then, in Python, assuming we have placed our Var class inside the namespace
+hello as we did before:
+
+[python]
+
+ >>> x = hello.Var('pi')
+ >>> x.value = 3.14
+ >>> print x.name, 'is around', x.value
+ pi is around 3.14
+
+Note that [^name] is exposed as [*read-only] while [^value] is exposed
+as [*read-write].
+
+ >>> x.name = 'e' # can't change name
+ Traceback (most recent call last):
+ File "<stdin>", line 1, in ?
+ AttributeError: can't set attribute
+
+[endsect]
+[section Class Properties]
+
+In C++, classes with public data members are usually frowned
+upon. Well designed classes that take advantage of encapsulation hide
+the class' data members. The only way to access the class' data is
+through access (getter/setter) functions. Access functions expose class
+properties. Here's an example:
+
+[c++]
+
+ struct Num
+ {
+ Num();
+ float get() const;
+ void set(float value);
+ ...
+ };
+
+However, in Python attribute access is fine; it doesn't neccessarily break
+encapsulation to let users handle attributes directly, because the
+attributes can just be a different syntax for a method call. Wrapping our
+[^Num] class using Boost.Python:
+
+ class_<Num>("Num")
+ .add_property("rovalue", &Num::get)
+ .add_property("value", &Num::get, &Num::set);
+
+And at last, in Python:
+
+[python]
+
+ >>> x = Num()
+ >>> x.value = 3.14
+ >>> x.value, x.rovalue
+ (3.14, 3.14)
+ >>> x.rovalue = 2.17 # error!
+
+Take note that the class property [^rovalue] is exposed as [*read-only]
+since the [^rovalue] setter member function is not passed in:
+
+[c++]
+
+ .add_property("rovalue", &Num::get)
+
+[endsect]
+[section Inheritance]
+
+In the previous examples, we dealt with classes that are not polymorphic.
+This is not often the case. Much of the time, we will be wrapping
+polymorphic classes and class hierarchies related by inheritance. We will
+often have to write Boost.Python wrappers for classes that are derived from
+abstract base classes.
+
+Consider this trivial inheritance structure:
+
+ struct Base { virtual ~Base(); };
+ struct Derived : Base {};
+
+And a set of C++ functions operating on [^Base] and [^Derived] object
+instances:
+
+ void b(Base*);
+ void d(Derived*);
+ Base* factory() { return new Derived; }
+
+We've seen how we can wrap the base class [^Base]:
+
+ class_<Base>("Base")
+ /*...*/
+ ;
+
+Now we can inform Boost.Python of the inheritance relationship between
+[^Derived] and its base class [^Base]. Thus:
+
+ class_<Derived, bases<Base> >("Derived")
+ /*...*/
+ ;
+
+Doing so, we get some things for free:
+
+# Derived automatically inherits all of Base's Python methods
+ (wrapped C++ member functions)
+# [*If] Base is polymorphic, [^Derived] objects which have been passed to
+ Python via a pointer or reference to [^Base] can be passed where a pointer
+ or reference to [^Derived] is expected.
+
+Now, we will expose the C++ free functions [^b] and [^d] and [^factory]:
+
+ def("b", b);
+ def("d", d);
+ def("factory", factory);
+
+Note that free function [^factory] is being used to generate new
+instances of class [^Derived]. In such cases, we use
+[^return_value_policy<manage_new_object>] to instruct Python to adopt
+the pointer to [^Base] and hold the instance in a new Python [^Base]
+object until the the Python object is destroyed. We will see more of
+Boost.Python [link python.call_policies call policies] later.
+
+ // Tell Python to take ownership of factory's result
+ def("factory", factory,
+ return_value_policy<manage_new_object>());
+
+[endsect]
+
+[section Class Virtual Functions]
+
+In this section, we will learn how to make functions behave polymorphically
+through virtual functions. Continuing our example, let us add a virtual function
+to our [^Base] class:
+
+ struct Base
+ {
+ virtual ~Base() {}
+ virtual int f() = 0;
+ };
+
+One of the goals of Boost.Python is to be minimally intrusive on an existing C++
+design. In principle, it should be possible to expose the interface for a 3rd
+party library without changing it. It is not ideal to add anything to our class
+`Base`. Yet, when you have a virtual function that's going to be overridden in
+Python and called polymorphically *from C++*, we'll need to add some
+scaffoldings to make things work properly. What we'll do is write a class
+wrapper that derives from `Base` that will unintrusively hook into the virtual
+functions so that a Python override may be called:
+
+ struct BaseWrap : Base, wrapper<Base>
+ {
+ int f()
+ {
+ return this->get_override("f")();
+ }
+ };
+
+Notice too that in addition to inheriting from `Base`, we also multiply-
+inherited `wrapper<Base>` (See [@../../../v2/wrapper.html Wrapper]). The
+`wrapper` template makes the job of wrapping classes that are meant to
+overridden in Python, easier.
+
+[blurb __alert__ [*MSVC6/7 Workaround]
+
+If you are using Microsoft Visual C++ 6 or 7, you have to write `f` as:
+
+`return call<int>(this->get_override("f").ptr());`.]
+
+BaseWrap's overridden virtual member function `f` in effect calls the
+corresponding method of the Python object through `get_override`.
+
+Finally, exposing `Base`:
+
+ class_<BaseWrap, boost::noncopyable>("Base")
+ .def("f", pure_virtual(&Base::f))
+ ;
+
+`pure_virtual` signals Boost.Python that the function `f` is a pure virtual
+function.
+
+[note [*member function and methods]
+
+Python, like many object oriented languages uses the term [*methods].
+Methods correspond roughly to C++'s [*member functions]]
+
+[endsect]
+
+[section Virtual Functions with Default Implementations]
+
+We've seen in the previous section how classes with pure virtual functions are
+wrapped using Boost.Python's [@../../../v2/wrapper.html class wrapper]
+facilities. If we wish to wrap [*non]-pure-virtual functions instead, the
+mechanism is a bit different.
+
+Recall that in the [link python.class_virtual_functions previous section], we
+wrapped a class with a pure virtual function that we then implemented in C++, or
+Python classes derived from it. Our base class:
+
+ struct Base
+ {
+ virtual int f() = 0;
+ };
+
+had a pure virtual function [^f]. If, however, its member function [^f] was
+not declared as pure virtual:
+
+ struct Base
+ {
+ virtual ~Base() {}
+ virtual int f() { return 0; }
+ };
+
+We wrap it this way:
+
+ struct BaseWrap : Base, wrapper<Base>
+ {
+ int f()
+ {
+ if (override f = this->get_override("f"))
+ return f(); // *note*
+ return Base::f();
+ }
+
+ int default_f() { return this->Base::f(); }
+ };
+
+Notice how we implemented `BaseWrap::f`. Now, we have to check if there is an
+override for `f`. If none, then we call `Base::f()`.
+
+[blurb __alert__ [*MSVC6/7 Workaround]
+
+If you are using Microsoft Visual C++ 6 or 7, you have to rewrite the line
+with the `*note*` as:
+
+`return call<char const*>(f.ptr());`.]
+
+Finally, exposing:
+
+ class_<BaseWrap, boost::noncopyable>("Base")
+ .def("f", &Base::f, &BaseWrap::default_f)
+ ;
+
+Take note that we expose both `&Base::f` and `&BaseWrap::default_f`.
+Boost.Python needs to keep track of 1) the dispatch function [^f] and 2) the
+forwarding function to its default implementation [^default_f]. There's a
+special [^def] function for this purpose.
+
+In Python, the results would be as expected:
+
+[python]
+
+ >>> base = Base()
+ >>> class Derived(Base):
+ ... def f(self):
+ ... return 42
+ ...
+ >>> derived = Derived()
+
+Calling [^base.f()]:
+
+ >>> base.f()
+ 0
+
+Calling [^derived.f()]:
+
+ >>> derived.f()
+ 42
+
+[endsect]
+[section Class Operators/Special Functions]
+
+[h2 Python Operators]
+
+C is well known for the abundance of operators. C++ extends this to the
+extremes by allowing operator overloading. Boost.Python takes advantage of
+this and makes it easy to wrap C++ operator-powered classes.
+
+Consider a file position class [^FilePos] and a set of operators that take
+on FilePos instances:
+
+[c++]
+
+ class FilePos { /*...*/ };
+
+ FilePos operator+(FilePos, int);
+ FilePos operator+(int, FilePos);
+ int operator-(FilePos, FilePos);
+ FilePos operator-(FilePos, int);
+ FilePos& operator+=(FilePos&, int);
+ FilePos& operator-=(FilePos&, int);
+ bool operator<(FilePos, FilePos);
+
+The class and the various operators can be mapped to Python rather easily
+and intuitively:
+
+ class_<FilePos>("FilePos")
+ .def(self + int()) // __add__
+ .def(int() + self) // __radd__
+ .def(self - self) // __sub__
+ .def(self - int()) // __sub__
+ .def(self += int()) // __iadd__
+ .def(self -= other<int>())
+ .def(self < self); // __lt__
+
+The code snippet above is very clear and needs almost no explanation at
+all. It is virtually the same as the operators' signatures. Just take
+note that [^self] refers to FilePos object. Also, not every class [^T] that
+you might need to interact with in an operator expression is (cheaply)
+default-constructible. You can use [^other<T>()] in place of an actual
+[^T] instance when writing "self expressions".
+
+[h2 Special Methods]
+
+Python has a few more ['Special Methods]. Boost.Python supports all of the
+standard special method names supported by real Python class instances. A
+similar set of intuitive interfaces can also be used to wrap C++ functions
+that correspond to these Python ['special functions]. Example:
+
+ class Rational
+ { public: operator double() const; };
+
+ Rational pow(Rational, Rational);
+ Rational abs(Rational);
+ ostream& operator<<(ostream&,Rational);
+
+ class_<Rational>("Rational")
+ .def(float_(self)) // __float__
+ .def(pow(self, other<Rational>)) // __pow__
+ .def(abs(self)) // __abs__
+ .def(str(self)) // __str__
+ ;
+
+Need we say more?
+
+[note What is the business of `operator<<`?
+Well, the method `str` requires the `operator<<` to do its work (i.e.
+`operator<<` is used by the method defined by `def(str(self))`.]
+
+[endsect]
+[endsect] [/ Exposing Classes ]
+
+[section Functions]
+
+In this chapter, we'll look at Boost.Python powered functions in closer
+detail. We will see some facilities to make exposing C++ functions to
+Python safe from potential pifalls such as dangling pointers and
+references. We will also see facilities that will make it even easier for
+us to expose C++ functions that take advantage of C++ features such as
+overloading and default arguments.
+
+[:['Read on...]]
+
+But before you do, you might want to fire up Python 2.2 or later and type
+[^>>> import this].
+
+[pre
+>>> import this
+The Zen of Python, by Tim Peters
+Beautiful is better than ugly.
+Explicit is better than implicit.
+Simple is better than complex.
+Complex is better than complicated.
+Flat is better than nested.
+Sparse is better than dense.
+Readability counts.
+Special cases aren't special enough to break the rules.
+Although practicality beats purity.
+Errors should never pass silently.
+Unless explicitly silenced.
+In the face of ambiguity, refuse the temptation to guess.
+There should be one-- and preferably only one --obvious way to do it
+Although that way may not be obvious at first unless you're Dutch.
+Now is better than never.
+Although never is often better than *right* now.
+If the implementation is hard to explain, it's a bad idea.
+If the implementation is easy to explain, it may be a good idea.
+Namespaces are one honking great idea -- let's do more of those!
+]
+
+[section Call Policies]
+
+In C++, we often deal with arguments and return types such as pointers
+and references. Such primitive types are rather, ummmm, low level and
+they really don't tell us much. At the very least, we don't know the
+owner of the pointer or the referenced object. No wonder languages
+such as Java and Python never deal with such low level entities. In
+C++, it's usually considered a good practice to use smart pointers
+which exactly describe ownership semantics. Still, even good C++
+interfaces use raw references and pointers sometimes, so Boost.Python
+must deal with them. To do this, it may need your help. Consider the
+following C++ function:
+
+ X& f(Y& y, Z* z);
+
+How should the library wrap this function? A naive approach builds a
+Python X object around result reference. This strategy might or might
+not work out. Here's an example where it didn't
+
+ >>> x = f(y, z) # x refers to some C++ X
+ >>> del y
+ >>> x.some_method() # CRASH!
+
+What's the problem?
+
+Well, what if f() was implemented as shown below:
+
+ X& f(Y& y, Z* z)
+ {
+ y.z = z;
+ return y.x;
+ }
+
+The problem is that the lifetime of result X& is tied to the lifetime
+of y, because the f() returns a reference to a member of the y
+object. This idiom is is not uncommon and perfectly acceptable in the
+context of C++. However, Python users should not be able to crash the
+system just by using our C++ interface. In this case deleting y will
+invalidate the reference to X. We have a dangling reference.
+
+Here's what's happening:
+
+# [^f] is called passing in a reference to [^y] and a pointer to [^z]
+# A reference to [^y.x] is returned
+# [^y] is deleted. [^x] is a dangling reference
+# [^x.some_method()] is called
+# [*BOOM!]
+
+We could copy result into a new object:
+
+[python]
+
+ >>> f(y, z).set(42) # Result disappears
+ >>> y.x.get() # No crash, but still bad
+ 3.14
+
+This is not really our intent of our C++ interface. We've broken our
+promise that the Python interface should reflect the C++ interface as
+closely as possible.
+
+Our problems do not end there. Suppose Y is implemented as follows:
+
+[c++]
+
+ struct Y
+ {
+ X x; Z* z;
+ int z_value() { return z->value(); }
+ };
+
+Notice that the data member [^z] is held by class Y using a raw
+pointer. Now we have a potential dangling pointer problem inside Y:
+
+ >>> x = f(y, z) # y refers to z
+ >>> del z # Kill the z object
+ >>> y.z_value() # CRASH!
+
+For reference, here's the implementation of [^f] again:
+
+ X& f(Y& y, Z* z)
+ {
+ y.z = z;
+ return y.x;
+ }
+
+Here's what's happening:
+
+# [^f] is called passing in a reference to [^y] and a pointer to [^z]
+# A pointer to [^z] is held by [^y]
+# A reference to [^y.x] is returned
+# [^z] is deleted. [^y.z] is a dangling pointer
+# [^y.z_value()] is called
+# [^z->value()] is called
+# [*BOOM!]
+
+[h2 Call Policies]
+
+Call Policies may be used in situations such as the example detailed above.
+In our example, [^return_internal_reference] and [^with_custodian_and_ward]
+are our friends:
+
+ def("f", f,
+ return_internal_reference<1,
+ with_custodian_and_ward<1, 2> >());
+
+What are the [^1] and [^2] parameters, you ask?
+
+ return_internal_reference<1
+
+Informs Boost.Python that the first argument, in our case [^Y& y], is the
+owner of the returned reference: [^X&]. The "[^1]" simply specifies the
+first argument. In short: "return an internal reference [^X&] owned by the
+1st argument [^Y& y]".
+
+ with_custodian_and_ward<1, 2>
+
+Informs Boost.Python that the lifetime of the argument indicated by ward
+(i.e. the 2nd argument: [^Z* z]) is dependent on the lifetime of the
+argument indicated by custodian (i.e. the 1st argument: [^Y& y]).
+
+It is also important to note that we have defined two policies above. Two
+or more policies can be composed by chaining. Here's the general syntax:
+
+ policy1<args...,
+ policy2<args...,
+ policy3<args...> > >
+
+Here is the list of predefined call policies. A complete reference detailing
+these can be found [@../../../v2/reference.html#models_of_call_policies here].
+
+* [*with_custodian_and_ward]: Ties lifetimes of the arguments
+* [*with_custodian_and_ward_postcall]: Ties lifetimes of the arguments and results
+* [*return_internal_reference]: Ties lifetime of one argument to that of result
+* [*return_value_policy<T> with T one of:]
+ * [*reference_existing_object]: naive (dangerous) approach
+ * [*copy_const_reference]: Boost.Python v1 approach
+ * [*copy_non_const_reference]:
+ * [*manage_new_object]: Adopt a pointer and hold the instance
+
+[blurb :-) [*Remember the Zen, Luke:]
+
+"Explicit is better than implicit"
+
+"In the face of ambiguity, refuse the temptation to guess"
+]
+
+[endsect]
+[section Overloading]
+
+The following illustrates a scheme for manually wrapping an overloaded
+member functions. Of course, the same technique can be applied to wrapping
+overloaded non-member functions.
+
+We have here our C++ class:
+
+ struct X
+ {
+ bool f(int a)
+ {
+ return true;
+ }
+
+ bool f(int a, double b)
+ {
+ return true;
+ }
+
+ bool f(int a, double b, char c)
+ {
+ return true;
+ }
+
+ int f(int a, int b, int c)
+ {
+ return a + b + c;
+ };
+ };
+
+Class X has 4 overloaded functions. We will start by introducing some
+member function pointer variables:
+
+ bool (X::*fx1)(int) = &X::f;
+ bool (X::*fx2)(int, double) = &X::f;
+ bool (X::*fx3)(int, double, char)= &X::f;
+ int (X::*fx4)(int, int, int) = &X::f;
+
+With these in hand, we can proceed to define and wrap this for Python:
+
+ .def("f", fx1)
+ .def("f", fx2)
+ .def("f", fx3)
+ .def("f", fx4)
+
+[endsect]
+[section Default Arguments]
+
+Boost.Python wraps (member) function pointers. Unfortunately, C++ function
+pointers carry no default argument info. Take a function [^f] with default
+arguments:
+
+ int f(int, double = 3.14, char const* = "hello");
+
+But the type of a pointer to the function [^f] has no information
+about its default arguments:
+
+ int(*g)(int,double,char const*) = f; // defaults lost!
+
+When we pass this function pointer to the [^def] function, there is no way
+to retrieve the default arguments:
+
+ def("f", f); // defaults lost!
+
+Because of this, when wrapping C++ code, we had to resort to manual
+wrapping as outlined in the [link python.overloading previous section], or
+writing thin wrappers:
+
+ // write "thin wrappers"
+ int f1(int x) { return f(x); }
+ int f2(int x, double y) { return f(x,y); }
+
+ /*...*/
+
+ // in module init
+ def("f", f); // all arguments
+ def("f", f2); // two arguments
+ def("f", f1); // one argument
+
+When you want to wrap functions (or member functions) that either:
+
+* have default arguments, or
+* are overloaded with a common sequence of initial arguments
+
+[h2 BOOST_PYTHON_FUNCTION_OVERLOADS]
+
+Boost.Python now has a way to make it easier. For instance, given a function:
+
+ int foo(int a, char b = 1, unsigned c = 2, double d = 3)
+ {
+ /*...*/
+ }
+
+The macro invocation:
+
+ BOOST_PYTHON_FUNCTION_OVERLOADS(foo_overloads, foo, 1, 4)
+
+will automatically create the thin wrappers for us. This macro will create
+a class [^foo_overloads] that can be passed on to [^def(...)]. The third
+and fourth macro argument are the minimum arguments and maximum arguments,
+respectively. In our [^foo] function the minimum number of arguments is 1
+and the maximum number of arguments is 4. The [^def(...)] function will
+automatically add all the foo variants for us:
+
+ def("foo", foo, foo_overloads());
+
+[h2 BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS]
+
+Objects here, objects there, objects here there everywhere. More frequently
+than anything else, we need to expose member functions of our classes to
+Python. Then again, we have the same inconveniences as before when default
+arguments or overloads with a common sequence of initial arguments come
+into play. Another macro is provided to make this a breeze.
+
+Like [^BOOST_PYTHON_FUNCTION_OVERLOADS],
+[^BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS] may be used to automatically create
+the thin wrappers for wrapping member functions. Let's have an example:
+
+ struct george
+ {
+ void
+ wack_em(int a, int b = 0, char c = 'x')
+ {
+ /*...*/
+ }
+ };
+
+The macro invocation:
+
+ BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS(george_overloads, wack_em, 1, 3)
+
+will generate a set of thin wrappers for george's [^wack_em] member function
+accepting a minimum of 1 and a maximum of 3 arguments (i.e. the third and
+fourth macro argument). The thin wrappers are all enclosed in a class named
+[^george_overloads] that can then be used as an argument to [^def(...)]:
+
+ .def("wack_em", &george::wack_em, george_overloads());
+
+See the [@../../../v2/overloads.html#BOOST_PYTHON_FUNCTION_OVERLOADS-spec overloads reference]
+for details.
+
+[h2 init and optional]
+
+A similar facility is provided for class constructors, again, with
+default arguments or a sequence of overloads. Remember [^init<...>]? For example,
+given a class X with a constructor:
+
+ struct X
+ {
+ X(int a, char b = 'D', std::string c = "constructor", double d = 0.0);
+ /*...*/
+ }
+
+You can easily add this constructor to Boost.Python in one shot:
+
+ .def(init<int, optional<char, std::string, double> >())
+
+Notice the use of [^init<...>] and [^optional<...>] to signify the default
+(optional arguments).
+
+[endsect]
+[section Auto-Overloading]
+
+It was mentioned in passing in the previous section that
+[^BOOST_PYTHON_FUNCTION_OVERLOADS] and [^BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS]
+can also be used for overloaded functions and member functions with a
+common sequence of initial arguments. Here is an example:
+
+ void foo()
+ {
+ /*...*/
+ }
+
+ void foo(bool a)
+ {
+ /*...*/
+ }
+
+ void foo(bool a, int b)
+ {
+ /*...*/
+ }
+
+ void foo(bool a, int b, char c)
+ {
+ /*...*/
+ }
+
+Like in the previous section, we can generate thin wrappers for these
+overloaded functions in one-shot:
+
+ BOOST_PYTHON_FUNCTION_OVERLOADS(foo_overloads, foo, 0, 3)
+
+Then...
+
+ .def("foo", (void(*)(bool, int, char))0, foo_overloads());
+
+Notice though that we have a situation now where we have a minimum of zero
+(0) arguments and a maximum of 3 arguments.
+
+[h2 Manual Wrapping]
+
+It is important to emphasize however that [*the overloaded functions must
+have a common sequence of initial arguments]. Otherwise, our scheme above
+will not work. If this is not the case, we have to wrap our functions
+[link python.overloading manually].
+
+Actually, we can mix and match manual wrapping of overloaded functions and
+automatic wrapping through [^BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS] and
+its sister, [^BOOST_PYTHON_FUNCTION_OVERLOADS]. Following up on our example
+presented in the section [link python.overloading on overloading], since the
+first 4 overload functins have a common sequence of initial arguments, we
+can use [^BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS] to automatically wrap the
+first three of the [^def]s and manually wrap just the last. Here's
+how we'll do this:
+
+ BOOST_PYTHON_MEMBER_FUNCTION_OVERLOADS(xf_overloads, f, 1, 4)
+
+Create a member function pointers as above for both X::f overloads:
+
+ bool (X::*fx1)(int, double, char) = &X::f;
+ int (X::*fx2)(int, int, int) = &X::f;
+
+Then...
+
+ .def("f", fx1, xf_overloads());
+ .def("f", fx2)
+
+[endsect]
+[endsect] [/ Functions ]
+
+[section:object Object Interface]
+
+Python is dynamically typed, unlike C++ which is statically typed. Python
+variables may hold an integer, a float, list, dict, tuple, str, long etc.,
+among other things. In the viewpoint of Boost.Python and C++, these
+Pythonic variables are just instances of class [^object]. We will see in
+this chapter how to deal with Python objects.
+
+As mentioned, one of the goals of Boost.Python is to provide a
+bidirectional mapping between C++ and Python while maintaining the Python
+feel. Boost.Python C++ [^object]s are as close as possible to Python. This
+should minimize the learning curve significantly.
+
+[$images/python.png]
+
+[section Basic Interface]
+
+Class [^object] wraps [^PyObject*]. All the intricacies of dealing with
+[^PyObject]s such as managing reference counting are handled by the
+[^object] class. C++ object interoperability is seamless. Boost.Python C++
+[^object]s can in fact be explicitly constructed from any C++ object.
+
+To illustrate, this Python code snippet:
+
+[python]
+
+ def f(x, y):
+ if (y == 'foo'):
+ x[3:7] = 'bar'
+ else:
+ x.items += y(3, x)
+ return x
+
+ def getfunc():
+ return f;
+
+Can be rewritten in C++ using Boost.Python facilities this way:
+
+[c++]
+
+ object f(object x, object y) {
+ if (y == "foo")
+ x.slice(3,7) = "bar";
+ else
+ x.attr("items") += y(3, x);
+ return x;
+ }
+ object getfunc() {
+ return object(f);
+ }
+
+Apart from cosmetic differences due to the fact that we are writing the
+code in C++, the look and feel should be immediately apparent to the Python
+coder.
+
+[endsect]
+[section Derived Object types]
+
+Boost.Python comes with a set of derived [^object] types corresponding to
+that of Python's:
+
+* list
+* dict
+* tuple
+* str
+* long_
+* enum
+
+These derived [^object] types act like real Python types. For instance:
+
+ str(1) ==> "1"
+
+Wherever appropriate, a particular derived [^object] has corresponding
+Python type's methods. For instance, [^dict] has a [^keys()] method:
+
+ d.keys()
+
+[^make_tuple] is provided for declaring ['tuple literals]. Example:
+
+ make_tuple(123, 'D', "Hello, World", 0.0);
+
+In C++, when Boost.Python [^object]s are used as arguments to functions,
+subtype matching is required. For example, when a function [^f], as
+declared below, is wrapped, it will only accept instances of Python's
+[^str] type and subtypes.
+
+ void f(str name)
+ {
+ object n2 = name.attr("upper")(); // NAME = name.upper()
+ str NAME = name.upper(); // better
+ object msg = "%s is bigger than %s" % make_tuple(NAME,name);
+ }
+
+In finer detail:
+
+ str NAME = name.upper();
+
+Illustrates that we provide versions of the str type's methods as C++
+member functions.
+
+ object msg = "%s is bigger than %s" % make_tuple(NAME,name);
+
+Demonstrates that you can write the C++ equivalent of [^"format" % x,y,z]
+in Python, which is useful since there's no easy way to do that in std C++.
+
+[blurb
+ __alert__ [*Beware] the common pitfall of forgetting that the constructors
+ of most of Python's mutable types make copies, just as in Python.
+]
+
+Python:
+[python]
+
+ >>> d = dict(x.__dict__) # copies x.__dict__
+ >>> d['whatever'] = 3 # modifies the copy
+
+C++:
+[c++]
+
+ dict d(x.attr("__dict__")); // copies x.__dict__
+ d['whatever'] = 3; // modifies the copy
+
+[h2 class_<T> as objects]
+
+Due to the dynamic nature of Boost.Python objects, any [^class_<T>] may
+also be one of these types! The following code snippet wraps the class
+(type) object.
+
+We can use this to create wrapped instances. Example:
+
+ object vec345 = (
+ class_<Vec2>("Vec2", init<double, double>())
+ .def_readonly("length", &Point::length)
+ .def_readonly("angle", &Point::angle)
+ )(3.0, 4.0);
+
+ assert(vec345.attr("length") == 5.0);
+
+[endsect]
+[section Extracting C++ objects]
+
+At some point, we will need to get C++ values out of object instances. This
+can be achieved with the [^extract<T>] function. Consider the following:
+
+ double x = o.attr("length"); // compile error
+
+In the code above, we got a compiler error because Boost.Python
+[^object] can't be implicitly converted to [^double]s. Instead, what
+we wanted to do above can be achieved by writing:
+
+ double l = extract<double>(o.attr("length"));
+ Vec2& v = extract<Vec2&>(o);
+ assert(l == v.length());
+
+The first line attempts to extract the "length" attribute of the Boost.Python
+[^object]. The second line attempts to ['extract] the [^Vec2] object from held
+by the Boost.Python [^object].
+
+Take note that we said "attempt to" above. What if the Boost.Python [^object]
+does not really hold a [^Vec2] type? This is certainly a possibility considering
+the dynamic nature of Python [^object]s. To be on the safe side, if the C++ type
+can't be extracted, an appropriate exception is thrown. To avoid an exception,
+we need to test for extractibility:
+
+ extract<Vec2&> x(o);
+ if (x.check()) {
+ Vec2& v = x(); ...
+
+__tip__ The astute reader might have noticed that the [^extract<T>]
+facility in fact solves the mutable copying problem:
+
+ dict d = extract<dict>(x.attr("__dict__"));
+ d["whatever"] = 3; // modifies x.__dict__ !
+
+
+[endsect]
+[section Enums]
+
+Boost.Python has a nifty facility to capture and wrap C++ enums. While
+Python has no [^enum] type, we'll often want to expose our C++ enums to
+Python as an [^int]. Boost.Python's enum facility makes this easy while
+taking care of the proper conversions from Python's dynamic typing to C++'s
+strong static typing (in C++, ints cannot be implicitly converted to
+enums). To illustrate, given a C++ enum:
+
+ enum choice { red, blue };
+
+the construct:
+
+ enum_<choice>("choice")
+ .value("red", red)
+ .value("blue", blue)
+ ;
+
+can be used to expose to Python. The new enum type is created in the
+current [^scope()], which is usually the current module. The snippet above
+creates a Python class derived from Python's [^int] type which is
+associated with the C++ type passed as its first parameter.
+
+[note [*what is a scope?]
+
+The scope is a class that has an associated global Python object which
+controls the Python namespace in which new extension classes and wrapped
+functions will be defined as attributes. Details can be found
+[@../../../v2/scope.html here].]
+
+You can access those values in Python as
+
+[python]
+
+ >>> my_module.choice.red
+ my_module.choice.red
+
+where my_module is the module where the enum is declared. You can also
+create a new scope around a class:
+
+[c++]
+
+ scope in_X = class_<X>("X")
+ .def( ... )
+ .def( ... )
+ ;
+
+ // Expose X::nested as X.nested
+ enum_<X::nested>("nested")
+ .value("red", red)
+ .value("blue", blue)
+ ;
+
+[def Py_Initialize [@http://www.python.org/doc/current/api/initialization.html#l2h-652 Py_Initialize]]
+[def Py_Finalize [@http://www.python.org/doc/current/api/initialization.html#l2h-656 Py_Finalize]]
+[def Py_XINCREF [@http://www.python.org/doc/current/api/countingRefs.html#l2h-65 Py_XINCREF]]
+[def Py_XDECREF [@http://www.python.org/doc/current/api/countingRefs.html#l2h-67 Py_XDECREF]]
+[def PyImport_AppendInittab [@http://www.python.org/doc/current/api/importing.html#l2h-137 PyImport_AppendInittab]]
+[def PyImport_AddModule [@http://www.python.org/doc/current/api/importing.html#l2h-125 PyImport_AddModule]]
+[def PyModule_New [@http://www.python.org/doc/current/api/moduleObjects.html#l2h-591 PyModule_New]]
+[def PyModule_GetDict [@http://www.python.org/doc/current/api/moduleObjects.html#l2h-594 PyModule_GetDict]]
+
+[endsect]
+
+[section:creating_python_object Creating `boost::python::object` from `PyObject*`]
+
+When you want a `boost::python::object` to manage a pointer to `PyObject*` pyobj one does:
+
+ boost::python::object o(boost::python::handle<>(pyobj));
+
+In this case, the `o` object, manages the `pyobj`, it won’t increase the reference count on construction.
+
+Otherwise, to use a borrowed reference:
+
+ boost::python::object o(boost::python::handle<>(boost::python::borrowed(pyobj)));
+
+In this case, `Py_INCREF` is called, so `pyobj` is not destructed when object o goes out of scope.
+
+[endsect] [/ creating_python_object ]
+
+[endsect] [/ Object Interface]
+
+[section Embedding]
+
+By now you should know how to use Boost.Python to call your C++ code from
+Python. However, sometimes you may need to do the reverse: call Python code
+from the C++-side. This requires you to ['embed] the Python interpreter
+into your C++ program.
+
+Currently, Boost.Python does not directly support everything you'll need
+when embedding. Therefore you'll need to use the
+[@http://www.python.org/doc/current/api/api.html Python/C API] to fill in
+the gaps. However, Boost.Python already makes embedding a lot easier and,
+in a future version, it may become unnecessary to touch the Python/C API at
+all. So stay tuned... :-)
+
+[h2 Building embedded programs]
+
+To be able to embed python into your programs, you have to link to
+both Boost.Python's as well as Python's own runtime library.
+
+Boost.Python's library comes in two variants. Both are located
+in Boost's [^/libs/python/build/bin-stage] subdirectory. On Windows, the
+variants are called [^boost_python.lib] (for release builds) and
+[^boost_python_debug.lib] (for debugging). If you can't find the libraries,
+you probably haven't built Boost.Python yet. See
+[@../../../building.html Building and Testing] on how to do this.
+
+Python's library can be found in the [^/libs] subdirectory of
+your Python directory. On Windows it is called pythonXY.lib where X.Y is
+your major Python version number.
+
+Additionally, Python's [^/include] subdirectory has to be added to your
+include path.
+
+In a Jamfile, all the above boils down to:
+
+[pre
+projectroot c:\projects\embedded_program ; # location of the program
+
+# bring in the rules for python
+SEARCH on python.jam = $(BOOST_BUILD_PATH) ;
+include python.jam ;
+
+exe embedded_program # name of the executable
+ : #sources
+ embedded_program.cpp
+ : # requirements
+ <find-library>boost_python <library-path>c:\boost\libs\python
+ $(PYTHON_PROPERTIES)
+ <library-path>$(PYTHON_LIB_PATH)
+ <find-library>$(PYTHON_EMBEDDED_LIBRARY) ;
+]
+
+[h2 Getting started]
+
+Being able to build is nice, but there is nothing to build yet. Embedding
+the Python interpreter into one of your C++ programs requires these 4
+steps:
+
+# '''#include''' [^<boost/python.hpp>]
+
+# Call Py_Initialize() to start the interpreter and create the [^__main__] module.
+
+# Call other Python C API routines to use the interpreter.
+
+[/ # Call Py_Finalize() to stop the interpreter and release its resources.]
+
+[note [*Note that at this time you must not call Py_Finalize() to stop the
+interpreter. This may be fixed in a future version of boost.python.]
+]
+
+(Of course, there can be other C++ code between all of these steps.)
+
+[:['[*Now that we can embed the interpreter in our programs, lets see how to put it to use...]]]
+
+[section Using the interpreter]
+
+As you probably already know, objects in Python are reference-counted.
+Naturally, the [^PyObject]s of the Python C API are also reference-counted.
+There is a difference however. While the reference-counting is fully
+automatic in Python, the Python C API requires you to do it
+[@http://www.python.org/doc/current/c-api/refcounting.html by hand]. This is
+messy and especially hard to get right in the presence of C++ exceptions.
+Fortunately Boost.Python provides the [@../../../v2/handle.html handle] and
+[@../../../v2/object.html object] class templates to automate the process.
+
+[h2 Running Python code]
+
+Boost.python provides three related functions to run Python code from C++.
+
+ object eval(str expression, object globals = object(), object locals = object())
+ object exec(str code, object globals = object(), object locals = object())
+ object exec_file(str filename, object globals = object(), object locals = object())
+
+eval evaluates the given expression and returns the resulting value.
+exec executes the given code (typically a set of statements) returning the result,
+and exec_file executes the code contained in the given file.
+
+The [^globals] and [^locals] parameters are Python dictionaries
+containing the globals and locals of the context in which to run the code.
+For most intents and purposes you can use the namespace dictionary of the
+[^__main__] module for both parameters.
+
+Boost.python provides a function to import a module:
+
+ object import(str name)
+
+import imports a python module (potentially loading it into the running process
+first), and returns it.
+
+Let's import the [^__main__] module and run some Python code in its namespace:
+
+ object main_module = import("__main__");
+ object main_namespace = main_module.attr("__dict__");
+
+ object ignored = exec("hello = file('hello.txt', 'w')\n"
+ "hello.write('Hello world!')\n"
+ "hello.close()",
+ main_namespace);
+
+This should create a file called 'hello.txt' in the current directory
+containing a phrase that is well-known in programming circles.
+
+[h2 Manipulating Python objects]
+
+Often we'd like to have a class to manipulate Python objects.
+But we have already seen such a class above, and in the
+[@python/object.html previous section]: the aptly named [^object] class
+and its derivatives. We've already seen that they can be constructed from
+a [^handle]. The following examples should further illustrate this fact:
+
+ object main_module = import("__main__");
+ object main_namespace = main_module.attr("__dict__");
+ object ignored = exec("result = 5 ** 2", main_namespace);
+ int five_squared = extract<int>(main_namespace["result"]);
+
+Here we create a dictionary object for the [^__main__] module's namespace.
+Then we assign 5 squared to the result variable and read this variable from
+the dictionary. Another way to achieve the same result is to use eval instead,
+which returns the result directly:
+
+ object result = eval("5 ** 2");
+ int five_squared = extract<int>(result);
+
+[h2 Exception handling]
+
+If an exception occurs in the evaluation of the python expression,
+[@../../../v2/errors.html#error_already_set-spec error_already_set] is thrown:
+
+ try
+ {
+ object result = eval("5/0");
+ // execution will never get here:
+ int five_divided_by_zero = extract<int>(result);
+ }
+ catch(error_already_set const &)
+ {
+ // handle the exception in some way
+ }
+
+The [^error_already_set] exception class doesn't carry any information in itself.
+To find out more about the Python exception that occurred, you need to use the
+[@http://www.python.org/doc/api/exceptionHandling.html exception handling functions]
+of the Python C API in your catch-statement. This can be as simple as calling
+[@http://www.python.org/doc/api/exceptionHandling.html#l2h-70 PyErr_Print()] to
+print the exception's traceback to the console, or comparing the type of the
+exception with those of the [@http://www.python.org/doc/api/standardExceptions.html
+standard exceptions]:
+
+ catch(error_already_set const &)
+ {
+ if (PyErr_ExceptionMatches(PyExc_ZeroDivisionError))
+ {
+ // handle ZeroDivisionError specially
+ }
+ else
+ {
+ // print all other errors to stderr
+ PyErr_Print();
+ }
+ }
+
+(To retrieve even more information from the exception you can use some of the other
+exception handling functions listed [@http://www.python.org/doc/api/exceptionHandling.html here].)
+
+[endsect]
+[endsect] [/ Embedding]
+
+[section Iterators]
+
+In C++, and STL in particular, we see iterators everywhere. Python also has
+iterators, but these are two very different beasts.
+
+[*C++ iterators:]
+
+* C++ has 5 type categories (random-access, bidirectional, forward, input, output)
+* There are 2 Operation categories: reposition, access
+* A pair of iterators is needed to represent a (first/last) range.
+
+[*Python Iterators:]
+
+* 1 category (forward)
+* 1 operation category (next())
+* Raises StopIteration exception at end
+
+The typical Python iteration protocol: [^[*for y in x...]] is as follows:
+
+[python]
+
+ iter = x.__iter__() # get iterator
+ try:
+ while 1:
+ y = iter.next() # get each item
+ ... # process y
+ except StopIteration: pass # iterator exhausted
+
+Boost.Python provides some mechanisms to make C++ iterators play along
+nicely as Python iterators. What we need to do is to produce
+appropriate `__iter__` function from C++ iterators that is compatible
+with the Python iteration protocol. For example:
+
+[c++]
+
+ object get_iterator = iterator<vector<int> >();
+ object iter = get_iterator(v);
+ object first = iter.next();
+
+Or for use in class_<>:
+
+ .def("__iter__", iterator<vector<int> >())
+
+[*range]
+
+We can create a Python savvy iterator using the range function:
+
+* range(start, finish)
+* range<Policies,Target>(start, finish)
+
+Here, start/finish may be one of:
+
+* member data pointers
+* member function pointers
+* adaptable function object (use Target parameter)
+
+[*iterator]
+
+* iterator<T, Policies>()
+
+Given a container [^T], iterator is a shortcut that simply calls [^range]
+with &T::begin, &T::end.
+
+Let's put this into action... Here's an example from some hypothetical
+bogon Particle accelerator code:
+
+[python]
+
+ f = Field()
+ for x in f.pions:
+ smash(x)
+ for y in f.bogons:
+ count(y)
+
+Now, our C++ Wrapper:
+
+[c++]
+
+ class_<F>("Field")
+ .property("pions", range(&F::p_begin, &F::p_end))
+ .property("bogons", range(&F::b_begin, &F::b_end));
+
+[*stl_input_iterator]
+
+So far, we have seen how to expose C++ iterators and ranges to Python.
+Sometimes we wish to go the other way, though: we'd like to pass a
+Python sequence to an STL algorithm or use it to initialize an STL
+container. We need to make a Python iterator look like an STL iterator.
+For that, we use `stl_input_iterator<>`. Consider how we might
+implement a function that exposes `std::list<int>::assign()` to
+Python:
+
+[c++]
+
+ template<typename T>
+ void list_assign(std::list<T>& l, object o) {
+ // Turn a Python sequence into an STL input range
+ stl_input_iterator<T> begin(o), end;
+ l.assign(begin, end);
+ }
+
+ // Part of the wrapper for list<int>
+ class_<std::list<int> >("list_int")
+ .def("assign", &list_assign<int>)
+ // ...
+ ;
+
+Now in Python, we can assign any integer sequence to `list_int` objects:
+
+[python]
+
+ x = list_int();
+ x.assign([1,2,3,4,5])
+
+[endsect]
+[section:exception Exception Translation]
+
+All C++ exceptions must be caught at the boundary with Python code. This
+boundary is the point where C++ meets Python. Boost.Python provides a
+default exception handler that translates selected standard exceptions,
+then gives up:
+
+ raise RuntimeError, 'unidentifiable C++ Exception'
+
+Users may provide custom translation. Here's an example:
+
+ struct PodBayDoorException;
+ void translator(PodBayDoorException const& x) {
+ PyErr_SetString(PyExc_UserWarning, "I'm sorry Dave...");
+ }
+ BOOST_PYTHON_MODULE(kubrick) {
+ register_exception_translator<
+ PodBayDoorException>(translator);
+ ...
+
+[endsect]
+[section:techniques General Techniques]
+
+Here are presented some useful techniques that you can use while wrapping code with Boost.Python.
+
+[section Creating Packages]
+
+A Python package is a collection of modules that provide to the user a certain
+functionality. If you're not familiar on how to create packages, a good
+introduction to them is provided in the
+[@http://www.python.org/doc/current/tut/node8.html Python Tutorial].
+
+But we are wrapping C++ code, using Boost.Python. How can we provide a nice
+package interface to our users? To better explain some concepts, let's work
+with an example.
+
+We have a C++ library that works with sounds: reading and writing various
+formats, applying filters to the sound data, etc. It is named (conveniently)
+[^sounds]. Our library already has a neat C++ namespace hierarchy, like so:
+
+ sounds::core
+ sounds::io
+ sounds::filters
+
+We would like to present this same hierarchy to the Python user, allowing him
+to write code like this:
+
+ import sounds.filters
+ sounds.filters.echo(...) # echo is a C++ function
+
+The first step is to write the wrapping code. We have to export each module
+separately with Boost.Python, like this:
+
+ /* file core.cpp */
+ BOOST_PYTHON_MODULE(core)
+ {
+ /* export everything in the sounds::core namespace */
+ ...
+ }
+
+ /* file io.cpp */
+ BOOST_PYTHON_MODULE(io)
+ {
+ /* export everything in the sounds::io namespace */
+ ...
+ }
+
+ /* file filters.cpp */
+ BOOST_PYTHON_MODULE(filters)
+ {
+ /* export everything in the sounds::filters namespace */
+ ...
+ }
+
+Compiling these files will generate the following Python extensions:
+[^core.pyd], [^io.pyd] and [^filters.pyd].
+
+[note The extension [^.pyd] is used for python extension modules, which
+are just shared libraries. Using the default for your system, like [^.so] for
+Unix and [^.dll] for Windows, works just as well.]
+
+Now, we create this directory structure for our Python package:
+
+[pre
+sounds/
+ \_\_init\_\_.py
+ core.pyd
+ filters.pyd
+ io.pyd
+]
+
+The file [^\_\_init\_\_.py] is what tells Python that the directory [^sounds/] is
+actually a Python package. It can be a empty file, but can also perform some
+magic, that will be shown later.
+
+Now our package is ready. All the user has to do is put [^sounds] into his
+[@http://www.python.org/doc/current/tut/node8.html#SECTION008110000000000000000 PYTHONPATH]
+and fire up the interpreter:
+
+[python]
+
+ >>> import sounds.io
+ >>> import sounds.filters
+ >>> sound = sounds.io.open('file.mp3')
+ >>> new_sound = sounds.filters.echo(sound, 1.0)
+
+Nice heh?
+
+This is the simplest way to create hierarchies of packages, but it is not very
+flexible. What if we want to add a ['pure] Python function to the filters
+package, for instance, one that applies 3 filters in a sound object at once?
+Sure, you can do this in C++ and export it, but why not do so in Python? You
+don't have to recompile the extension modules, plus it will be easier to write
+it.
+
+If we want this flexibility, we will have to complicate our package hierarchy a
+little. First, we will have to change the name of the extension modules:
+
+[c++]
+
+ /* file core.cpp */
+ BOOST_PYTHON_MODULE(_core)
+ {
+ ...
+ /* export everything in the sounds::core namespace */
+ }
+
+Note that we added an underscore to the module name. The filename will have to
+be changed to [^_core.pyd] as well, and we do the same to the other extension modules.
+Now, we change our package hierarchy like so:
+
+[pre
+sounds/
+ \_\_init\_\_.py
+ core/
+ \_\_init\_\_.py
+ _core.pyd
+ filters/
+ \_\_init\_\_.py
+ _filters.pyd
+ io/
+ \_\_init\_\_.py
+ _io.pyd
+]
+
+Note that we created a directory for each extension module, and added a
+\_\_init\_\_.py to each one. But if we leave it that way, the user will have to
+access the functions in the core module with this syntax:
+
+[python]
+
+ >>> import sounds.core._core
+ >>> sounds.core._core.foo(...)
+
+which is not what we want. But here enters the [^\_\_init\_\_.py] magic: everything
+that is brought to the [^\_\_init\_\_.py] namespace can be accessed directly by the
+user. So, all we have to do is bring the entire namespace from [^_core.pyd]
+to [^core/\_\_init\_\_.py]. So add this line of code to [^sounds/core/\_\_init\_\_.py]:
+
+ from _core import *
+
+We do the same for the other packages. Now the user accesses the functions and
+classes in the extension modules like before:
+
+ >>> import sounds.filters
+ >>> sounds.filters.echo(...)
+
+with the additional benefit that we can easily add pure Python functions to
+any module, in a way that the user can't tell the difference between a C++
+function and a Python function. Let's add a ['pure] Python function,
+[^echo_noise], to the [^filters] package. This function applies both the
+[^echo] and [^noise] filters in sequence in the given [^sound] object. We
+create a file named [^sounds/filters/echo_noise.py] and code our function:
+
+ import _filters
+ def echo_noise(sound):
+ s = _filters.echo(sound)
+ s = _filters.noise(sound)
+ return s
+
+Next, we add this line to [^sounds/filters/\_\_init\_\_.py]:
+
+ from echo_noise import echo_noise
+
+And that's it. The user now accesses this function like any other function
+from the [^filters] package:
+
+ >>> import sounds.filters
+ >>> sounds.filters.echo_noise(...)
+
+[endsect]
+[section Extending Wrapped Objects in Python]
+
+Thanks to Python's flexibility, you can easily add new methods to a class,
+even after it was already created:
+
+ >>> class C(object): pass
+ >>>
+ >>> # a regular function
+ >>> def C_str(self): return 'A C instance!'
+ >>>
+ >>> # now we turn it in a member function
+ >>> C.__str__ = C_str
+ >>>
+ >>> c = C()
+ >>> print c
+ A C instance!
+ >>> C_str(c)
+ A C instance!
+
+Yes, Python rox. :-)
+
+We can do the same with classes that were wrapped with Boost.Python. Suppose
+we have a class [^point] in C++:
+
+[c++]
+
+ class point {...};
+
+ BOOST_PYTHON_MODULE(_geom)
+ {
+ class_<point>("point")...;
+ }
+
+If we are using the technique from the previous session,
+[link python.creating_packages Creating Packages], we can code directly
+into [^geom/\_\_init\_\_.py]:
+
+[python]
+
+ from _geom import *
+
+ # a regular function
+ def point_str(self):
+ return str((self.x, self.y))
+
+ # now we turn it into a member function
+ point.__str__ = point_str
+
+[*All] point instances created from C++ will also have this member function!
+This technique has several advantages:
+
+* Cut down compile times to zero for these additional functions
+* Reduce the memory footprint to virtually zero
+* Minimize the need to recompile
+* Rapid prototyping (you can move the code to C++ if required without changing the interface)
+
+You can even add a little syntactic sugar with the use of metaclasses. Let's
+create a special metaclass that "injects" methods in other classes.
+
+ # The one Boost.Python uses for all wrapped classes.
+ # You can use here any class exported by Boost instead of "point"
+ BoostPythonMetaclass = point.__class__
+
+ class injector(object):
+ class __metaclass__(BoostPythonMetaclass):
+ def __init__(self, name, bases, dict):
+ for b in bases:
+ if type(b) not in (self, type):
+ for k,v in dict.items():
+ setattr(b,k,v)
+ return type.__init__(self, name, bases, dict)
+
+ # inject some methods in the point foo
+ class more_point(injector, point):
+ def __repr__(self):
+ return 'Point(x=%s, y=%s)' % (self.x, self.y)
+ def foo(self):
+ print 'foo!'
+
+Now let's see how it got:
+
+ >>> print point()
+ Point(x=10, y=10)
+ >>> point().foo()
+ foo!
+
+Another useful idea is to replace constructors with factory functions:
+
+ _point = point
+
+ def point(x=0, y=0):
+ return _point(x, y)
+
+In this simple case there is not much gained, but for constructurs with
+many overloads and/or arguments this is often a great simplification, again
+with virtually zero memory footprint and zero compile-time overhead for
+the keyword support.
+
+[endsect]
+[section Reducing Compiling Time]
+
+If you have ever exported a lot of classes, you know that it takes quite a good
+time to compile the Boost.Python wrappers. Plus the memory consumption can
+easily become too high. If this is causing you problems, you can split the
+class_ definitions in multiple files:
+
+[c++]
+
+ /* file point.cpp */
+ #include <point.h>
+ #include <boost/python.hpp>
+
+ void export_point()
+ {
+ class_<point>("point")...;
+ }
+
+ /* file triangle.cpp */
+ #include <triangle.h>
+ #include <boost/python.hpp>
+
+ void export_triangle()
+ {
+ class_<triangle>("triangle")...;
+ }
+
+Now you create a file [^main.cpp], which contains the [^BOOST_PYTHON_MODULE]
+macro, and call the various export functions inside it.
+
+ void export_point();
+ void export_triangle();
+
+ BOOST_PYTHON_MODULE(_geom)
+ {
+ export_point();
+ export_triangle();
+ }
+
+Compiling and linking together all this files produces the same result as the
+usual approach:
+
+ #include <boost/python.hpp>
+ #include <point.h>
+ #include <triangle.h>
+
+ BOOST_PYTHON_MODULE(_geom)
+ {
+ class_<point>("point")...;
+ class_<triangle>("triangle")...;
+ }
+
+but the memory is kept under control.
+
+This method is recommended too if you are developing the C++ library and
+exporting it to Python at the same time: changes in a class will only demand
+the compilation of a single cpp, instead of the entire wrapper code.
+
+[note If you're exporting your classes with [@../../../../pyste/index.html Pyste],
+take a look at the [^--multiple] option, that generates the wrappers in
+various files as demonstrated here.]
+
+[note This method is useful too if you are getting the error message
+['"fatal error C1204:Compiler limit:internal structure overflow"] when compiling
+a large source file, as explained in the [@../../../v2/faq.html#c1204 FAQ].]
+
+[endsect]
+[endsect] [/ General Techniques]
+
+