from test_support import verbose, verify import sys import new class Eggs: def get_yolks(self): return self.yolks print 'new.module()' m = new.module('Spam') if verbose: print m m.Eggs = Eggs sys.modules['Spam'] = m import Spam def get_more_yolks(self): return self.yolks + 3 print 'new.classobj()' C = new.classobj('Spam', (Spam.Eggs,), {'get_more_yolks': get_more_yolks}) if verbose: print C print 'new.instance()' c = new.instance(C, {'yolks': 3}) if verbose: print c o = new.instance(C) verify(o.__dict__ == {}, "new __dict__ should be empty") del o o = new.instance(C, None) verify(o.__dict__ == {}, "new __dict__ should be empty") del o def break_yolks(self): self.yolks = self.yolks - 2 print 'new.instancemethod()' im = new.instancemethod(break_yolks, c, C) if verbose: print im verify(c.get_yolks() == 3 and c.get_more_yolks() == 6, 'Broken call of hand-crafted class instance') im() verify(c.get_yolks() == 1 and c.get_more_yolks() == 4, 'Broken call of hand-crafted instance method') # It's unclear what the semantics should be for a code object compiled at # module scope, but bound and run in a function. In CPython, `c' is global # (by accident?) while in Jython, `c' is local. The intent of the test # clearly is to make `c' global, so let's be explicit about it. codestr = ''' global c a = 1 b = 2 c = a + b ''' ccode = compile(codestr, '', 'exec') # Jython doesn't have a __builtins__, so use a portable alternative import __builtin__ g = {'c': 0, '__builtins__': __builtin__} # this test could be more robust print 'new.function()' func = new.function(ccode, g) if verbose: print func func() verify(g['c'] == 3, 'Could not create a proper function object') print 'new.code()' # bogus test of new.code() # Note: Jython will never have new.code() if hasattr(new, 'code'): d = new.code(3, 3, 3, 3, codestr, (), (), (), "", "", 1, "", (), ()) # test backwards-compatibility version with no freevars or cellvars d = new.code(3, 3, 3, 3, codestr, (), (), (), "", "", 1, "") if verbose: print d