#include "quadmath.h" #include #include #define ABS(x) ((x) >= 0 ? (x) : -(x)) static void format (char * res, const __float128 x, size_t n) { char buffer[1024]; char *p; memset (buffer, 0, sizeof(buffer)); g_Qfmt (buffer, &x, n + 1, sizeof(buffer) - 3); p = buffer + (*buffer == '-' ? 1 : 0); // The sign is the easiest part res[0] = (signbitq (x) ? '-' : '+'); if (*p == '.') { // We have a number smaller than 1, without exponent int exp = 0; char *c; for (c = p+1; *c == '0'; c++) exp++; // We move the string "exp" characters left size_t l = strlen (p+1+exp); memcpy (res + 2, p + 1 + exp, l); memset (res + 2 + l, '0', n - l + 1); sprintf (res + n + 3, "e-%02d", exp + 1); res[1] = res[2]; res[2] = '.'; return; } // Now, do we already have an exponent char *c; for (c = p; *c && *c != 'e'; c++) ; if (*c) { int exp = strtol (c + 1, NULL, 10); size_t l = c - p; memcpy (res + 1, p, l); if (l <= n + 1) memset (res + 1 + l, '0', (int) n - l + 2); sprintf (res + n + 3, "e%c%02d", exp >= 0 ? '+' : '-', ABS(exp)); return; } else { // If we have no exponent, normalize and add the exponent for (c = p; *c && *c != '.'; c++) ; res[1] = *p; res[2] = '.'; size_t l = c - p; memcpy (res + 3, p + 1, l); size_t l2 = strlen (c + 1); memcpy (res + 2 + l, c + 1, l2); memset (res + 2 + l + l2, '0', n - (l + l2) + 1); sprintf (res + n + 3, "e+%02d", l - 1); return; } } void quadmath_dtoaq (char *s, size_t size, size_t n, __float128 x) { char buffer[1024]; memset (buffer, 0, sizeof(buffer)); format (buffer, x, n); memcpy (s, buffer, size); }