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authorElena Zannoni <ezannoni@kwikemart.cygnus.com>2003-10-10 19:20:31 +0000
committerElena Zannoni <ezannoni@kwikemart.cygnus.com>2003-10-10 19:20:31 +0000
commit9de88c80c0a379fc3960fd46d7e2e8d0d9238d19 (patch)
treefdd49c41b4180044619dcc7b5ab633ebc5171abe /gdb/sh-tdep.c
parent441a042489c326c4f37b989a133ceec3202b1d74 (diff)
downloadgdb-9de88c80c0a379fc3960fd46d7e2e8d0d9238d19.tar.gz
2003-10-10 Elena Zannoni <ezannoni@redhat.com>
* sh-tdep.c (sh_use_struct_convention): Clarify one case in comment.
Diffstat (limited to 'gdb/sh-tdep.c')
-rw-r--r--gdb/sh-tdep.c12
1 files changed, 11 insertions, 1 deletions
diff --git a/gdb/sh-tdep.c b/gdb/sh-tdep.c
index eee7698b842..3d8c62943fe 100644
--- a/gdb/sh-tdep.c
+++ b/gdb/sh-tdep.c
@@ -568,7 +568,7 @@ sh_skip_prologue (CORE_ADDR start_pc)
All other aggregate types are returned by address. The caller
function passes the address of an area large enough to hold the
aggregate value in R2. The called function stores the result in
- this location."
+ this location.
To reiterate, structs smaller than 8 bytes could also be returned
in memory, if they don't pass the "same size and alignment as an
@@ -582,6 +582,16 @@ sh_skip_prologue (CORE_ADDR start_pc)
the return value from foo() will be in memory, not
in R0, because there is no 3-byte integer type.
+ Similarly, in
+
+ struct s { char c[2]; } wibble;
+ struct s foo(void) { return wibble; }
+
+ because a struct containing two chars has alignment 1, that matches
+ type char, but size 2, that matches type short. There's no integer
+ type that has alignment 1 and size 2, so the struct is returned in
+ memory.
+
*/
static int