fsck_commit_buffer(): do not special case the last validation

The pattern taken by all the validations in this function is:

	if (notice a violation exists) {
		err = report(... VIOLATION_KIND ...);
		if (err)
			return err;
	}

where report() returns zero if specified kind of violation is set to
be ignored, and otherwise shows an error message and returns non-zero.

The last validation in the function immediately before the function
returns 0 to declare "all good" can cheat and directly return the
return value from report(), and the current code does so, i.e.

	if (notice a violation exists)
		return report(... VIOLATION_KIND ...);
	return 0;

But that is a selfish code that declares it is the ultimate and
final form of the function, never to be enhanced later.  To allow
and invite future enhancements, make the last test follow the same
pattern.

Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 5 insertions, 3 deletions

diff --git a/fsck.c b/fsck.c
index ca4c685377..21dfa5f98c 100644
--- a/fsck.c
+++ b/fsck.c
@@ -666,9 +666,11 @@ static int fsck_commit_buffer(struct commit *commit, const char *buffer,
 	err = fsck_ident(&buffer, &commit->object, options);
 	if (err)
 		return err;
-	if (!commit->tree)
-		return report(options, &commit->object, FSCK_MSG_BAD_TREE, "could not load commit's tree %s", sha1_to_hex(tree_sha1));
-
+	if (!commit->tree) {
+		err = report(options, &commit->object, FSCK_MSG_BAD_TREE, "could not load commit's tree %s", sha1_to_hex(tree_sha1));
+		if (err)
+			return err;
+	}
 	return 0;
 }