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authorTim Henigan <tim.henigan@gmail.com>2012-02-24 18:12:58 -0500
committerJunio C Hamano <gitster@pobox.com>2012-02-27 15:10:23 -0800
commit860f70f9f4206379361fd5af84c8fde31984b418 (patch)
tree74806c7f14b85fa2e1075722b49e3c7e75377a1e /Documentation/CodingGuidelines
parent48f359bfafa7db4c399fa13f17ccfea7c35f333b (diff)
downloadgit-860f70f9f4206379361fd5af84c8fde31984b418.tar.gz
CodingGuidelines: do not use 'which' in shell scripts
During the code review of a recent patch, it was noted that shell scripts must not use 'which $cmd' to check the availability of the command $cmd. The output of the command is not machine parseable and its exit code is not reliable across platforms. It is better to use 'type' to accomplish this task. Signed-off-by: Tim Henigan <tim.henigan@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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diff --git a/Documentation/CodingGuidelines b/Documentation/CodingGuidelines
index cfe3785909..45577117c2 100644
--- a/Documentation/CodingGuidelines
+++ b/Documentation/CodingGuidelines
@@ -46,6 +46,11 @@ For shell scripts specifically (not exhaustive):
properly nests. It should have been the way Bourne spelled
it from day one, but unfortunately isn't.
+ - If you want to find out if a command is available on the user's
+ $PATH, you should use 'type <command>', instead of 'which <command>'.
+ The output of 'which' is not machine parseable and its exit code
+ is not reliable across platforms.
+
- We use POSIX compliant parameter substitutions and avoid bashisms;
namely: