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T2693.hs:11:7:
Couldn't match expected type ‛TFn a’ with actual type ‛TFn a0’
NB: ‛TFn’ is a type function, and may not be injective
The type variable ‛a0’ is ambiguous
When checking that ‛x’ has the inferred type ‛forall a. TFn a’
Probable cause: the inferred type is ambiguous
In the expression:
do { let Just x = ...;
let n = fst x + fst x;
return () }
In an equation for ‛f’:
f = do { let Just x = ...;
let n = ...;
return () }
T2693.hs:19:15:
Couldn't match expected type ‛(a2, b0)’ with actual type ‛TFn a3’
The type variables ‛a2’, ‛b0’, ‛a3’ are ambiguous
Relevant bindings include n :: a2 (bound at T2693.hs:19:7)
In the first argument of ‛fst’, namely ‛x’
In the first argument of ‛(+)’, namely ‛fst x’
T2693.hs:19:23:
Couldn't match expected type ‛(a4, a2)’ with actual type ‛TFn a5’
The type variables ‛a2’, ‛a4’, ‛a5’ are ambiguous
Relevant bindings include n :: a2 (bound at T2693.hs:19:7)
In the first argument of ‛snd’, namely ‛x’
In the second argument of ‛(+)’, namely ‛snd x’
T2693.hs:29:20:
Couldn't match type ‛TFn a0’ with ‛PVR a1’
The type variables ‛a0’, ‛a1’ are ambiguous
Expected type: () -> Maybe (PVR a1)
Actual type: () -> Maybe (TFn a0)
In the first argument of ‛mapM’, namely ‛g’
In a stmt of a 'do' block: pvs <- mapM g undefined
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