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T2693.hs:11:7:
Couldn't match expected type `TFn a' with actual type `TFn a0'
NB: `TFn' is a type function, and may not be injective
The type variable `a0' is ambiguous
When checking that `x' has the inferred type `forall a. TFn a'
Probable cause: the inferred type is ambiguous
In the expression:
do { let Just x = ...;
let n = fst x + fst x;
return () }
In an equation for `f':
f = do { let Just x = ...;
let n = ...;
return () }
T2693.hs:19:15:
Couldn't match expected type `(a2, b0)' with actual type `TFn a3'
The type variables `a2', `b0', `a3' are ambiguous
Relevant bindings include n :: a2 (bound at T2693.hs:19:7)
In the first argument of `fst', namely `x'
In the first argument of `(+)', namely `fst x'
In the expression: fst x + snd x
T2693.hs:19:23:
Couldn't match expected type `(a4, a2)' with actual type `TFn a5'
The type variables `a2', `a4', `a5' are ambiguous
Relevant bindings include n :: a2 (bound at T2693.hs:19:7)
In the first argument of `snd', namely `x'
In the second argument of `(+)', namely `snd x'
In the expression: fst x + snd x
T2693.hs:29:20:
Couldn't match type `TFn a0' with `PVR a1'
The type variables `a0', `a1' are ambiguous
Expected type: () -> Maybe (PVR a1)
Actual type: () -> Maybe (TFn a0)
In the first argument of `mapM', namely `g'
In a stmt of a 'do' block: pvs <- mapM g undefined
In the expression:
do { pvs <- mapM g undefined;
let n = (map pvrX pvs) `min` (map pvrX pvs);
undefined }
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