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T4179.hs:26:16:
Could not deduce (A3 (x (A2 (x (Con x)) -> A3 (x (Con x))))
~ A3 (x (Con x)))
from the context (Functor x, DoC (FCon x))
bound by the type signature for
fCon :: (Functor x, DoC (FCon x)) =>
Con x -> A2 (FCon x) -> A3 (FCon x)
at T4179.hs:26:1-17
NB: `A3' is a type function, and may not be injective
Expected type: x (A2 (x (Con x)) -> A3 (x (Con x)))
-> A2 (x (Con x)) -> A3 (x (Con x))
Actual type: x (A2 (x (Con x)) -> A3 (x (Con x)))
-> A2 (x (A2 (x (Con x)) -> A3 (x (Con x))))
-> A3 (x (A2 (x (Con x)) -> A3 (x (Con x))))
In the first argument of `foldDoC', namely `op'
In the expression: foldDoC op
In an equation for `fCon': fCon = foldDoC op
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