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rebindable6.hs:106:17:
No instance for (HasSeq (IO a -> t0 -> IO b))
arising from a do statement
Possible fix:
add an instance declaration for (HasSeq (IO a -> t0 -> IO b))
In a stmt of a 'do' block: f
In the expression:
do { f;
Just (b :: b) <- g;
return b }
In an equation for `test_do':
test_do f g
= do { f;
Just (b :: b) <- g;
return b }
rebindable6.hs:107:17:
No instance for (HasFail ([Prelude.Char] -> t1))
arising from a do statement
Possible fix:
add an instance declaration for (HasFail ([Prelude.Char] -> t1))
In a stmt of a 'do' block: Just (b :: b) <- g
In the expression:
do { f;
Just (b :: b) <- g;
return b }
In an equation for `test_do':
test_do f g
= do { f;
Just (b :: b) <- g;
return b }
rebindable6.hs:107:17:
No instance for (HasBind (IO (Maybe b) -> (Maybe b -> t1) -> t0))
arising from a do statement
Possible fix:
add an instance declaration for
(HasBind (IO (Maybe b) -> (Maybe b -> t1) -> t0))
In a stmt of a 'do' block: Just (b :: b) <- g
In the expression:
do { f;
Just (b :: b) <- g;
return b }
In an equation for `test_do':
test_do f g
= do { f;
Just (b :: b) <- g;
return b }
rebindable6.hs:108:17:
No instance for (HasReturn (b -> t1))
arising from a use of `return'
Possible fix: add an instance declaration for (HasReturn (b -> t1))
In a stmt of a 'do' block: return b
In the expression:
do { f;
Just (b :: b) <- g;
return b }
In an equation for `test_do':
test_do f g
= do { f;
Just (b :: b) <- g;
return b }
|
