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T11452.hs:6:12: error:
• Illegal polytype: (forall a. a -> a) -> ()
The type of a Typed Template Haskell expression must not have any quantification.
• In the Template Haskell splice $$([|| \ _ -> () ||])
In the expression: $$([|| \ _ -> () ||])
In an equation for ‘impred’: impred = $$([|| \ _ -> () ||])
T11452.hs:6:14: error:
• Couldn't match type ‘p0’ with ‘forall a. a -> a’
Expected: Language.Haskell.TH.Syntax.Code
Language.Haskell.TH.Syntax.Q ((forall a. a -> a) -> ())
Actual: Language.Haskell.TH.Syntax.Code
Language.Haskell.TH.Syntax.Q (p0 -> ())
• Cannot instantiate unification variable ‘p0’
with a type involving polytypes: forall a. a -> a
• In the Template Haskell quotation [|| \ _ -> () ||]
In the expression: [|| \ _ -> () ||]
In the Template Haskell splice $$([|| \ _ -> () ||])
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