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T10619.hs:10:14: error:
    • Couldn't match type ‘p1’ with ‘forall a. a -> a’
      Expected: (forall a. a -> a) -> forall b. b -> b
        Actual: p1 -> p1
    • Cannot instantiate unification variable ‘p1’
      with a type involving polytypes: forall a. a -> a
    • In the expression: \ y -> y
      In the expression:
        if True then
            ((\ x -> x) :: (forall a. a -> a) -> forall b. b -> b)
        else
            \ y -> y
      In an equation for ‘foo’:
          foo _
            = if True then
                  ((\ x -> x) :: (forall a. a -> a) -> forall b. b -> b)
              else
                  \ y -> y

T10619.hs:14:15: error:
    • Couldn't match type ‘p3’ with ‘forall a. a -> a’
      Expected: p3 -> p3
        Actual: (forall a. a -> a) -> forall b. b -> b
    • Cannot equate type variable ‘p3’
      with a type involving polytypes: forall a. a -> a
      ‘p3’ is a rigid type variable bound by
        the inferred type of bar :: p2 -> p3 -> p3
        at T10619.hs:(12,1)-(14,66)
    • In the expression:
          (\ x -> x) :: (forall a. a -> a) -> forall b. b -> b
      In the expression:
        if True then
            \ y -> y
        else
            ((\ x -> x) :: (forall a. a -> a) -> forall b. b -> b)
      In an equation for ‘bar’:
          bar _
            = if True then
                  \ y -> y
              else
                  ((\ x -> x) :: (forall a. a -> a) -> forall b. b -> b)
    • Relevant bindings include
        bar :: p2 -> p3 -> p3 (bound at T10619.hs:12:1)

T10619.hs:17:13: error:
    • Couldn't match type ‘p0’ with ‘forall a. a -> a’
      Expected: (forall a. a -> a) -> forall b. b -> b
        Actual: p0 -> p0
    • Cannot instantiate unification variable ‘p0’
      with a type involving polytypes: forall a. a -> a
    • In the expression: \ y -> y
      In an equation for ‘baz’: baz False = \ y -> y

T10619.hs:20:14: error:
    • Couldn't match type ‘p’ with ‘forall a. a -> a’
      Expected: p -> p
        Actual: (forall a. a -> a) -> forall b. b -> b
    • Cannot equate type variable ‘p’
      with a type involving polytypes: forall a. a -> a
      ‘p’ is a rigid type variable bound by
        the inferred type of quux :: Bool -> p -> p
        at T10619.hs:(19,1)-(20,64)
    • In the expression:
          (\ x -> x) :: (forall a. a -> a) -> forall b. b -> b
      In an equation for ‘quux’:
          quux True = (\ x -> x) :: (forall a. a -> a) -> forall b. b -> b
    • Relevant bindings include
        quux :: Bool -> p -> p (bound at T10619.hs:19:1)