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T17173.hs:6:7: error:
• Cannot apply expression of type ‘a0 -> a0’
to a visible type argument ‘Bool’
• In the expression:
(let
myId :: forall a. a -> a
myId x = x
in myId)
@Bool True
In an equation for ‘foo’:
foo
= (let
myId :: forall a. a -> a
myId x = x
in myId)
@Bool True
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