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T2534.hs:3:13: error:
• Couldn't match type ‘[b]’ with ‘a0 -> [b]’
Expected type: [a0] -> [b] -> [b]
Actual type: [a0] -> (a0 -> [b]) -> [b]
• In the first argument of ‘foldr’, namely ‘(>>=)’
In the expression: foldr (>>=) [] []
In an equation for ‘foo’: foo = foldr (>>=) [] []
• Relevant bindings include foo :: [b] (bound at T2534.hs:3:1)
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