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T2534.hs:3:19:
Couldn't match expected type ‛a -> a -> b’ with actual type ‛[t0]’
Relevant bindings include
foo :: a -> a -> b (bound at T2534.hs:3:1)
In the second argument of ‛foldr’, namely ‛[]’
In the expression: foldr (>>=) [] []
In an equation for ‛foo’: foo = foldr (>>=) [] []
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