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T2846b.hs:5:5:
No instance for (Show (Num a0 => a0)) arising from a use of `show'
Possible fix: add an instance declaration for (Show (Num a0 => a0))
In the expression: show ([1, 2, 3] :: [Num a => a])
In an equation for `f': f = show ([1, 2, 3] :: [Num a => a])
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