Bug fix for complicated GROUP BY ... ORDER BY query.

Fixed problem in access rights testing (from last patch)


mysql-test/r/group_by.result:
  Condenced GROUP test case
mysql-test/t/group_by.test:
  Condenced GROUP test case
sql/sql_parse.cc:
  Fixed problem in access rights testing (from last patch)
sql/sql_select.cc:
  Rollback Sinisa's GROUP BY patch and make a better one.

1 files changed, 5 insertions, 26 deletions

diff --git a/mysql-test/r/group_by.result b/mysql-test/r/group_by.result
index d990760d39b..0ec1c03c467 100644
--- a/mysql-test/r/group_by.result
+++ b/mysql-test/r/group_by.result
@@ -375,38 +375,17 @@ hijklm	2
 DROP TABLE t1;
 drop table if exists t1;
 create table t1 (One int unsigned, Two int unsigned, Three int unsigned, Four int unsigned);
-insert into t1 values (1,2,1,4);
-insert into t1 values (1,2,2,4);
-insert into t1 values (1,2,3,4);
-insert into t1 values (1,2,4,4);
-insert into t1 values (1,1,1,4);
-insert into t1 values (1,1,2,4);
-insert into t1 values (1,1,3,4);
-insert into t1 values (1,1,4,4);
-insert into t1 values (1,3,1,4);
-insert into t1 values (1,3,2,4);
-insert into t1 values (1,3,3,4);
-insert into t1 values (1,3,4,4);
+insert into t1 values (1,2,1,4),(1,2,2,4),(1,2,3,4),(1,2,4,4),(1,1,1,4),(1,1,2,4),(1,1,3,4),(1,1,4,4),(1,3,1,4),(1,3,2,4),(1,3,3,4),(1,3,4,4);
 select One, Two, sum(Four) from t1 group by One,Two;
 One	Two	sum(Four)
 1	1	16
 1	2	16
 1	3	16
-drop table if exists t1;
-drop table if exists t1,t2;
+drop table t1;
 create table t1 (id integer primary key not null auto_increment, gender char(1));
-insert into t1 values(NULL, 'M');
-insert into t1 values(NULL, 'F');
-insert into t1 values(NULL, 'F');
-insert into t1 values(NULL, 'F');
-insert into t1 values(NULL, 'M');
-create table t2 (user_id integer not null, timestamp datetime);
-insert into t2 values (1, sysdate());
-insert into t2 values (2, sysdate());
-insert into t2 values (1, sysdate());
-insert into t2 values (3, sysdate());
-insert into t2 values (4, sysdate());
-insert into t2 values (4, sysdate());
+insert into t1 values (NULL, 'M'), (NULL, 'F'),(NULL, 'F'),(NULL, 'F'),(NULL, 'M');
+create table t2 (user_id integer not null, date date);
+insert into t2 values (1, '2002-06-09'),(2, '2002-06-09'),(1, '2002-06-09'),(3, '2002-06-09'),(4, '2002-06-09'),(4, '2002-06-09');
 select u.gender as gender, count(distinct  u.id) as dist_count, (count(distinct u.id)/5*100) as percentage from t1 u, t2 l where l.user_id = u.id group by u.gender;
 gender	dist_count	percentage
 F	3	60.00