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-rw-r--r--mysql-test/r/subselect.result89
1 files changed, 89 insertions, 0 deletions
diff --git a/mysql-test/r/subselect.result b/mysql-test/r/subselect.result
index b23556887c1..e3aa87876ed 100644
--- a/mysql-test/r/subselect.result
+++ b/mysql-test/r/subselect.result
@@ -4899,3 +4899,92 @@ WHERE t1.a = d1.a;
ERROR 42S22: Unknown column 'd1.a' in 'where clause'
DROP TABLE t1;
End of 5.1 tests.
+Set up test tables.
+CREATE TABLE t1 (
+t1_id INT UNSIGNED,
+PRIMARY KEY(t1_id)
+) Engine=MyISAM;
+INSERT INTO t1 (t1_id) VALUES (1), (2), (3), (4), (5);
+CREATE TABLE t2 SELECT * FROM t1;
+CREATE TABLE t3 (
+t3_id INT UNSIGNED AUTO_INCREMENT,
+t1_id INT UNSIGNED,
+amount DECIMAL(16,2),
+PRIMARY KEY(t3_id),
+KEY(t1_id)
+) Engine=MyISAM;
+INSERT INTO t3 (t1_id, t3_id, amount)
+VALUES (1, 1, 100.00), (2, 2, 200.00), (4, 4, 400.00);
+This is the 'inner query' running by itself.
+Produces correct results.
+SELECT
+t1.t1_id,
+IFNULL((SELECT SUM(amount) FROM t3 WHERE t3.t1_id=t1.t1_id), 0) AS total_amount
+FROM
+t1
+LEFT JOIN t2 ON t2.t1_id=t1.t1_id
+GROUP BY
+t1.t1_id
+;
+t1_id total_amount
+1 100.00
+2 200.00
+3 0.00
+4 400.00
+5 0.00
+SELECT * FROM (the same inner query)
+Produces correct results.
+SELECT * FROM (
+SELECT
+t1.t1_id,
+IFNULL((SELECT SUM(amount) FROM t3 WHERE t3.t1_id=t1.t1_id), 0) AS total_amount
+FROM
+t1
+LEFT JOIN t2 ON t2.t1_id=t1.t1_id
+GROUP BY
+t1.t1_id
+) AS t;
+t1_id total_amount
+1 100.00
+2 200.00
+3 0.00
+4 400.00
+5 0.00
+Now make t2.t1_id part of a key.
+ALTER TABLE t2 ADD PRIMARY KEY(t1_id);
+Same inner query by itself.
+Still correct results.
+SELECT
+t1.t1_id,
+IFNULL((SELECT SUM(amount) FROM t3 WHERE t3.t1_id=t1.t1_id), 0) AS total_amount
+FROM
+t1
+LEFT JOIN t2 ON t2.t1_id=t1.t1_id
+GROUP BY
+t1.t1_id;
+t1_id total_amount
+1 100.00
+2 200.00
+3 0
+4 400.00
+5 0
+SELECT * FROM (the same inner query), now with indexes on the LEFT JOIN
+SELECT * FROM (
+SELECT
+t1.t1_id,
+IFNULL((SELECT SUM(amount) FROM t3 WHERE t3.t1_id=t1.t1_id), 0) AS total_amount
+FROM
+t1
+LEFT JOIN t2 ON t2.t1_id=t1.t1_id
+GROUP BY
+t1.t1_id
+) AS t;
+t1_id total_amount
+1 100.00
+2 200.00
+3 0.00
+4 400.00
+5 0.00
+DROP TABLE t3;
+DROP TABLE t2;
+DROP TABLE t1;