#
# The following entries are meant for testing the parser, ensuring
# the right values are passed down to the executor, for all possible
# syntax combinations.
#
# Test basic syntax.
#
create table t1 (a int);
create table t_keyword (`offset` int);
insert into t1 values (1), (1), (2), (3), (2);
insert into t_keyword values (1), (1), (2), (3), (2);
#
# Make sure the FETCH clause addition didn't introduce problems with
# the offset keyword.
#
select * from t1
order by a
offset 2 rows;
a
2
2
3
select * from t1
offset 2 rows;
a
2
2
3
#
# Offset is now a reserved keyword. Column names can not have that name
# without escaping the identifier.
#
select * from t_keyword
order by offset;
ERROR 42000: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'offset' at line 2
select * from t_keyword
order by `offset`;
offset
1
1
2
2
3
#
# Test syntax without a specific limit. (implicit one row)
# Test the alias between row / rows and first / next.
# Test ONLY vs WITH TIES.
#
select * from t1
fetch first row only;
a
1
select * from t1
fetch first rows only;
a
1
select * from t1
fetch next row only;
a
1
select * from t1
fetch next rows only;
a
1
#
# Row / rows are mandatory after offset <n>
#
select * from t1
order by a
offset 2
fetch first row only;
ERROR 42000: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'fetch first row only' at line 4
select * from t1
order by a
offset 2;
ERROR 42000: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' at line 3
select * from t1
order by a
offset 2 row
fetch first row only;
a
2
select * from t1
order by a
offset 2 rows
fetch first row only;
a
2
#
# Include offset before fetch clause.
#
select * from t1
order by a
offset 2 rows
fetch first row only;
a
2
select * from t1
order by a
offset 2 rows
fetch first rows only;
a
2
select * from t1
offset 2 rows
fetch next row only;
a
2
select * from t1
offset 2 rows
fetch next rows only;
a
2
#
# Repeat the tests, but now with WITH TIES.
# WITH TIES requires order by.
#
select * from t1
fetch first row with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
fetch first rows with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
fetch next row with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
fetch next rows with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
order by a
fetch first row with ties;
a
1
1
select * from t1
order by a
fetch first rows with ties;
a
1
1
select * from t1
order by a
fetch next row with ties;
a
1
1
select * from t1
order by a
fetch next rows with ties;
a
1
1
#
# Include offset before fetch clause.
#
select * from t1
order by a
offset 2 rows
fetch first row with ties;
a
2
2
select * from t1
order by a
offset 2 rows
fetch first rows with ties;
a
2
2
select * from t1
order by a
offset 2 rows
fetch next row with ties;
a
2
2
select * from t1
order by a
offset 2 rows
fetch next rows with ties;
a
2
2
#
# Test syntax with a specific limit
#
select * from t1
fetch first 3 row only;
a
1
1
2
select * from t1
fetch first 3 rows only;
a
1
1
2
select * from t1
fetch next 3 row only;
a
1
1
2
select * from t1
fetch next 3 rows only;
a
1
1
2
#
# Include offset before fetch clause.
#
select * from t1
order by a
offset 2 rows
fetch first 3 row only;
a
2
2
3
select * from t1
order by a
offset 2 rows
fetch first 3 rows only;
a
2
2
3
select * from t1
offset 2 rows
fetch next 3 row only;
a
2
3
2
select * from t1
offset 2 rows
fetch next 3 rows only;
a
2
3
2
#
# Repeat the tests, but now with WITH TIES.
# WITH TIES requires order by.
#
select * from t1
fetch first 3 row with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
fetch first 3 rows with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
fetch next 3 row with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
fetch next 3 rows with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
order by a
fetch first 3 row with ties;
a
1
1
2
2
select * from t1
order by a
fetch first 3 rows with ties;
a
1
1
2
2
select * from t1
order by a
fetch next 3 row with ties;
a
1
1
2
2
select * from t1
order by a
fetch next 3 rows with ties;
a
1
1
2
2
#
# Include offset before fetch clause.
#
select * from t1
offset 2 rows
fetch first row with ties;
ERROR HY000: FETCH ... WITH TIES requires ORDER BY clause to be present
select * from t1
order by a
offset 2 rows
fetch first 3 row with ties;
a
2
2
3
select * from t1
order by a
offset 2 rows
fetch first 3 rows with ties;
a
2
2
3
select * from t1
order by a
offset 2 rows
fetch next 3 row with ties;
a
2
2
3
select * from t1
order by a
offset 2 rows
fetch next 3 rows with ties;
a
2
2
3
drop table t1;
drop table t_keyword;
#
# Test behaviour with a simple select.
#
create table t1 (id int, first_name varchar(100), last_name varchar(100), score double);
insert into t1 values
(1, 'Alice', 'Fowler', 5),
(2, 'John', 'Doe', 6),
(3, 'John', 'Smith', 6),
(4, 'John', 'Smith', 6),
(5, 'John', 'Smith', 7),
(6, 'John', 'Elton', 8.1),
(7, 'Bob',  'Trasc', 9),
(8, 'Silvia', 'Ganush', 10);
create table t2
(id int,
location varchar(100),
fk int,
constraint `fk_t1`
     FOREIGN KEY (fk) REFERENCES t1 (id)
ON DELETE CASCADE
ON UPDATE RESTRICT);
insert into t2 values
(1, 'L1', 1),
(2, 'L2', 2),
(3, 'L3', 3),
(4, 'L3', 4),
(5, 'L4', 5),
(6, 'L4', 6),
(7, 'L4', 7),
(7, null, 8);
select * from t1
order by id
fetch first 3 rows only;
id	first_name	last_name	score
1	Alice	Fowler	5
2	John	Doe	6
3	John	Smith	6
select * from t1
order by id
fetch first 3 rows with ties;
id	first_name	last_name	score
1	Alice	Fowler	5
2	John	Doe	6
3	John	Smith	6
select * from t1
order by first_name
fetch first 3 rows only;
id	first_name	last_name	score
1	Alice	Fowler	5
7	Bob	Trasc	9
3	John	Smith	6
select * from t1
order by first_name
fetch first 3 rows with ties;
id	first_name	last_name	score
1	Alice	Fowler	5
7	Bob	Trasc	9
2	John	Doe	6
3	John	Smith	6
4	John	Smith	6
5	John	Smith	7
6	John	Elton	8.1
#
# Test multi-part order by.
#
select * from t1
order by first_name, last_name
fetch first 3 rows with ties;
id	first_name	last_name	score
1	Alice	Fowler	5
7	Bob	Trasc	9
2	John	Doe	6
select * from t1
order by first_name, last_name
fetch first 4 rows with ties;
id	first_name	last_name	score
1	Alice	Fowler	5
7	Bob	Trasc	9
2	John	Doe	6
6	John	Elton	8.1
select * from t1
order by first_name, last_name
offset 1 rows
fetch first 3 rows with ties;
id	first_name	last_name	score
7	Bob	Trasc	9
2	John	Doe	6
6	John	Elton	8.1
select * from t1
order by first_name, last_name
offset 1 rows
fetch first 3 rows only;
id	first_name	last_name	score
7	Bob	Trasc	9
2	John	Doe	6
6	John	Elton	8.1
select * from t1
order by first_name, last_name
offset 1 rows
fetch first 3 rows with ties;
id	first_name	last_name	score
7	Bob	Trasc	9
2	John	Doe	6
6	John	Elton	8.1
select * from t1
order by first_name, last_name
offset 2 rows
fetch first 3 rows only;
id	first_name	last_name	score
2	John	Doe	6
6	John	Elton	8.1
5	John	Smith	7
select * from t1
order by first_name, last_name
offset 2 rows
fetch first 3 rows with ties;
id	first_name	last_name	score
2	John	Doe	6
6	John	Elton	8.1
3	John	Smith	6
4	John	Smith	6
5	John	Smith	7
select * from t1
order by first_name, last_name
offset 3 rows
fetch first 3 rows only;
id	first_name	last_name	score
6	John	Elton	8.1
3	John	Smith	6
4	John	Smith	6
select * from t1
order by first_name, last_name
offset 3 rows
fetch first 3 rows with ties;
id	first_name	last_name	score
6	John	Elton	8.1
3	John	Smith	6
4	John	Smith	6
5	John	Smith	7
select * from t1
order by first_name, last_name
offset 4 rows
fetch first 3 rows only;
id	first_name	last_name	score
3	John	Smith	6
4	John	Smith	6
5	John	Smith	7
select * from t1
order by first_name, last_name
offset 4 rows
fetch first 3 rows with ties;
id	first_name	last_name	score
3	John	Smith	6
4	John	Smith	6
5	John	Smith	7
#
# Test offset crossing into a new peer-group.
#
select * from t1
order by first_name, last_name
offset 5 rows
fetch first 3 rows with ties;
id	first_name	last_name	score
4	John	Smith	6
5	John	Smith	7
8	Silvia	Ganush	10
select * from t1
order by first_name, last_name
offset 5 rows
fetch first 3 rows only;
id	first_name	last_name	score
4	John	Smith	6
5	John	Smith	7
8	Silvia	Ganush	10
#
# Simple join with 2 tables, order by without columns in the
# second table and also with columns in the second table.
#
# Cover both only and with ties.
#
select t1.id, t1.first_name, t1.last_name, t1.score, t2.location
from t1 inner join t2 on t1.id = t2.fk
order by t1.first_name, t1.last_name
fetch first 3 rows only;
id	first_name	last_name	score	location
1	Alice	Fowler	5	L1
7	Bob	Trasc	9	L4
2	John	Doe	6	L2
select t1.id, t1.first_name, t1.last_name, t1.score, t2.location
from t1 inner join t2 on t1.id = t2.fk
order by t2.location, t1.first_name, t1.last_name
fetch first 3 rows only;
id	first_name	last_name	score	location
8	Silvia	Ganush	10	NULL
1	Alice	Fowler	5	L1
2	John	Doe	6	L2
select t1.id, t1.first_name, t1.last_name, t1.score, t2.location
from t1 inner join t2 on t1.id = t2.fk
order by t1.first_name, t1.last_name
fetch first 3 rows with ties;
id	first_name	last_name	score	location
1	Alice	Fowler	5	L1
7	Bob	Trasc	9	L4
2	John	Doe	6	L2
select t1.id, t1.first_name, t1.last_name, t1.score, t2.location
from t1 inner join t2 on t1.id = t2.fk
order by t2.location, t1.first_name, t1.last_name
fetch first 3 rows with ties;
id	first_name	last_name	score	location
8	Silvia	Ganush	10	NULL
1	Alice	Fowler	5	L1
2	John	Doe	6	L2
#
# Test descending order by.
#
select t1.id, t1.first_name, t1.last_name, t1.score, t2.location
from t1 inner join t2 on t1.id = t2.fk
order by t2.location desc, t1.first_name, t1.last_name
fetch first 3 rows only;
id	first_name	last_name	score	location
7	Bob	Trasc	9	L4
6	John	Elton	8.1	L4
5	John	Smith	7	L4
select * from t2
order by t2.location desc
fetch first 2 rows with ties;
id	location	fk
5	L4	5
6	L4	6
7	L4	7
select * from t2
order by t2.location desc
offset 1 rows
fetch first 2 rows with ties;
id	location	fk
6	L4	6
7	L4	7
select * from t2
order by t2.location desc
offset 2 rows
fetch first 2 rows with ties;
id	location	fk
3	L3	3
4	L3	4
7	L4	7
#
# Test a join with descending order by.
#
select t1.id, t1.first_name, t1.last_name, t1.score, t2.location
from t1 inner join t2 on t1.id = t2.fk
order by t2.location desc, t1.first_name, t1.last_name
fetch first 3 rows with ties;
id	first_name	last_name	score	location
7	Bob	Trasc	9	L4
6	John	Elton	8.1	L4
5	John	Smith	7	L4
#
# Test subqueries.
#
select * from (
select * from t2
order by t2.location desc
offset 2 rows
fetch first 2 rows with ties
) temp;
id	location	fk
7	L4	7
3	L3	3
4	L3	4
select * from t2
order by t2.location desc
offset 0 rows
fetch first 2 rows with ties;
id	location	fk
5	L4	5
6	L4	6
7	L4	7
create view v1 as (
select * from t2
order by t2.location desc
offset 0 rows
fetch first 2 rows with ties
);
create view v2 as (
select * from t2
order by t2.location desc
offset 1 rows
fetch first 2 rows with ties
);
create view v3 as (
select * from t2
order by t2.location desc
offset 2 rows
fetch first row with ties
);
select * from v1;
id	location	fk
5	L4	5
6	L4	6
7	L4	7
select * from v2;
id	location	fk
6	L4	6
7	L4	7
select * from v3;
id	location	fk
7	L4	7
show create view v1;
View	Create View	character_set_client	collation_connection
v1	CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`localhost` SQL SECURITY DEFINER VIEW `v1` AS (select `t2`.`id` AS `id`,`t2`.`location` AS `location`,`t2`.`fk` AS `fk` from `t2` order by `t2`.`location` desc offset 0 rows  fetch first 2 rows with ties)	latin1	latin1_swedish_ci
show create view v2;
View	Create View	character_set_client	collation_connection
v2	CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`localhost` SQL SECURITY DEFINER VIEW `v2` AS (select `t2`.`id` AS `id`,`t2`.`location` AS `location`,`t2`.`fk` AS `fk` from `t2` order by `t2`.`location` desc offset 1 rows  fetch first 2 rows with ties)	latin1	latin1_swedish_ci
show create view v3;
View	Create View	character_set_client	collation_connection
v3	CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`localhost` SQL SECURITY DEFINER VIEW `v3` AS (select `t2`.`id` AS `id`,`t2`.`location` AS `location`,`t2`.`fk` AS `fk` from `t2` order by `t2`.`location` desc offset 2 rows  fetch first 1 rows with ties)	latin1	latin1_swedish_ci
#
# Test joins with views and order by referenced from the view.
#
select *
from t1 inner join v1 on t1.id = v1.fk
order by v1.location desc, t1.first_name
offset 1 rows
fetch first 1 rows with ties;
id	first_name	last_name	score	id	location	fk
5	John	Smith	7	5	L4	5
6	John	Elton	8.1	6	L4	6
select first_name, last_name, sum(score)
from t1
group by first_name, last_name
order by first_name;
first_name	last_name	sum(score)
Alice	Fowler	5
Bob	Trasc	9
John	Doe	6
John	Elton	8.1
John	Smith	19
Silvia	Ganush	10
#
# Test with ties with group by. Make sure that if order by is a less
# specific sort of group by, that WITH TIES still gets executed.
#
explain
select first_name, last_name, sum(score)
from t1
group by first_name, last_name
order by first_name
offset 1 rows
fetch first 2 rows with ties;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	SIMPLE	t1	ALL	NULL	NULL	NULL	NULL	8	Using temporary; Using filesort
select first_name, last_name, sum(score)
from t1
group by first_name, last_name
order by first_name
offset 1 rows
fetch first 2 rows with ties;
first_name	last_name	sum(score)
Bob	Trasc	9
John	Doe	6
John	Elton	8.1
John	Smith	19
drop table t1;
drop table t2;
drop view v1;
drop view v2;
drop view v3;
#
# Test with ties when an index is used to provide the order by.
#
create table t1 (id int, first_name varchar(100), last_name varchar(100), score double);
create index t1_name on t1 (first_name, last_name);
insert into t1 values
(1, 'Alice', 'Fowler', 5),
(2, 'John', 'Doe', 6),
(3, 'John', 'Smith', 6),
(4, 'John', 'Smith', 6),
(5, 'John', 'Smith', 7),
(6, 'John', 'Elton', 8.1),
(7, 'Bob',  'Trasc', 9),
(8, 'Silvia', 'Ganush', 10);
explain select first_name, last_name
from t1
order by first_name
offset 1 rows
fetch first 2 rows with ties;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	SIMPLE	t1	index	NULL	t1_name	206	NULL	3	Using index
explain select first_name, last_name
from t1
order by first_name desc
fetch first 2 rows with ties;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	SIMPLE	t1	index	NULL	t1_name	206	NULL	2	Using index
select first_name, last_name
from t1
order by first_name
offset 1 rows
fetch first 2 rows with ties;
first_name	last_name
Bob	Trasc
John	Doe
John	Elton
John	Smith
John	Smith
John	Smith
select first_name, last_name
from t1
order by first_name desc
fetch first 2 rows with ties;
first_name	last_name
Silvia	Ganush
John	Smith
John	Smith
John	Smith
John	Elton
John	Doe
select first_name, last_name
from t1
order by first_name desc
offset 1 rows
fetch first 2 rows with ties;
first_name	last_name
John	Smith
John	Smith
John	Smith
John	Elton
John	Doe
select first_name, last_name
from t1
order by first_name desc
offset 4 rows
fetch first 2 rows with ties;
first_name	last_name
John	Elton
John	Doe
select first_name, last_name
from t1
order by first_name desc
offset 4 rows
fetch first 3 rows with ties;
first_name	last_name
John	Elton
John	Doe
Bob	Trasc
explain select first_name, last_name
from t1
where first_name != 'John'
order by first_name
fetch first 2 rows with ties;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	SIMPLE	t1	range	t1_name	t1_name	103	NULL	3	Using where; Using index
select first_name, last_name
from t1
where first_name != 'John'
order by first_name
fetch first 2 rows with ties;
first_name	last_name
Alice	Fowler
Bob	Trasc
select first_name, last_name
from t1
where first_name != 'John'
group by first_name, last_name
order by first_name
fetch first 2 rows with ties;
first_name	last_name
Alice	Fowler
Bob	Trasc
#
# Test CTE support.
#
explain with temp_table as (
select first_name, last_name
from t1
where first_name != 'John'
  group by first_name, last_name
order by first_name
fetch first 2 rows with ties
)
select * from temp_table
order by first_name, last_name;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	PRIMARY	<derived2>	ALL	NULL	NULL	NULL	NULL	2	Using filesort
2	DERIVED	t1	range	t1_name	t1_name	103	NULL	3	Using where; Using index
with temp_table as (
select first_name, last_name
from t1
group by first_name, last_name
order by first_name
fetch first 3 rows with ties
)
select * from temp_table
order by first_name, last_name;
first_name	last_name
Alice	Fowler
Bob	Trasc
John	Doe
John	Elton
John	Smith
with temp_table as (
select first_name, last_name
from t1
group by first_name, last_name
order by first_name
fetch first 3 rows with ties
)
select * from temp_table
order by last_name
fetch first 3 rows with ties;
first_name	last_name
John	Doe
John	Elton
Alice	Fowler
with temp_table as (
select first_name, last_name
from t1
group by first_name, last_name
order by first_name
fetch first 3 rows with ties
)
select * from temp_table
order by first_name
fetch first 3 rows with ties;
first_name	last_name
Alice	Fowler
Bob	Trasc
John	Doe
John	Elton
John	Smith
with temp_table as (
select first_name, last_name
from t1
group by first_name, last_name
order by first_name
fetch first 3 rows with ties
)
select * from temp_table
order by first_name
offset 1 rows
fetch first 2 rows with ties;
first_name	last_name
Bob	Trasc
John	Doe
John	Elton
John	Smith
select first_name, row_number() over () rn
from t1
order by rn
offset 1 rows
fetch first 2 rows with ties;
first_name	rn
Bob	2
John	3
select first_name, row_number() over () rn
from t1
order by rn desc
offset 1 rows
fetch first 2 rows with ties;
first_name	rn
John	7
John	6
select first_name, score, rank() over (ORDER BY score)
from t1
order by rank() over (ORDER BY score)
fetch first 3 rows with ties;
first_name	score	rank() over (ORDER BY score)
Alice	5	1
John	6	2
John	6	2
John	6	2
select first_name, score, rank() over (ORDER BY score)
from t1
order by rank() over (ORDER BY score)
offset 1 rows
fetch first 2 rows with ties;
first_name	score	rank() over (ORDER BY score)
John	6	2
John	6	2
John	6	2
select first_name, score, rank() over (ORDER BY score)
from t1
order by rank() over (ORDER BY score)
fetch first 6 rows with ties;
first_name	score	rank() over (ORDER BY score)
Alice	5	1
John	6	2
John	6	2
John	6	2
John	7	5
John	8.1	6
#
# Test nulls.
#
create table t2 (id int, location varchar(100), time datetime, value int, fk int);
insert into t2 values (1, 'home', '2020-01-01 10:00', 10, 1);
insert into t2 values (2, 'home', '2020-01-01 11:00', 11, 2);
insert into t2 values (3, 'home', '2020-01-01 12:00', 12, 3);
insert into t2 values (4, 'home', '2020-01-01 13:00', 13, 3);
insert into t2 values (5, 'home', '2020-01-01 14:00', 13, 3);
insert into t2 values (6, 'home', '2020-01-01 15:00', 13, 2);
insert into t2 values (7, 'home', '2020-01-01 16:00', 13, 6);
insert into t2 values (8, 'outside', '2020-01-01 17:00', 17, 6);
insert into t2 values (9, 'outside', '2020-01-01 18:00', 17, 6);
insert into t2 values (10, 'outside', '2020-01-01 19:00', 17, 8);
insert into t2 values (11, 'outside', '2020-01-01 20:00', 16, 7);
insert into t2 values (12, 'outside', '2020-01-01 21:00', 16, 7);
select *
from t1 left join t2 on t1.id = t2.fk
order by t2.location;
id	first_name	last_name	score	id	location	time	value	fk
1	Alice	Fowler	5	1	home	2020-01-01 10:00:00	10	1
2	John	Doe	6	2	home	2020-01-01 11:00:00	11	2
2	John	Doe	6	6	home	2020-01-01 15:00:00	13	2
3	John	Smith	6	3	home	2020-01-01 12:00:00	12	3
3	John	Smith	6	4	home	2020-01-01 13:00:00	13	3
3	John	Smith	6	5	home	2020-01-01 14:00:00	13	3
4	John	Smith	6	NULL	NULL	NULL	NULL	NULL
5	John	Smith	7	NULL	NULL	NULL	NULL	NULL
6	John	Elton	8.1	7	home	2020-01-01 16:00:00	13	6
6	John	Elton	8.1	8	outside	2020-01-01 17:00:00	17	6
6	John	Elton	8.1	9	outside	2020-01-01 18:00:00	17	6
7	Bob	Trasc	9	11	outside	2020-01-01 20:00:00	16	7
7	Bob	Trasc	9	12	outside	2020-01-01 21:00:00	16	7
8	Silvia	Ganush	10	10	outside	2020-01-01 19:00:00	17	8
select *
from t1 left join t2 on t1.id = t2.fk
order by t2.location
fetch first 1 row with ties;
id	first_name	last_name	score	id	location	time	value	fk
4	John	Smith	6	NULL	NULL	NULL	NULL	NULL
5	John	Smith	7	NULL	NULL	NULL	NULL	NULL
select *
from t1 left join t2 on t1.id = t2.fk
order by t2.location
fetch first 2 row with ties;
id	first_name	last_name	score	id	location	time	value	fk
4	John	Smith	6	NULL	NULL	NULL	NULL	NULL
5	John	Smith	7	NULL	NULL	NULL	NULL	NULL
select *
from t1 left join t2 on t1.id = t2.fk
order by t2.location
fetch first 3 row with ties;
id	first_name	last_name	score	id	location	time	value	fk
1	Alice	Fowler	5	1	home	2020-01-01 10:00:00	10	1
2	John	Doe	6	2	home	2020-01-01 11:00:00	11	2
2	John	Doe	6	6	home	2020-01-01 15:00:00	13	2
3	John	Smith	6	3	home	2020-01-01 12:00:00	12	3
3	John	Smith	6	4	home	2020-01-01 13:00:00	13	3
3	John	Smith	6	5	home	2020-01-01 14:00:00	13	3
4	John	Smith	6	NULL	NULL	NULL	NULL	NULL
5	John	Smith	7	NULL	NULL	NULL	NULL	NULL
6	John	Elton	8.1	7	home	2020-01-01 16:00:00	13	6
select *
from t1 left join t2 on t1.id = t2.fk
order by t2.location
offset 2 rows
fetch first 1 row with ties;
id	first_name	last_name	score	id	location	time	value	fk
1	Alice	Fowler	5	1	home	2020-01-01 10:00:00	10	1
2	John	Doe	6	2	home	2020-01-01 11:00:00	11	2
2	John	Doe	6	6	home	2020-01-01 15:00:00	13	2
3	John	Smith	6	3	home	2020-01-01 12:00:00	12	3
3	John	Smith	6	4	home	2020-01-01 13:00:00	13	3
3	John	Smith	6	5	home	2020-01-01 14:00:00	13	3
6	John	Elton	8.1	7	home	2020-01-01 16:00:00	13	6
#
# Test union-like operator with multiple fetch first clauses.
#
select * from t1 order by 1 fetch first 3 rows with ties;
id	first_name	last_name	score
1	Alice	Fowler	5
2	John	Doe	6
3	John	Smith	6
select * from t1 order by first_name desc fetch first 3 rows with ties;
id	first_name	last_name	score
8	Silvia	Ganush	10
2	John	Doe	6
3	John	Smith	6
4	John	Smith	6
5	John	Smith	7
6	John	Elton	8.1
(select * from t1 order by 1 fetch first 3 rows with ties)
intersect
(select * from t1 order by first_name desc fetch first 3 rows with ties)
order by first_name
fetch first 1 row with ties;
id	first_name	last_name	score
2	John	Doe	6
3	John	Smith	6
(select * from t1 order by 1 fetch first 3 rows with ties)
except
(select * from t1 order by first_name desc fetch first 3 rows with ties)
order by first_name
fetch first 1 row with ties;
id	first_name	last_name	score
1	Alice	Fowler	5
(select * from t1 order by 1 fetch first 3 rows with ties)
except
(select * from t1 order by first_name desc fetch first 3 rows with ties)
order by first_name
offset 1 rows
fetch first 1 row with ties;
id	first_name	last_name	score
select sum(score)
from t1
order by 1
fetch first 2 rows with ties;
sum(score)
57.1
select sum(score)
from t1
group by id
order by 1
fetch first 2 rows with ties;
sum(score)
5
6
6
6
drop table t1;
drop table t2;
#
# Test SQL_CALC_FOUND_ROWS
#
create table t1 (a int, b int, index (a,b));
insert into t1 values (1,1), (1,2), (1,3), (2,1), (2,2), (3,1);
select SQL_CALC_FOUND_ROWS a, b, count(*)
from t1
group by a, b
order by a
fetch first 1 rows with ties;
a	b	count(*)
1	1	1
1	2	1
1	3	1
SELECT FOUND_ROWS();
FOUND_ROWS()
6
select SQL_CALC_FOUND_ROWS a, b
from t1
order by a
fetch first 1 rows with ties;
a	b
1	1
1	2
1	3
SELECT FOUND_ROWS();
FOUND_ROWS()
6
#
# Test index read optimization with ORDER BY as sub part of GROUP BY
#
explain select a, b, count(*)
from t1
group by a, b
order by a;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	SIMPLE	t1	index	NULL	a	10	NULL	6	Using index
explain select a, b, count(*)
from t1
group by a, b
order by a
fetch first 1 rows with ties;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	SIMPLE	t1	index	NULL	a	10	NULL	1	Using index
#
# Test FETCH ... WITH TIES / ONLY with prepared statements
#
prepare s from "select a, b from t1 order by a fetch first ? rows with ties";
set @a='qwe';
execute s using @a;
a	b
set @a=-1;
execute s using @a;
ERROR HY000: Incorrect arguments to EXECUTE
prepare s2 from "select a, b from t1 order by a offset ? rows fetch first ? rows with ties";
set @offset=1;
set @limit_count= 2;
execute s2 using @offset, @limit_count;
a	b
1	2
1	3
execute s2 using @offset, 3;
a	b
1	2
1	3
2	1
2	2
execute s2 using -1, 3;
ERROR HY000: Incorrect arguments to EXECUTE
#
# Test with ties with a constant order by.
#
select a, b
from t1
order by 'x'
fetch first 2 rows with ties;
a	b
1	1
1	2
1	3
2	1
2	2
3	1
select b, sum(a)
from t1
group by b
order by 'x', 'y', 'z'
fetch first 2 rows with ties;
b	sum(a)
1	6
2	3
3	1
#
# Test with ties when group by is used and order by gets eliminated.
#
select b, sum(a)
from t1
group by b
order by 'x', 'y', 'z'
fetch first 2 rows with ties;
b	sum(a)
1	6
2	3
3	1
#
# Test an ill formed SELECT using MySQL/MariaDBs group by extension
# of not requiring all non-aggregate fields to be part of group
# by.
#
select b, a, sum(a)
from t1
group by a
order by b, 'x', 'y', 'z'
fetch first 2 rows with ties;
b	a	sum(a)
1	1	3
1	2	4
1	3	3
delete from t1;
insert into t1 values (1,1), (1,2), (1,3), (2,1), (2,2), (3,2), (3, 3);
select b, a, sum(a)
from t1
group by a
order by b, 'x', 'y', 'z'
fetch first 1 rows with ties;
b	a	sum(a)
1	1	3
1	2	4
select b, a, sum(a)
from t1
group by a
order by 'x', b, 'x', 'y', 'z'
fetch first 1 rows with ties;
b	a	sum(a)
1	1	3
1	2	4
select b, a, sum(a)
from t1
group by a
order by 'x', 'y', b
fetch first 1 rows with ties;
b	a	sum(a)
1	1	3
1	2	4
#
# Test with ties when order by a const column is used.
#
select a, b
from t1
order by a, 'a'
fetch first 2 rows with ties;
a	b
1	1
1	2
1	3
#
# Order by aggregates.
#
select a, b, sum(a)
from t1
group by a, b
order by sum(a)
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
1	2	1
1	3	1
# Test different sum function in order by, not present in select list.
select a, b, sum(a)
from t1
group by a, b
order by sum(b)
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
2	1	2
# Test aggregates with constant columns in order by.
select a, b, sum(a)
from t1
group by a, b
order by a
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
1	2	1
1	3	1
select a, b, sum(a)
from t1
group by a, b
order by a, 'x'
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
1	2	1
1	3	1
select a, b, sum(a)
from t1
group by a, b
order by a, b
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
select a, b, sum(a)
from t1
group by a, b
order by a, b
fetch first 2 rows with ties;
a	b	sum(a)
1	1	1
1	2	1
select a, b, sum(a)
from t1
group by a, b
order by a, b, 'x'
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
select a, b, sum(a)
from t1
group by a, 'x', b
order by a, b, 'x'
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
select a, b, sum(a)
from t1
group by 'x', a, b
order by a, b, 'x'
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
select a, b, sum(a)
from t1
group by a, b
order by 'x', a, 'x', b, 't', b
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
select a, b, sum(a)
from t1
group by a, b
order by b, 't', b
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
2	1	2
#
# Test with subqueries in order by
#
select a, b, sum(a)
from t1
group by a, b
order by (select 1)
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
1	2	1
1	3	1
2	1	2
2	2	2
3	2	3
3	3	3
select a, b, sum(a)
from t1
group by a, b
order by (select 1), a
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
1	2	1
1	3	1
select a, b, sum(a)
from t1
group by a, b
order by (select 1), a
fetch first 1 rows with ties;
a	b	sum(a)
1	1	1
1	2	1
1	3	1
drop table t1;
#
# MDEV-25441
# WITH TIES is not respected with SQL_BUFFER_RESULT and constant in ORDER BY
#
CREATE TABLE t1 (a INT);
INSERT INTO t1 values (1), (2), (3), (4), (5), (6), (7), (8), (9), (10);
explain SELECT SQL_BUFFER_RESULT 1 AS f FROM t1 ORDER BY f FETCH NEXT 2 ROW WITH TIES;
id	select_type	table	type	possible_keys	key	key_len	ref	rows	Extra
1	SIMPLE	t1	ALL	NULL	NULL	NULL	NULL	10	Using temporary
SELECT SQL_BUFFER_RESULT 1 AS f FROM t1 ORDER BY f FETCH NEXT 2 ROW WITH TIES;
f
1
1
1
1
1
1
1
1
1
1
SELECT 1 AS f FROM t1 ORDER BY f FETCH NEXT 2 ROW WITH TIES;
f
1
1
1
1
1
1
1
1
1
1
drop table t1;
#
# MDEV-25481: Memory leak upon query WITH TIES involving a blob
#
CREATE TABLE t (a TEXT);
INSERT INTO t VALUES ('foo'),('bar');
SELECT a FROM t ORDER BY a FETCH FIRST 2 ROWS WITH TIES;
a
bar
foo
DROP TABLE t;