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# test of problems with having (Reported by Mark Rogers)
#

--disable_warnings
drop table if exists t1,t2;
--enable_warnings

create table t1 (a int);
select count(a) as b from t1 where a=0 having b > 0;
insert into t1 values (null);
select count(a) as b from t1 where a=0 having b > 0;
select count(a) as b from t1 where a=0 having b >=0;
explain extended select count(a) as b from t1 where a=0 having b >=0;
drop table t1; 

#
# Test of problem with HAVING and AVG()
#

CREATE TABLE t1 (
  raw_id int(10) NOT NULL default '0',
  chr_start int(10) NOT NULL default '0',
  chr_end int(10) NOT NULL default '0',
  raw_start int(10) NOT NULL default '0',
  raw_end int(10) NOT NULL default '0',
  raw_ori int(2) NOT NULL default '0'
);

INSERT INTO t1 VALUES (469713,1,164123,1,164123,1),(317330,164124,317193,101,153170,1),(469434,317194,375620,101,58527,1),(591816,375621,484273,1,108653,1),(591807,484274,534671,91,50488,1),(318885,534672,649362,101,114791,1),(318728,649363,775520,102,126259,1),(336829,775521,813997,101,38577,1),(317740,813998,953227,101,139330,1),(1,813998,953227,101,139330,1);

CREATE TABLE t2 (
  id int(10) unsigned NOT NULL default '0',
  contig_id int(10) unsigned NOT NULL default '0',
  seq_start int(10) NOT NULL default '0',
  seq_end int(10) NOT NULL default '0',
  strand tinyint(2) NOT NULL default '0',
  KEY id (id)
);
INSERT INTO t2 VALUES (133195,469713,61327,61384,1),(133196,469713,64113,64387,1),(133197,1,1,1,0),(133197,1,1,1,-2);
SELECT e.id,
   MIN( IF(sgp.raw_ori=1,
          (e.seq_start+sgp.chr_start-sgp.raw_start),  
          (sgp.chr_start+sgp.raw_end-e.seq_end))) as start, 
   MAX( IF(sgp.raw_ori=1,
           (e.seq_end+sgp.chr_start-sgp.raw_start),  
           (sgp.chr_start+sgp.raw_end-e.seq_start))) as end, 
   AVG(IF (sgp.raw_ori=1,e.strand,(-e.strand))) as chr_strand 
FROM  t1 sgp,
      t2 e  
WHERE sgp.raw_id=e.contig_id 
GROUP BY e.id 
HAVING chr_strand= -1 and end >= 0 
  AND start <= 999660;
drop table t1,t2;

#
# Test problem with having and MAX() IS NOT NULL
#

CREATE TABLE t1 (Fld1 int(11) default NULL,Fld2 int(11) default NULL);
INSERT INTO t1 VALUES (1,10),(1,20),(2,NULL),(2,NULL),(3,50);
select Fld1, max(Fld2) as q from t1 group by Fld1 having q is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having max(Fld2) is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having avg(Fld2) is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having std(Fld2) is not null;
select Fld1, max(Fld2) from t1 group by Fld1 having variance(Fld2) is not null;
drop table t1;

#
# Test problem with count(distinct) in having
#
create table t1 (id int not null, qty int not null);
insert into t1 values (1,2),(1,3),(2,4),(2,5);
select id, sum(qty) as sqty from t1 group by id having sqty>2;
select sum(qty) as sqty from t1 group by id having count(id) > 0;
select sum(qty) as sqty from t1 group by id having count(distinct id) > 0;
drop table t1;

#
# Test case for Bug #4358 Problem with HAVING clause that uses alias from the
#              select list and TEXT field 
#

CREATE TABLE t1 (
  `id` bigint(20) NOT NULL default '0',
  `description` text
) ENGINE=MyISAM;

CREATE TABLE t2 (
  `id` bigint(20) NOT NULL default '0',
  `description` varchar(20)
) ENGINE=MyISAM;

INSERT INTO t1  VALUES (1, 'test');
INSERT INTO t2 VALUES (1, 'test');

CREATE TABLE t3 (
  `id`       bigint(20) NOT NULL default '0',
  `order_id` bigint(20) NOT NULL default '0'
) ENGINE=MyISAM;

select
	a.id, a.description,
	count(b.id) as c 
from t1 a left join t3 b on a.id=b.order_id 
group by a.id, a.description 
having (a.description is not null) and (c=0);

select
	a.*, 
	count(b.id) as c 
from t2 a left join t3 b on a.id=b.order_id 
group by a.id, a.description
having (a.description is not null) and (c=0);

INSERT INTO t1  VALUES (2, 'test2');

select
	a.id, a.description,
	count(b.id) as c 
from t1 a left join t3 b on a.id=b.order_id 
group by a.id, a.description 
having (a.description is not null) and (c=0);
drop table t1,t2,t3;

#
# Bug #14274: HAVING clause containing only set function
#

CREATE TABLE t1 (a int);
INSERT INTO t1 VALUES (3), (4), (1), (3), (1);

SELECT SUM(a) FROM t1 GROUP BY a HAVING SUM(a)>0;
SELECT SUM(a) FROM t1 GROUP BY a HAVING SUM(a);

DROP TABLE t1;

# End of 4.1 tests