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# test of problems with having (Reported by Mark Rogers)
#
drop table if exists t1;
create table t1 (a int);
select count(a) as b from t1 where a=0 having b > 0;
insert into t1 values (null);
select count(a) as b from t1 where a=0 having b > 0;
select count(a) as b from t1 where a=0 having b >=0;
drop table t1;
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