path: root/mysql-test/t/table_elim.test

#
# Table elimination (MWL#17) tests
#
--disable_warnings
drop table if exists t0, t1, t2, t3;
drop view if exists v1, v2;
--enable_warnings

create table t1 (a int);
insert into t1 values (0),(1),(2),(3);
create table t0 as select * from t1;

create table t2 (a int primary key, b int) 
  as select a, a as b from t1 where a in (1,2);

create table t3 (a int primary key, b int) 
  as select a, a as b from t1 where a in (1,3);

--echo # This will be  eliminated:
explain select t1.a from t1 left join t2 on t2.a=t1.a;
explain extended select t1.a from t1 left join t2 on t2.a=t1.a;

select t1.a from t1 left join t2 on t2.a=t1.a;

--echo # This will not be eliminated as t2.b is in in select list:
explain select * from t1 left join t2 on t2.a=t1.a;

--echo # This will not be eliminated as t2.b is in in order list:
explain select t1.a from t1 left join t2 on t2.a=t1.a order by t2.b;

--echo # This will not be eliminated as t2.b is in group list:
explain select t1.a from t1 left join t2 on t2.a=t1.a group by t2.b;

--echo # This will not be eliminated as t2.b is in the WHERE
explain select t1.a from t1 left join t2 on t2.a=t1.a where t2.b < 3 or t2.b is null;

--echo # Elimination of multiple tables:
explain select t1.a from t1 left join (t2 join t3) on t2.a=t1.a and t3.a=t1.a;

--echo # Elimination of multiple tables (2):
explain select t1.a from t1 left join (t2 join t3 on t2.b=t3.b) on t2.a=t1.a and t3.a=t1.a;

--echo # Elimination when done within an outer join nest:
explain extended
select t0.*
from
  t0 left join (t1 left join (t2 join t3 on t2.b=t3.b) on t2.a=t1.a and
  t3.a=t1.a) on t0.a=t1.a;

--echo # Elimination with aggregate functions
explain select count(*) from t1 left join t2 on t2.a=t1.a;
explain select count(1) from t1 left join t2 on t2.a=t1.a;
explain select count(1) from t1 left join t2 on t2.a=t1.a group by t1.a;

--echo This must not use elimination:
explain select count(1) from t1 left join t2 on t2.a=t1.a group by t2.a;

drop table t0, t1, t2, t3;

# This will stand for elim_facts
create table t0 ( id integer, primary key (id));

# Attribute1, non-versioned
create table t1 (
  id integer,
  attr1 integer,
  primary key (id),
  key (attr1)
);

# Attribute2, time-versioned
create table t2 (
  id integer,
  attr2 integer,
  fromdate date,
  primary key (id, fromdate),
  key (attr2,fromdate)
);

insert into t0 values (0),(1),(2),(3),(4),(5),(6),(7),(8),(9);
insert into t0 select A.id + 10*B.id from t0 A, t0 B where B.id > 0;

insert into t1 select id, id from t0;
insert into t2 select id, id, date_add('2009-06-22', interval id day) from t0;
insert into t2 select id, id+1, date_add('2008-06-22', interval id day) from t0;

create view v1 as
select 
  f.id, a1.attr1, a2.attr2
from 
  t0 f 
  left join t1 a1 on a1.id=f.id
  left join t2 a2 on a2.id=f.id and 
                     a2.fromdate=(select MAX(fromdate) from
                                  t2 where id=a2.id);
create view v2 as
select 
  f.id, a1.attr1, a2.attr2
from 
  t0 f 
  left join t1 a1 on a1.id=f.id
  left join t2 a2 on a2.id=f.id and 
                     a2.fromdate=(select MAX(fromdate) from
                                  t2 where id=f.id);

--echo This should use one table:
explain select id from v1 where id=2;
--echo This should use one table:
explain extended select id from v1 where id in (1,2,3,4);
--echo This should use facts and a1 tables:
explain extended select id from v1 where attr1 between 12 and 14;
--echo This should use facts, a2 and its subquery:
explain extended select id from v1 where attr2 between 12 and 14;

# Repeat for v2: 

--echo This should use one table:
explain select id from v2 where id=2;
--echo This should use one table:
explain extended select id from v2 where id in (1,2,3,4);
--echo This should use facts and a1 tables:
explain extended select id from v2 where attr1 between 12 and 14;
--echo This should use facts, a2 and its subquery:
explain extended select id from v2 where attr2 between 12 and 14;

drop view v1, v2;
drop table t0, t1, t2;

#
# Tests for the code that uses t.keypartX=func(t.keypartY) equalities to
# make table elimination inferences
#
create table t1 (a int);
insert into t1 values (0),(1),(2),(3);

create table t2 (pk1 int, pk2 int, pk3 int, col int, primary key(pk1, pk2, pk3));
insert into t2 select a,a,a,a from t1;

--echo This must use only t1:
explain select t1.* from t1 left join t2 on t2.pk1=t1.a and 
                                            t2.pk2=t2.pk1+1 and
                                            t2.pk3=t2.pk2+1;

--echo This must use only t1:
explain select t1.* from t1 left join t2 on t2.pk1=t1.a and 
                                            t2.pk3=t2.pk1+1 and
                                            t2.pk2=t2.pk3+1;

--echo This must use both:
explain select t1.* from t1 left join t2 on t2.pk1=t1.a and 
                                            t2.pk3=t2.pk1+1 and
                                            t2.pk2=t2.pk3+t2.col;

--echo This must use only t1:
explain select t1.* from t1 left join t2 on t2.pk2=t1.a and 
                                            t2.pk1=t2.pk2+1 and
                                            t2.pk3=t2.pk1;

drop table t1, t2;
#
# Check that equality propagation is taken into account
#
create table t1 (pk int primary key, col int);
insert into t1 values (1,1),(2,2);

create table t2 like t1;
insert into t2 select * from t1;

create table t3 like t1;
insert into t3 select * from t1;

explain 
select t1.* from t1 left join ( t2 left join t3 on t3.pk=t2.col) on t2.col=t1.col;

explain 
select t1.*, t2.* from t1 left join (t2 left join t3 on t3.pk=t2.col) on t2.pk=t1.col;

explain select t1.* 
from 
  t1 left join ( t2 left join t3 on t3.pk=t2.col or t3.pk=t2.col) 
  on t2.col=t1.col or t2.col=t1.col;

explain select t1.*, t2.* 
from 
  t1 left join 
  (t2 left join t3 on t3.pk=t2.col or t3.pk=t2.col) 
  on t2.pk=t1.col or t2.pk=t1.col;

drop table t1, t2, t3;

--echo # 
--echo # Check things that look like functional dependencies but really are not
--echo # 

create table t1 (a char(10) character set latin1 collate latin1_general_ci primary key);
insert into t1 values ('foo');
insert into t1 values ('bar');

create table t2 (a char(10) character set latin1 collate latin1_general_cs primary key);
insert into t2 values ('foo');
insert into t2 values ('FOO');

-- echo this must not use table elimination:
explain select t1.* from t1 left join t2 on t2.a='foo' collate latin1_general_ci; 

-- echo this must not use table elimination:
explain select t1.* from t1 left join t2 on t2.a=t1.a collate latin1_general_ci; 
drop table t1,t2;

create table t1 (a int primary key);
insert into t1 values (1),(2);
create table t2 (a char(10) primary key);
insert into t2 values ('1'),('1.0');
-- echo this must not use table elimination:
explain select t1.* from t1 left join t2 on t2.a=1;
-- echo this must not use table elimination:
explain select t1.* from t1 left join t2 on t2.a=t1.a;

drop table t1, t2;
# partial unique keys do not work at the moment, although they are able to
# provide one-match guarantees:
create table t1 (a char(10) primary key);
insert into t1 values ('foo'),('bar');

create table t2 (a char(10), unique key(a(2)));
insert into t2 values ('foo'),('bar');

explain select t1.* from t1 left join t2 on t2.a=t1.a;

drop table t1, t2;

--echo #
--echo # check UPDATE/DELETE that look like they could be eliminated
--echo #
create table t1 (a int primary key, b int);
insert into t1 values (1,1),(2,2),(3,3);

create table t2 like t1;
insert into t2 select * from t1;
update t1 left join t2 using (a) set t2.a=t2.a+100;
select * from t1;
select * from t2;

delete from t2;
insert into t2 select * from t1;

delete t2 from t1 left join t2 using (a);
select * from t1;
select * from t2;
drop table t1, t2;

--echo #
--echo # Tests with various edge-case ON expressions
--echo #
create table t1 (a int, b int, c int, d int);
insert into t1 values (0,0,0,0),(1,1,1,1),(2,2,2,2),(3,3,3,3);

create table t2 (pk int primary key, b int) 
  as select a as pk, a as b from t1 where a in (1,2);

create table t3 (pk1 int, pk2 int, b int, unique(pk1,pk2));
insert into t3 select a as pk1, a as pk2, a as b from t1 where a in (1,3);

explain select t1.a from t1 left join t2 on t2.pk=t1.a and t2.b<t1.b;
explain select t1.a from t1 left join t2 on t2.pk=t1.a or t2.b<t1.b;
explain select t1.a from t1 left join t2 on t2.b<t1.b or t2.pk=t1.a;

explain select t1.a from t1 left join t2 on t2.pk between 10 and 20;
explain select t1.a from t1 left join t2 on t2.pk between 0.5 and 1.5;
explain select t1.a from t1 left join t2 on t2.pk between 10 and 10;

explain select t1.a from t1 left join t2 on t2.pk in (10);
explain select t1.a from t1 left join t2 on t2.pk in (t1.a);

explain select t1.a from t1 left join t2 on TRUE;

explain select t1.a from t1 left join t3 on t3.pk1=t1.a and t3.pk2 IS NULL;

drop table t1,t2,t3;

--echo #
--echo # Multi-equality tests 
--echo #
create table t1 (a int, b int, c int, d int);
insert into t1 values (0,0,0,0),(1,1,1,1),(2,2,2,2),(3,3,3,3);

create table t2 (pk int primary key, b int, c int);
insert into t2 select a,a,a from t1 where a in (1,2);

explain 
select t1.* 
from t1 left join t2 on t2.pk=t2.c and t2.b=t1.a and t1.a=t1.b and t2.c=t2.b
where t1.d=1;

explain 
select t1.* 
from 
    t1 
  left join 
    t2 
  on (t2.pk=t2.c and t2.b=t1.a and t1.a=t1.b and t2.c=t2.b) or
     (t2.pk=t2.c and t2.b=t1.a and t1.a=t1.b and t2.c=t2.b) 
where t1.d=1;

--echo #This can't be eliminated:
explain 
select t1.* 
from 
    t1 
  left join 
    t2 
  on (t2.pk=t2.c and t2.b=t1.a and               t2.c=t1.b) or
     (t2.pk=t2.c and               t1.a=t1.b and t2.c=t1.b) 
where t1.d=1;

explain 
select t1.* 
from 
    t1 
  left join 
    t2 
  on (t2.pk=t2.c and t2.b=t1.a and t2.c=t1.b) or
     (t2.pk=t2.c and               t2.c=t1.b) 
;

explain 
select t1.* 
from t1 left join t2 on t2.pk=3 or t2.pk= 4;

explain 
select t1.* 
from t1 left join t2 on t2.pk=3 or t2.pk= 3;

explain 
select t1.* 
from t1 left join t2 on (t2.pk=3 and t2.b=3) or (t2.pk= 4 and t2.b=3);

drop table t1, t2;