blob: 9811801545690fe4817bb74f9fce16c4f22d1177 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
|
/* Copyright (C) 2000 MySQL AB
This program is free software; you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; version 2 of the License.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program; if not, write to the Free Software
Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA */
/*
Author : David
strintstr(src, from, pat) looks for an instance of pat in src
backwards from pos from. pat is not a regex(3) pattern, it is a literal
string which must be matched exactly.
The result 0 if the pattern was not found else it is the start char of
the pattern counted from the begining of the string.
*/
#include <my_global.h>
#include "m_string.h"
uint r_strinstr(reg1 my_string str,int from, reg4 my_string search)
{
reg2 my_string i, j;
uint len = (uint) strlen(search);
/* pointer to the last char of buff */
my_string start = str + from - 1;
/* pointer to the last char of search */
my_string search_end = search + len - 1;
skip:
while (start >= str) /* Cant be != because the first char */
{
if (*start-- == *search_end)
{
i = start; j = search_end - 1;
while (j >= search && start > str)
if (*i-- != *j--)
goto skip;
return (uint) ((start - len) - str + 3);
}
}
return (0);
}
|
