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o = "xxxxxxxxxxxxxxxxxxx";
o = o + o;
o + o;
o = o + o;
o = o + o;
o = o + o;
var B = 40000;
var last = new Date();
for (i = 0; i < 30000000; i++) {
db.foo.insert({ o: o });
if (i % B == 0) {
var n = new Date();
print(i);
print("per sec: " + B*1000 / (n - last));
last = n;
}
}
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