Re: [perl #46011] overload "0+" doesn't handle integer results

Message-ID: <20071007042214.GH29047@bort.ca>

p4raw-id: //depot/perl@32059

1 files changed, 26 insertions, 1 deletions

diff --git a/lib/overload.t b/lib/overload.t
index 34b4521db5..9b1792328b 100644
--- a/lib/overload.t
+++ b/lib/overload.t
@@ -47,7 +47,7 @@ sub numify { 0 + "${$_[0]}" }	# Not needed, additional overhead
 package main;
 
 $| = 1;
-use Test::More tests => 528;
+use Test::More tests => 535;
 
 
 $a = new Oscalar "087";
@@ -1375,3 +1375,28 @@ foreach my $op (qw(<=> == != < <= > >=)) {
     is("$wham_eth", $string);
     is ($crunch_eth->Pie("Blackbird"), "$string, Blackbird");
 }
+
+{
+    package numify_int;
+    use overload "0+" => sub { $_[0][0] += 1; 42 };
+    package numify_self;
+    use overload "0+" => sub { $_[0][0]++; $_[0] };
+    package numify_other;
+    use overload "0+" => sub { $_[0][0]++; $_[0][1] = bless [], 'numify_int' };
+
+    package main;
+    my $o = bless [], 'numify_int';
+    is(int($o), 42, 'numifies to integer');
+    is($o->[0], 1, 'int() numifies only once');
+
+    my $aref = [];
+    my $num_val = 0 + $aref;
+    my $r = bless $aref, 'numify_self';
+    is(int($r), $num_val, 'numifies to self');
+    is($r->[0], 1, 'int() numifies once when returning self');
+
+    my $s = bless [], 'numify_other';
+    is(int($s), 42, 'numifies to numification of other object');
+    is($s->[0], 1, 'int() numifies once when returning other object');
+    is($s->[1][0], 1, 'returned object numifies too');
+}