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author | Karl Williamson <public@khwilliamson.com> | 2012-01-05 15:27:35 -0700 |
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committer | Karl Williamson <public@khwilliamson.com> | 2012-01-13 09:58:38 -0700 |
commit | 9fef6a0d04f0ff51fd6182e37d56e3439312a445 (patch) | |
tree | 671bb084690f378babb606b9901d9eba94554ca7 /pod/perlop.pod | |
parent | ba05a734abc139486481541de5692c30c0ec39e4 (diff) | |
download | perl-9fef6a0d04f0ff51fd6182e37d56e3439312a445.tar.gz |
perlop: Typos, too long lines, corrections
Diffstat (limited to 'pod/perlop.pod')
-rw-r--r-- | pod/perlop.pod | 12 |
1 files changed, 6 insertions, 6 deletions
diff --git a/pod/perlop.pod b/pod/perlop.pod index 80add657e2..607f631d45 100644 --- a/pod/perlop.pod +++ b/pod/perlop.pod @@ -1421,7 +1421,7 @@ sequences mean on both ASCII and EBCDIC platforms. Use of any other character following the "c" besides those listed above is discouraged, and some are deprecated with the intention of removing -those in Perl 5.16. What happens for any of these +those in a later Perl version. What happens for any of these other characters currently though, is that the value is derived by xor'ing with the seventh bit, which is 64. @@ -1450,7 +1450,7 @@ see L<perlrebackslash/Octal escapes>.) Starting in Perl 5.14, you may use C<\o{}> instead, which avoids all these problems. Otherwise, it is best to use this construct only for ordinals C<\077> and below, remembering to pad to the left with zeros to make three digits. For larger ordinals, either use -C<\o{}> , or convert to something else, such as to hex and use C<\x{}> +C<\o{}>, or convert to something else, such as to hex and use C<\x{}> instead. Having fewer than 3 digits may lead to a misleading warning message that says @@ -1475,10 +1475,10 @@ character set encoding. In ASCII the character in the 80th position (indexed from 0) is the letter "P", and in EBCDIC it is the ampersand symbol "&". C<\x{100}> and C<\o{400}> are both 256 in decimal, so the number is interpreted as a Unicode code point no matter what the native encoding is. The name of the -character in the 100th position (indexed by 0) in Unicode is +character in the 256th position (indexed by 0) in Unicode is C<LATIN CAPITAL LETTER A WITH MACRON>. -There are a couple of exceptions to the above rule. C<\N{U+I<hex number>}> is +There are a couple of exceptions to the above rule. S<C<\N{U+I<hex number>}>> is always interpreted as a Unicode code point, so that C<\N{U+0050}> is "P" even on EBCDIC platforms. And if L<C<S<use encoding>>|encoding> is in effect, the number is considered to be in that encoding, and is translated from that into @@ -1506,8 +1506,8 @@ X<\l> X<\u> X<\L> X<\U> X<\E> X<\Q> C<\L>, C<\U>, and C<\Q> can stack, in which case you need one C<\E> for each. For example: - say "This \Qquoting \ubusiness \Uhere isn't quite\E done yet,\E is it?"; - This quoting\ Business\ HERE\ ISN\'T\ QUITE\ done\ yet\, is it? + say"This \Qquoting \ubusiness \Uhere isn't quite\E done yet,\E is it?"; + This quoting\ Business\ HERE\ ISN\'T\ QUITE\ done\ yet\, is it? If C<use locale> is in effect, the case map used by C<\l>, C<\L>, C<\u>, and C<\U> is taken from the current locale. See L<perllocale>. |