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author | David Mitchell <davem@iabyn.com> | 2010-03-25 10:56:35 +0000 |
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committer | David Mitchell <davem@iabyn.com> | 2010-03-25 10:56:35 +0000 |
commit | 447ee1343739cf8e34c4ff1ba9b30eae75c3f1ab (patch) | |
tree | b713c83f9510652e10e27b68b31c2a0d45e49149 /utils | |
parent | fd69380d5d5b95ef16e2521cf4251b34ee0ce151 (diff) | |
download | perl-447ee1343739cf8e34c4ff1ba9b30eae75c3f1ab.tar.gz |
RT #67962: $1 treated as tainted in untainted match
Fix the issue in the following:
use re 'taint';
$tainted =~ /(...)/;
# $1 now correctly tainted
$untainted =~ s/(...)/$1/;
# $untainted now incorrectly tainted
The problem stems from when $1 is updated.
pp_substcont, which is called after the replacement expression has been
evaluated, checks the returned expression for taintedness, and if so,
taints the variable being substituted. For a substitution like
s/(...)/x$1/ this works fine: the expression "x".$1 causes $1's get magic
to be called, which sets $1 based on the recent match, and is marked as
not tainted. Thus the returned expression is untainted. In the variant
s/(...)/$1/, the returned value on the stack is $1 itself, and its get
magic hasn't been called yet. So it still has the tainted flag from the
previous pattern.
The solution is to mg_get the returned expression *before* testing for
taintedness.
Diffstat (limited to 'utils')
0 files changed, 0 insertions, 0 deletions