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|
#!./perl -T
BEGIN {
chdir 't' if -d 't';
@INC = '../lib';
}
use warnings;
use strict;
$|++;
require "./test.pl";
plan(tests => 36);
use vars qw($TODO);
=pod
Even if you have a C<sub q{}>, calling C<q()> will be parsed as the
C<q()> operator. Calling C<&q()> or C<main::q()> gets you the function.
This test verifies this behavior for nine different operators.
=cut
sub m { return "m-".shift }
sub q { return "q-".shift }
sub qq { return "qq-".shift }
sub qr { return "qr-".shift }
sub qw { return "qw-".shift }
sub qx { return "qx-".shift }
sub s { return "s-".shift }
sub tr { return "tr-".shift }
sub y { return "y-".shift }
# m operator
can_ok( 'main', "m" );
SILENCE_WARNING: { # Complains because $_ is undef
no warnings;
isnt( m('unqualified'), "m-unqualified", "m('unqualified') is oper" );
}
is( main::m('main'), "m-main", "main::m() is func" );
is( &m('amper'), "m-amper", "&m() is func" );
# q operator
can_ok( 'main', "q" );
isnt( q('unqualified'), "q-unqualified", "q('unqualified') is oper" );
is( main::q('main'), "q-main", "main::q() is func" );
is( &q('amper'), "q-amper", "&q() is func" );
# qq operator
can_ok( 'main', "qq" );
isnt( qq('unqualified'), "qq-unqualified", "qq('unqualified') is oper" );
is( main::qq('main'), "qq-main", "main::qq() is func" );
is( &qq('amper'), "qq-amper", "&qq() is func" );
# qr operator
can_ok( 'main', "qr" );
isnt( qr('unqualified'), "qr-unqualified", "qr('unqualified') is oper" );
is( main::qr('main'), "qr-main", "main::qr() is func" );
is( &qr('amper'), "qr-amper", "&qr() is func" );
# qw operator
can_ok( 'main', "qw" );
isnt( qw('unqualified'), "qw-unqualified", "qw('unqualified') is oper" );
is( main::qw('main'), "qw-main", "main::qw() is func" );
is( &qw('amper'), "qw-amper", "&qw() is func" );
# qx operator
can_ok( 'main', "qx" );
eval "qx('unqualified'".
($^O eq 'MSWin32' ? " 2>&1)" : ")");
SKIP: {
skip("external command not portable on VMS", 1) if $^O eq 'VMS';
TODO: {
local $TODO = $^O eq 'MSWin32' ? "Tainting of PATH not working of Windows" : $TODO;
like( $@, qr/^Insecure/, "qx('unqualified') doesn't work" );
}
}
is( main::qx('main'), "qx-main", "main::qx() is func" );
is( &qx('amper'), "qx-amper", "&qx() is func" );
# s operator
can_ok( 'main', "s" );
eval "s('unqualified')";
like( $@, qr/^Substitution replacement not terminated/, "s('unqualified') doesn't work" );
is( main::s('main'), "s-main", "main::s() is func" );
is( &s('amper'), "s-amper", "&s() is func" );
# tr operator
can_ok( 'main', "tr" );
eval "tr('unqualified')";
like( $@, qr/^Transliteration replacement not terminated/, "tr('unqualified') doesn't work" );
is( main::tr('main'), "tr-main", "main::tr() is func" );
is( &tr('amper'), "tr-amper", "&tr() is func" );
# y operator
can_ok( 'main', "y" );
eval "y('unqualified')";
like( $@, qr/^Transliteration replacement not terminated/, "y('unqualified') doesn't work" );
is( main::y('main'), "y-main", "main::y() is func" );
is( &y('amper'), "y-amper", "&y() is func" );
=pod
from irc://irc.perl.org/p5p 2004/08/12
<kane-xs> bug or feature?
<purl> You decide!!!!
<kane-xs> [kane@coke ~]$ perlc -le'sub y{1};y(1)'
<kane-xs> Transliteration replacement not terminated at -e line 1.
<Nicholas> bug I think
<kane-xs> i'll perlbug
<rgs> feature
<kane-xs> smiles at rgs
<kane-xs> done
<rgs> will be closed at not a bug,
<rgs> like the previous reports of this one
<Nicholas> feature being first class and second class keywords?
<rgs> you have similar ones with q, qq, qr, qx, tr, s and m
<rgs> one could say 1st class keywords, yes
<rgs> and I forgot qw
<kane-xs> hmm silly...
<Nicholas> it's acutally operators, isn't it?
<Nicholas> as in you can't call a subroutine with the same name as an
operator unless you have the & ?
<kane-xs> or fqpn (fully qualified package name)
<kane-xs> main::y() works just fine
<kane-xs> as does &y; but not y()
<Andy> If that's a feature, then let's write a test that it continues
to work like that.
=cut
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