Coverage for cogapp\whiteutils: 92%

From a02f2441a87e433f06c827712060ddba4f5dfa53 Mon Sep 17 00:00:00 2001 From: Ned Batchelder Date: Fri, 23 Sep 2011 08:23:58 -0400 Subject: Latest sample output. --- doc/sample_html/cogapp_whiteutils.html | 418 ++++++++++++++++----------------- 1 file changed, 209 insertions(+), 209 deletions(-) (limited to 'doc/sample_html/cogapp_whiteutils.html') diff --git a/doc/sample_html/cogapp_whiteutils.html b/doc/sample_html/cogapp_whiteutils.html index 2a12461..a7ee966 100644 --- a/doc/sample_html/cogapp_whiteutils.html +++ b/doc/sample_html/cogapp_whiteutils.html @@ -1,209 +1,209 @@ - - - - - - - - Coverage for cogapp\whiteutils: 92% - - - - - - - - - - - -

Hot-keys on this page

- r - m - x - p toggle line displays -

- j - k next/prev highlighted chunk -

- 0 (zero) top of page -

- 1 (one) first highlighted chunk -

- -

- - - - - -

- -

""" Indentation utilities for Cog.

http://nedbatchelder.com/code/cog

"""

import re

def whitePrefix(strings):

""" Determine the whitespace prefix common to all non-blank lines

in the argument list.

"""

# Remove all blank lines from the list

strings = [s for s in strings if s.strip() != '']

if not strings: return ''

# Find initial whitespace chunk in the first line.

# This is the best prefix we can hope for.

prefix = re.match(r'\s*', strings[0]).group(0)

# Loop over the other strings, keeping only as much of

# the prefix as matches each string.

for s in strings:

for i in range(len(prefix)):

27 if prefix[i] != s[i]:

prefix = prefix[:i]

break

return prefix

def reindentBlock(lines, newIndent=''):

""" Take a block of text as a string or list of lines.

Remove any common whitespace indentation.

Re-indent using newIndent, and return it as a single string.

"""

if isinstance(lines, basestring):

lines = lines.split('\n')

oldIndent = whitePrefix(lines)

outLines = []

for l in lines:

if oldIndent:

l = l.replace(oldIndent, '', 1)

if l and newIndent:

l = newIndent + l

outLines.append(l)

return '\n'.join(outLines)

def commonPrefix(strings):

""" Find the longest string that is a prefix of all the strings.

"""

52 if not strings:

return ''

prefix = strings[0]

for s in strings:

if len(s) < len(prefix):

prefix = prefix[:len(s)]

if not prefix:

return ''

for i in range(len(prefix)):

if prefix[i] != s[i]:

prefix = prefix[:i]

break

return prefix

- -

- - - - - + + + + + + + + Coverage for cogapp\whiteutils: 92% + + + + + + + + + + + +

Hot-keys on this page

+ r + m + x + p toggle line displays +

+ j + k next/prev highlighted chunk +

+ 0 (zero) top of page +

+ 1 (one) first highlighted chunk +

+ +

+ + + + + +

+ +

""" Indentation utilities for Cog.

http://nedbatchelder.com/code/cog

"""

import re

def whitePrefix(strings):

""" Determine the whitespace prefix common to all non-blank lines

in the argument list.

"""

# Remove all blank lines from the list

strings = [s for s in strings if s.strip() != '']

if not strings: return ''

# Find initial whitespace chunk in the first line.

# This is the best prefix we can hope for.

prefix = re.match(r'\s*', strings[0]).group(0)

# Loop over the other strings, keeping only as much of

# the prefix as matches each string.

for s in strings:

for i in range(len(prefix)):

27 if prefix[i] != s[i]:

prefix = prefix[:i]

break

return prefix

def reindentBlock(lines, newIndent=''):

""" Take a block of text as a string or list of lines.

Remove any common whitespace indentation.

Re-indent using newIndent, and return it as a single string.

"""

if isinstance(lines, basestring):

lines = lines.split('\n')

oldIndent = whitePrefix(lines)

outLines = []

for l in lines:

if oldIndent:

l = l.replace(oldIndent, '', 1)

if l and newIndent:

l = newIndent + l

outLines.append(l)

return '\n'.join(outLines)

def commonPrefix(strings):

""" Find the longest string that is a prefix of all the strings.

"""

52 if not strings:

return ''

prefix = strings[0]

for s in strings:

if len(s) < len(prefix):

prefix = prefix[:len(s)]

if not prefix:

return ''

for i in range(len(prefix)):

if prefix[i] != s[i]:

prefix = prefix[:i]

break

return prefix

+ +

+ + + + + -- cgit v1.2.1

Coverage for cogapp\whiteutils : - 92% -

- 37 statements - 34 run - 3 missing - 0 excluded - - 2 partial - -

Coverage for cogapp\whiteutils : + 92% +

+ 37 statements + 34 run + 3 missing + 0 excluded + + 2 partial + +