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+ <H1>[pycrypto] PyCrypto AND Crypt_RSA integration</H1>
+ <B>Mads Kiilerich</B>
+ <A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=%5Bpycrypto%5D%20PyCrypto%20AND%20Crypt_RSA%20integration&In-Reply-To=3c5f192d0902061053o4c00c796k8a440b9f62b4efb7%40mail.gmail.com"
+ TITLE="[pycrypto] PyCrypto AND Crypt_RSA integration">mads at kiilerich.com
+ </A><BR>
+ <I>Fri Feb 6 18:56:50 CST 2009</I>
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+<PRE>Mauricio Arozi wrote, On 02/06/2009 07:53 PM:
+&gt;<i> Hello,
+</I>&gt;<i> I'm trying to import/export keys from/to Crypt_RSA
+</I>&gt;<i> &lt;<A HREF="http://pear.php.net/package/Crypt_RSA">http://pear.php.net/package/Crypt_RSA</A>&gt;, using PyCrypto
+</I>&gt;<i> &lt;<A HREF="http://www.dlitz.net/software/pycrypto/">http://www.dlitz.net/software/pycrypto/</A>&gt;. My problem is that while
+</I>&gt;<i> using PyCrypto to generate both public and private keys, the
+</I>&gt;<i> e(exponent?) is always the same.
+</I>&gt;<i> According to this site: <A HREF="http://pajhome.org.uk/crypt/rsa/rsa.html,">http://pajhome.org.uk/crypt/rsa/rsa.html,</A> and
+</I>&gt;<i> yet others, the e(exponent?) is used for the public key, and d for the
+</I>&gt;<i> private key.
+</I>
+Yes, many implementations and applications of RSA uses a fixed exponent
+- very often 65537 (F4). Usually that is a good decision and no problem
+- perhaps except for interoperability.
+
+And yes, interoperability is often very hard when implementing crypto
+stuff. IMHO an important criteria when selecting a crypto library is
+having examples / proof of how it interoperates with other implementations.
+
+It is not clear to me exactly what you are asking for, so I can't answer
+that directly - I hope someone else can do that.
+
+/Mads
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