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+ <H1>[pycrypto] same RSA.construct fails on OSX</H1>
+ <B>Legrandin</B>
+ <A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=Re%3A%20%5Bpycrypto%5D%20same%20RSA.construct%20fails%20on%20OSX&In-Reply-To=%3CCAGfyce0Q%3DDtQscTAFLD7kqj3DX4DD9HOKksA7tsYDdsArWTATg%40mail.gmail.com%3E"
+ TITLE="[pycrypto] same RSA.construct fails on OSX">gooksankoo at hoiptorrow.mailexpire.com
+ </A><BR>
+ <I>Fri Jan 20 10:22:50 EST 2012</I>
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+<PRE>Hi Antoine,
+
+&gt;<i> I've just found that simply removing p (or 'd' as it should be called..)
+</I>&gt;<i> is enough to fix it, so the code becomes:
+</I>&gt;<i> if d==0:
+</I>&gt;<i> &#160;k = RSA.construct((long(m), long(e)))
+</I>&gt;<i> else:
+</I>&gt;<i> &#160;k = RSA.construct((long(m), long(e), long(d)))
+</I>
+In the first case you generate a public key no matter which library
+you have installed.
+In the second case you generate a private key, but only if you are on 2.5.
+
+Do you need a public key or a private key?
+
+If you need a public key, just use 2 arguments.
+If you need a private key and you want it to work with all pycrypto
+versions, go and look for the remaining 2 parameters (p and q)... ;-)
+
+&gt;&gt;<i> With previous version you had to provide at least 5 elements,
+</I>&gt;&gt;<i> m+e+d+p+q (I don't recall how they complain if you provide only 3).
+</I>&gt;<i> According to the docs, it's 2 minimum (as above), anyone know if the
+</I>&gt;<i> code above is going to have problems running on distros with old
+</I>&gt;<i> versions of pycrypto?
+</I>
+I would simply assume it will have problem with previous versions:
+it's clearly off spec for them.
+</PRE>
+
+
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