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+ <H1>[pycrypto] Unicode?</H1>

+ Jeremy Gray

+ <A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=Re%3A%20%5Bpycrypto%5D%20Unicode%3F&In-Reply-To=%3CCANqwJFjV2SSsh8Ctvpi3_fDM8ssc%3DitGx%3DiJxP_z%2BuS9%3D7oX4w%40mail.gmail.com%3E"

+ TITLE="[pycrypto] Unicode?">jrgray at gmail.com

+ </A>

+ Mon Feb 3 04:40:14 PST 2014

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+<PRE>I may not understand the constraints of your situation, but wouldn't

+python's "universal newlines" file-open mode achieve what you want? infile

+= open(filename, 'Urb')

+--Jeremy

+On Mon, Feb 3, 2014 at 5:35 AM, Dave Pawson <<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">dave.pawson at gmail.com</A>> wrote:

+> Now resolved.

+> Source plain text is created / modified in either DOS or Linux (np to add

+> Mac)

+>

+> read using

+> chunk = unicode(infile.read(chunksize))

+> # replace newline as appropriate

+> chunk=replaceNL(chunk)

+> # Convert to byte string

+> chunk=safe_str(chunk)

+> encrypt and write to disk

+>

+> # for decrypt

+> #Iterate over file to read into string

+> # replace the individual bytes of the Unicode character (u2022 in my case)

+> # with \n for the local machine

+> retval = replaceBullet(retval)

+>

+> code below

+>

+> #

+> #Swap \n for \u2022

+> #

+> def replaceNL(str):

+> # If DOS, replace \r\x0A

+> # If Unix, replace \n

+> lineEnd=u'\n'

+> if string.find(str,'\r\x0a'):

+> lineEnd=u'\r\x0A'

+> return string.replace(str,lineEnd,u'\u2022')

+>

+> #

+> # Replace bullet by \n

+> #

+> def replaceBullet(bstr):

+> return string.replace(bstr,u'\\u2022',u'\n')

+>

+> def safe_str(obj):

+> """ return the byte string representation of obj """

+> try:

+> return str(obj)

+> except UnicodeEncodeError:

+> # obj is unicode

+> return unicode(obj).encode('unicode_escape')

+>

+> HTH others, though it seems messy, it works.

+>

+> Dave

+>

+> On 3 February 2014 09:39, Dave Pawson <<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">dave.pawson at gmail.com</A>> wrote:

+> > I'm having a problem 'sharing' an encrypted file between

+> > MSDOS and Linux.

+> >

+> > so I thought I'd replace \nl in the plain text with a non ASCII

+> > character prior to encryption.

+> >

+> > encryptor = AES.new(key, AES.MODE_CBC, iv)

+> > outfile.write(encryptor.encrypt(chunk))

+> >

+> > gives me

+> >

+> > File "/usr/lib64/python2.7/site-packages/Crypto/Cipher/blockalgo.py",

+> > line 244, in encrypt

+> > return self._cipher.encrypt(plaintext)

+> > UnicodeEncodeError: 'ascii' codec can't encode character u'\u2022' in

+> > position 34: ordinal not in range(128)

+> >

+> > It would seem I can't use non-ASCII characters, at least with AES, is

+> > this right ?

+> >

+> > If not, how to address it please?

+> >

+> > regards

+> >

+> > --

+> > Dave Pawson

+> > XSLT XSL-FO FAQ.

+> > Docbook FAQ.

+> > <A HREF="http://www.dpawson.co.uk">http://www.dpawson.co.uk</A>

+>

+> --

+> Dave Pawson

+> XSLT XSL-FO FAQ.

+> Docbook FAQ.

+> <A HREF="http://www.dpawson.co.uk">http://www.dpawson.co.uk</A>

+> _______________________________________________

+> pycrypto mailing list

+> <A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">pycrypto at lists.dlitz.net</A>

+> <A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto</A>

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