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<H1>[pycrypto] string XOR</H1>
<B>Dwayne C. Litzenberger</B>
<A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=%5Bpycrypto%5D%20string%20XOR&In-Reply-To=CAMp7mVtANYeMjVfxbsJxhv7vKCHOiJuUzynAniP%2BhD2LGyXFwQ%40mail.gmail.com"
TITLE="[pycrypto] string XOR">dlitz at dlitz.net
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<I>Sat Oct 22 14:23:50 CST 2011</I>
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<PRE>On Fri, Oct 21, 2011 at 03:09:36PM +0100, Richard Moore wrote:
><i>On Fri, Oct 21, 2011 at 2:55 PM, Dean Macinskas
</I>><i><<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">dmacinskas at geobridge.net</A>> wrote:
</I>>><i>     ke = operator.xor(kbpkb,ve)
</I>>><i>
</I>>><i> TypeError: unsupported operand type(s) for ^: 'str' and 'str'
</I>>><i>
</I>>><i> Is there a way to do this in native Python (I'm using 2.7.2), or must I use
</I>>><i> a library of some sort?
</I>><i>
</I>><i>Use ord() to convert each character to a number first, then chr() to
</I>><i>convert the number back to a character.
</I>
Also, if you're using PyCrypto anyway, you can use its fast C
implementation of a byte-wise string XOR:
from Crypto.Util.strxor import strxor
--
Dwayne C. Litzenberger <<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">dlitz at dlitz.net</A>>
OpenPGP: 19E1 1FE8 B3CF F273 ED17 4A24 928C EC13 39C2 5CF7
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