1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
|
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<HTML>
<HEAD>
<TITLE> [pycrypto] same RSA.construct fails on OSX
</TITLE>
<LINK REL="Index" HREF="index.html" >
<LINK REL="made" HREF="mailto:pycrypto%40lists.dlitz.net?Subject=Re%3A%20%5Bpycrypto%5D%20same%20RSA.construct%20fails%20on%20OSX&In-Reply-To=%3CCAGfyce0UFyJNYgfb6mgAnwofsHzoLGTcoFj2JzMBdnTp4Z1qhQ%40mail.gmail.com%3E">
<META NAME="robots" CONTENT="index,nofollow">
<style type="text/css">
pre {
white-space: pre-wrap; /* css-2.1, curent FF, Opera, Safari */
}
</style>
<META http-equiv="Content-Type" content="text/html; charset=us-ascii">
<LINK REL="Previous" HREF="000545.html">
<LINK REL="Next" HREF="000558.html">
</HEAD>
<BODY BGCOLOR="#ffffff">
<H1>[pycrypto] same RSA.construct fails on OSX</H1>
<B>Legrandin</B>
<A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=Re%3A%20%5Bpycrypto%5D%20same%20RSA.construct%20fails%20on%20OSX&In-Reply-To=%3CCAGfyce0UFyJNYgfb6mgAnwofsHzoLGTcoFj2JzMBdnTp4Z1qhQ%40mail.gmail.com%3E"
TITLE="[pycrypto] same RSA.construct fails on OSX">gooksankoo at hoiptorrow.mailexpire.com
</A><BR>
<I>Sun Jan 22 15:55:42 EST 2012</I>
<P><UL>
<LI>Previous message: <A HREF="000545.html">[pycrypto] same RSA.construct fails on OSX
</A></li>
<LI>Next message: <A HREF="000558.html">[pycrypto] autoconf error on Windows
</A></li>
<LI> <B>Messages sorted by:</B>
<a href="date.html#549">[ date ]</a>
<a href="thread.html#549">[ thread ]</a>
<a href="subject.html#549">[ subject ]</a>
<a href="author.html#549">[ author ]</a>
</LI>
</UL>
<HR>
<!--beginarticle-->
<PRE>Hi Antoine,
>><i> Do you need a public key or a private key?
</I>><i> As per above, public if d==0, private otherwise.
</I>
>><i> If you need a private key and you want it to work with all pycrypto
</I>>><i> versions, go and look for the remaining 2 parameters (p and q)... ;-)
</I>
Here I was wrong, I just had a look at the code.
If you pass three arguments, you always build a private key in any
version of pycrypto,
assuming that the third parameter (d) is really the correct private exponent.
p and q are not strictly needed.
If d is zero though, construct() in pycrypto <2.5 will succeed but you
will end with a key which may still be potentially used a private key,
even if it shouldn't.
In other words, sign&decrypt won't fail but their output will be wrong.
The code you came up with:
>>><i> if d==0:
</I>>>><i> k = RSA.construct((long(m), long(e)))
</I>>>><i> else:
</I>>>><i> k = RSA.construct((long(m), long(e), long(d)))
</I>
seems the most correct in your situation.
</PRE>
<!--endarticle-->
<HR>
<P><UL>
<!--threads-->
<LI>Previous message: <A HREF="000545.html">[pycrypto] same RSA.construct fails on OSX
</A></li>
<LI>Next message: <A HREF="000558.html">[pycrypto] autoconf error on Windows
</A></li>
<LI> <B>Messages sorted by:</B>
<a href="date.html#549">[ date ]</a>
<a href="thread.html#549">[ thread ]</a>
<a href="subject.html#549">[ subject ]</a>
<a href="author.html#549">[ author ]</a>
</LI>
</UL>
<hr>
<a href="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">More information about the pycrypto
mailing list</a><br>
</body></html>
|
