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   <H1>[pycrypto] providing signature in base64</H1>
    <B>Cornelius K&#246;lbel</B> 
    <A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=Re%3A%20%5Bpycrypto%5D%20providing%20signature%20in%20base64&In-Reply-To=%3C4FAA9396.9090603%40lsexperts.de%3E"
       TITLE="[pycrypto] providing signature in base64">cornelius.koelbel at lsexperts.de
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    <I>Wed May  9 11:56:06 EDT 2012</I>
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<PRE>Hi,

i discovered the number.bytes_to_long function, which does the trick,

but the signature validation still fails.

I assume I would have to b64decode my signature prior to converting it.
But it fails :-/

ret =  RSAKey.verify(hash, (number.bytes_to_long(sign.decode(&quot;base64&quot;)),) )
print ret

ret =  RSAKey.verify(hash, (number.bytes_to_long(base64.b64decode(sign)),))
print ret

Any hint on that?

The signature was created with openssl/M2Crypto.
And I'd like to mirgate to pycrypto.

Kind regards
Cornelius

Am 09.05.2012 16:28, schrieb Cornelius K&#246;lbel:
&gt;<i> Hello,
</I>&gt;<i>
</I>&gt;<i> I have a signature provided in base64 like this:
</I>&gt;<i>
</I>&gt;<i> XQgVBkxrmJXqN2+xkJx8dGRecadoLi61vjBTsl+kYibji0pf6ZsxYF2ewniV7pIbtjQxxIridBRtLo9d1Rpq6QvjvuVbVzqqimQeFZnQTp9scSfAbKCtDe1F4lEWCLP6s/6op3jgPpmgd0p5kPaA4iWLM5IjleT7kxgniggBXIky1aMq4L8DtLujcfHNLeJyXpw9TDPg/2KEYZGT1WqiXIeIuYPt7UySOVnmgIoQYstu7C5Vsy5hjzBfhpVvKaPjXEDeETL4UoO2S9H+hu0x932HyyiNTYCpY9VFQnptsVtTkkOvEqhY3xxYix4nzeU+vXc4hFFnhAZMJbPYmuPy5w==
</I>&gt;<i>
</I>&gt;<i> but I am breaking my head how to pass this to the verify function.
</I>&gt;<i>
</I>&gt;<i> I create the RSA Object from a PEM encoded public key. This works fine.
</I>&gt;<i>
</I>&gt;<i> But when I try to unpack the base64 encoded signature, I do not get ONE
</I>&gt;<i> long but a tuple with 32 long int.
</I>&gt;<i>
</I>&gt;<i>     long_signature= struct.unpack('Q'*32, sign.decode(&quot;base64&quot;))
</I>&gt;<i>     hash = sha256(licStr).digest()
</I>&gt;<i>     RSAKey = RSA.importKey(public)
</I>&gt;<i>     ret =  RSAKey.verify(hash, long_signature)
</I>&gt;<i>
</I>&gt;<i> I know that this is more a matter of how to handle the unpack function,
</I>&gt;<i> but did not find anything about this.
</I>&gt;<i>
</I>&gt;<i> Thanks a lot and kind regards
</I>&gt;<i> Cornelius
</I>

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