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   <H1>[pycrypto] Compile PyCrypto 2.6 on HP-UX 11.23 ia64 on HP C/aC++	compiler</H1>
    <B>Esmond Poynton</B> 
    <A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=Re%3A%20%5Bpycrypto%5D%20Compile%20PyCrypto%202.6%20on%20HP-UX%2011.23%20ia64%20on%20HP%20C/aC%2B%2B%0A%09compiler&In-Reply-To=%3CCAMSfCAWu39nMOm%2BmvXZgim1wGo6%3DAXkaSseYcPP%2BM1Rx0nrhwQ%40mail.gmail.com%3E"
       TITLE="[pycrypto] Compile PyCrypto 2.6 on HP-UX 11.23 ia64 on HP C/aC++	compiler">esmond.poynton at gmail.com
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    <I>Wed Feb 27 07:23:18 PST 2013</I>
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<PRE>Hello all,

i am looking for some help/hints on compiling on version 2.6 on HPUX 11.23
using the HP C/aC++ compiler.

Compiler info
# B9007AA               C.11.23.16     HP C/aC++ Developer's Bundle
  B9007AA.ACXX.ACXX     C.06.25        HP aC++ Programming Language

Python Info

# python                2.7.3          python
  python.python-INC
  python.python-RUN

Error message is below

<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">root at greopc01</A>:/tmp/pycrypto-2.6&gt;python setup.py build
running build
running build_py
running build_ext
running build_configure
warning: GMP or MPIR library not found; Not building
Crypto.PublicKey._fastmath.
building 'Crypto.Hash._MD2' extension
cc -Ae +Onolimit -I/usr/local/include -I/usr/local/include/ncurses
-I/usr/local/lib/hpux32/libffi-3.0.11/include +z -O3 -fomit-frame-pointer
-Isrc/ -I/usr/local/include/python2.7 -c src/MD2.c -o
build/temp.hp-ux-B.11.23-ia64-2.7/src/MD2.o
cc: warning 901: unknown option: `-fomit-frame-pointer': use +help for
online documentation.
cc -Ae -b -s +Onoprocelim build/temp.hp-ux-B.11.23-ia64-2.7/src/MD2.o
-lpython2.7 -o build/lib.hp-ux-B.11.23-ia64-2.7/Crypto/Hash/_MD2.so
ld: Can't find library for -lpython2.7
Fatal error.
error: command 'cc' failed with exit status 1
<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">root at greopc01</A>:/tmp/pycrypto-2.6&gt;

I am not sure how to resolve this error, if anyone is able to help with
some pointers or hints that would be great.

Esmond
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