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<H1>[pycrypto] Unicode?</H1>
<B>Dave Pawson</B>
<A HREF="mailto:pycrypto%40lists.dlitz.net?Subject=Re%3A%20%5Bpycrypto%5D%20Unicode%3F&In-Reply-To=%3CCAEncD4eja_Su42nR-6QLcM578RBsrF%2BKyNDZ9R_8_s2S%2B7GTvw%40mail.gmail.com%3E"
TITLE="[pycrypto] Unicode?">dave.pawson at gmail.com
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<I>Mon Feb 3 05:21:28 PST 2014</I>
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<PRE><grin/>
Not sure Jeremy! I'd never heard of it.
I'll let you know.... I'm assuming it is 2.x compatible?
regards
On 3 February 2014 12:40, Jeremy Gray <<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">jrgray at gmail.com</A>> wrote:
><i> I may not understand the constraints of your situation, but wouldn't
</I>><i> python's "universal newlines" file-open mode achieve what you want? infile
</I>><i> = open(filename, 'Urb')
</I>><i>
</I>><i> --Jeremy
</I>><i>
</I>><i>
</I>><i> On Mon, Feb 3, 2014 at 5:35 AM, Dave Pawson <<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">dave.pawson at gmail.com</A>> wrote:
</I>>><i>
</I>>><i> Now resolved.
</I>>><i> Source plain text is created / modified in either DOS or Linux (np to add
</I>>><i> Mac)
</I>>><i>
</I>>><i> read using
</I>>><i> chunk = unicode(infile.read(chunksize))
</I>>><i> # replace newline as appropriate
</I>>><i> chunk=replaceNL(chunk)
</I>>><i> # Convert to byte string
</I>>><i> chunk=safe_str(chunk)
</I>>><i> encrypt and write to disk
</I>>><i>
</I>>><i>
</I>>><i> # for decrypt
</I>>><i> #Iterate over file to read into string
</I>>><i> # replace the individual bytes of the Unicode character (u2022 in my case)
</I>>><i> # with \n for the local machine
</I>>><i> retval = replaceBullet(retval)
</I>>><i>
</I>>><i> code below
</I>>><i>
</I>>><i> #
</I>>><i> #Swap \n for \u2022
</I>>><i> #
</I>>><i> def replaceNL(str):
</I>>><i> # If DOS, replace \r\x0A
</I>>><i> # If Unix, replace \n
</I>>><i> lineEnd=u'\n'
</I>>><i> if string.find(str,'\r\x0a'):
</I>>><i> lineEnd=u'\r\x0A'
</I>>><i> return string.replace(str,lineEnd,u'\u2022')
</I>>><i>
</I>>><i> #
</I>>><i> # Replace bullet by \n
</I>>><i> #
</I>>><i> def replaceBullet(bstr):
</I>>><i> return string.replace(bstr,u'\\u2022',u'\n')
</I>>><i>
</I>>><i>
</I>>><i>
</I>>><i> def safe_str(obj):
</I>>><i> """ return the byte string representation of obj """
</I>>><i> try:
</I>>><i> return str(obj)
</I>>><i> except UnicodeEncodeError:
</I>>><i> # obj is unicode
</I>>><i> return unicode(obj).encode('unicode_escape')
</I>>><i>
</I>>><i> HTH others, though it seems messy, it works.
</I>>><i>
</I>>><i> Dave
</I>>><i>
</I>>><i>
</I>>><i> On 3 February 2014 09:39, Dave Pawson <<A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">dave.pawson at gmail.com</A>> wrote:
</I>>><i> > I'm having a problem 'sharing' an encrypted file between
</I>>><i> > MSDOS and Linux.
</I>>><i> >
</I>>><i> > so I thought I'd replace \nl in the plain text with a non ASCII
</I>>><i> > character prior to encryption.
</I>>><i> >
</I>>><i> > encryptor = AES.new(key, AES.MODE_CBC, iv)
</I>>><i> > outfile.write(encryptor.encrypt(chunk))
</I>>><i> >
</I>>><i> > gives me
</I>>><i> >
</I>>><i> > File "/usr/lib64/python2.7/site-packages/Crypto/Cipher/blockalgo.py",
</I>>><i> > line 244, in encrypt
</I>>><i> > return self._cipher.encrypt(plaintext)
</I>>><i> > UnicodeEncodeError: 'ascii' codec can't encode character u'\u2022' in
</I>>><i> > position 34: ordinal not in range(128)
</I>>><i> >
</I>>><i> >
</I>>><i> > It would seem I can't use non-ASCII characters, at least with AES, is
</I>>><i> > this right ?
</I>>><i> >
</I>>><i> > If not, how to address it please?
</I>>><i> >
</I>>><i> >
</I>>><i> > regards
</I>>><i> >
</I>>><i> >
</I>>><i> > --
</I>>><i> > Dave Pawson
</I>>><i> > XSLT XSL-FO FAQ.
</I>>><i> > Docbook FAQ.
</I>>><i> > <A HREF="http://www.dpawson.co.uk">http://www.dpawson.co.uk</A>
</I>>><i>
</I>>><i>
</I>>><i>
</I>>><i> --
</I>>><i> Dave Pawson
</I>>><i> XSLT XSL-FO FAQ.
</I>>><i> Docbook FAQ.
</I>>><i> <A HREF="http://www.dpawson.co.uk">http://www.dpawson.co.uk</A>
</I>>><i> _______________________________________________
</I>>><i> pycrypto mailing list
</I>>><i> <A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">pycrypto at lists.dlitz.net</A>
</I>>><i> <A HREF="http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto">http://lists.dlitz.net/cgi-bin/mailman/listinfo/pycrypto</A>
</I>><i>
</I>><i>
</I>><i>
</I>><i> _______________________________________________
</I>><i> pycrypto mailing list
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</I>><i>
</I>
--
Dave Pawson
XSLT XSL-FO FAQ.
Docbook FAQ.
<A HREF="http://www.dpawson.co.uk">http://www.dpawson.co.uk</A>
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