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+/* $NetBSD: lstConcat.c,v 1.16 2008/12/13 15:19:29 dsl Exp $ */
+
+/*
+ * Copyright (c) 1988, 1989, 1990, 1993
+ * The Regents of the University of California. All rights reserved.
+ *
+ * This code is derived from software contributed to Berkeley by
+ * Adam de Boor.
+ *
+ * Redistribution and use in source and binary forms, with or without
+ * modification, are permitted provided that the following conditions
+ * are met:
+ * 1. Redistributions of source code must retain the above copyright
+ * notice, this list of conditions and the following disclaimer.
+ * 2. Redistributions in binary form must reproduce the above copyright
+ * notice, this list of conditions and the following disclaimer in the
+ * documentation and/or other materials provided with the distribution.
+ * 3. Neither the name of the University nor the names of its contributors
+ * may be used to endorse or promote products derived from this software
+ * without specific prior written permission.
+ *
+ * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
+ * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
+ * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
+ * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
+ * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
+ * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
+ * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
+ * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
+ * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
+ * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
+ * SUCH DAMAGE.
+ */
+
+#ifndef MAKE_NATIVE
+static char rcsid[] = "$NetBSD: lstConcat.c,v 1.16 2008/12/13 15:19:29 dsl Exp $";
+#else
+#include <sys/cdefs.h>
+#ifndef lint
+#if 0
+static char sccsid[] = "@(#)lstConcat.c 8.1 (Berkeley) 6/6/93";
+#else
+__RCSID("$NetBSD: lstConcat.c,v 1.16 2008/12/13 15:19:29 dsl Exp $");
+#endif
+#endif /* not lint */
+#endif
+
+/*-
+ * listConcat.c --
+ * Function to concatentate two lists.
+ */
+
+#include "lstInt.h"
+
+/*-
+ *-----------------------------------------------------------------------
+ * Lst_Concat --
+ * Concatenate two lists. New elements are created to hold the data
+ * elements, if specified, but the elements themselves are not copied.
+ * If the elements should be duplicated to avoid confusion with another
+ * list, the Lst_Duplicate function should be called first.
+ * If LST_CONCLINK is specified, the second list is destroyed since
+ * its pointers have been corrupted and the list is no longer useable.
+ *
+ * Input:
+ * l1 The list to which l2 is to be appended
+ * l2 The list to append to l1
+ * flags LST_CONCNEW if LstNode's should be duplicated
+ * LST_CONCLINK if should just be relinked
+ *
+ * Results:
+ * SUCCESS if all went well. FAILURE otherwise.
+ *
+ * Side Effects:
+ * New elements are created and appended the first list.
+ *-----------------------------------------------------------------------
+ */
+ReturnStatus
+Lst_Concat(Lst l1, Lst l2, int flags)
+{
+ ListNode ln; /* original LstNode */
+ ListNode nln; /* new LstNode */
+ ListNode last; /* the last element in the list. Keeps
+ * bookkeeping until the end */
+ List list1 = l1;
+ List list2 = l2;
+
+ if (!LstValid (l1) || !LstValid (l2)) {
+ return (FAILURE);
+ }
+
+ if (flags == LST_CONCLINK) {
+ if (list2->firstPtr != NULL) {
+ /*
+ * We set the nextPtr of the
+ * last element of list two to be NIL to make the loop easier and
+ * so we don't need an extra case should the first list turn
+ * out to be non-circular -- the final element will already point
+ * to NIL space and the first element will be untouched if it
+ * existed before and will also point to NIL space if it didn't.
+ */
+ list2->lastPtr->nextPtr = NULL;
+ /*
+ * So long as the second list isn't empty, we just link the
+ * first element of the second list to the last element of the
+ * first list. If the first list isn't empty, we then link the
+ * last element of the list to the first element of the second list
+ * The last element of the second list, if it exists, then becomes
+ * the last element of the first list.
+ */
+ list2->firstPtr->prevPtr = list1->lastPtr;
+ if (list1->lastPtr != NULL) {
+ list1->lastPtr->nextPtr = list2->firstPtr;
+ } else {
+ list1->firstPtr = list2->firstPtr;
+ }
+ list1->lastPtr = list2->lastPtr;
+ }
+ if (list1->isCirc && list1->firstPtr != NULL) {
+ /*
+ * If the first list is supposed to be circular and it is (now)
+ * non-empty, we must make sure it's circular by linking the
+ * first element to the last and vice versa
+ */
+ list1->firstPtr->prevPtr = list1->lastPtr;
+ list1->lastPtr->nextPtr = list1->firstPtr;
+ }
+ free(l2);
+ } else if (list2->firstPtr != NULL) {
+ /*
+ * We set the nextPtr of the last element of list 2 to be nil to make
+ * the loop less difficult. The loop simply goes through the entire
+ * second list creating new LstNodes and filling in the nextPtr, and
+ * prevPtr to fit into l1 and its datum field from the
+ * datum field of the corresponding element in l2. The 'last' node
+ * follows the last of the new nodes along until the entire l2 has
+ * been appended. Only then does the bookkeeping catch up with the
+ * changes. During the first iteration of the loop, if 'last' is nil,
+ * the first list must have been empty so the newly-created node is
+ * made the first node of the list.
+ */
+ list2->lastPtr->nextPtr = NULL;
+ for (last = list1->lastPtr, ln = list2->firstPtr;
+ ln != NULL;
+ ln = ln->nextPtr)
+ {
+ PAlloc (nln, ListNode);
+ nln->datum = ln->datum;
+ if (last != NULL) {
+ last->nextPtr = nln;
+ } else {
+ list1->firstPtr = nln;
+ }
+ nln->prevPtr = last;
+ nln->flags = nln->useCount = 0;
+ last = nln;
+ }
+
+ /*
+ * Finish bookkeeping. The last new element becomes the last element
+ * of list one.
+ */
+ list1->lastPtr = last;
+
+ /*
+ * The circularity of both list one and list two must be corrected
+ * for -- list one because of the new nodes added to it; list two
+ * because of the alteration of list2->lastPtr's nextPtr to ease the
+ * above for loop.
+ */
+ if (list1->isCirc) {
+ list1->lastPtr->nextPtr = list1->firstPtr;
+ list1->firstPtr->prevPtr = list1->lastPtr;
+ } else {
+ last->nextPtr = NULL;
+ }
+
+ if (list2->isCirc) {
+ list2->lastPtr->nextPtr = list2->firstPtr;
+ }
+ }
+
+ return (SUCCESS);
+}
+