btrfs-progs: calculate available blocks on device properly

I found that mkfs.btrfs aborts when assigned multi volumes contain
a small volume:

  # parted /dev/sdf p
  Model: LSI MegaRAID SAS RMB (scsi)
  Disk /dev/sdf: 72.8GB
  Sector size (logical/physical): 512B/512B
  Partition Table: msdos

  Number  Start   End     Size    Type     File system  Flags
   1      32.3kB  72.4GB  72.4GB  primary
   2      72.4GB  72.8GB  461MB   primary

  # ./mkfs.btrfs -f /dev/sdf1 /dev/sdf2
  :
  SMALL VOLUME: forcing mixed metadata/data groups
  adding device /dev/sdf2 id 2
  mkfs.btrfs: volumes.c:852: btrfs_alloc_chunk: Assertion `!(ret)' failed.
  Aborted (core dumped)

This failure of btrfs_alloc_chunk was caused by following steps:
 1) since there is only small space in the small device, mkfs was
    going to allocate a chunk from free space as much as available.
    So mkfs called btrfs_alloc_chunk with
        size = device->total_bytes - device->used_bytes.
 2) (According to the comment in source code, to avoid overwriting
    superblock,) btrfs_alloc_chunk starts taking chunks at an offset
    of 1MB. It means that the layout of a disk will be like:
     [[1MB at beginning for sb][allocated chunks]* ... free space ... ]
    and you can see that the available free space for allocation is:
        avail = device->total_bytes - device->used_bytes - 1MB.
 3) Therefore there is only free space 1MB less than requested. damn.

>From further investigations I also found that this issue is easily
reproduced by using -A, --alloc-start option:

  # truncate --size=1G testfile
  # ./mkfs.btrfs -A900M -f testfile
   :
  mkfs.btrfs: volumes.c:852: btrfs_alloc_chunk: Assertion `!(ret)' failed.
  Aborted (core dumped)

In this case there is only 100MB for allocation but btrfs_alloc_chunk
was going to allocate more than the 100MB.

The root cause of both of above troubles is a same simple bug:
btrfs_chunk_alloc does not calculate available bytes properly even
though it researches how many devices have enough room to have a
chunk to be allocated.

So this patch introduces new function btrfs_device_avail_bytes()
which returns available bytes for allocation in specified device.

Signed-off-by: Hidetoshi Seto <seto.hidetoshi@jp.fujitsu.com>
Signed-off-by: David Sterba <dsterba@suse.cz>
Signed-off-by: Chris Mason <chris.mason@fusionio.com>

1 files changed, 8 insertions, 0 deletions

diff --git a/ctree.h b/ctree.h
index fedb79a..41a037c 100644
--- a/ctree.h
+++ b/ctree.h
@@ -814,6 +814,14 @@ struct btrfs_csum_item {
 	u8 csum;
 } __attribute__ ((__packed__));
 
+/*
+ * We don't want to overwrite 1M at the beginning of device, even though
+ * there is our 1st superblock at 64k. Some possible reasons:
+ *  - the first 64k blank is useful for some boot loader/manager
+ *  - the first 1M could be scratched by buggy partitioner or somesuch
+ */
+#define BTRFS_BLOCK_RESERVED_1M_FOR_SUPER	((u64)1024 * 1024)
+
 /* tag for the radix tree of block groups in ram */
 #define BTRFS_BLOCK_GROUP_DATA		(1ULL << 0)
 #define BTRFS_BLOCK_GROUP_SYSTEM	(1ULL << 1)