summaryrefslogtreecommitdiff
path: root/bzrlib/graph.py
diff options
context:
space:
mode:
Diffstat (limited to 'bzrlib/graph.py')
-rw-r--r--bzrlib/graph.py1715
1 files changed, 1715 insertions, 0 deletions
diff --git a/bzrlib/graph.py b/bzrlib/graph.py
new file mode 100644
index 0000000..e1c2522
--- /dev/null
+++ b/bzrlib/graph.py
@@ -0,0 +1,1715 @@
+# Copyright (C) 2007-2011 Canonical Ltd
+#
+# This program is free software; you can redistribute it and/or modify
+# it under the terms of the GNU General Public License as published by
+# the Free Software Foundation; either version 2 of the License, or
+# (at your option) any later version.
+#
+# This program is distributed in the hope that it will be useful,
+# but WITHOUT ANY WARRANTY; without even the implied warranty of
+# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
+# GNU General Public License for more details.
+#
+# You should have received a copy of the GNU General Public License
+# along with this program; if not, write to the Free Software
+# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
+
+from __future__ import absolute_import
+
+import time
+
+from bzrlib import (
+ debug,
+ errors,
+ osutils,
+ revision,
+ trace,
+ )
+
+STEP_UNIQUE_SEARCHER_EVERY = 5
+
+# DIAGRAM of terminology
+# A
+# /\
+# B C
+# | |\
+# D E F
+# |\/| |
+# |/\|/
+# G H
+#
+# In this diagram, relative to G and H:
+# A, B, C, D, E are common ancestors.
+# C, D and E are border ancestors, because each has a non-common descendant.
+# D and E are least common ancestors because none of their descendants are
+# common ancestors.
+# C is not a least common ancestor because its descendant, E, is a common
+# ancestor.
+#
+# The find_unique_lca algorithm will pick A in two steps:
+# 1. find_lca('G', 'H') => ['D', 'E']
+# 2. Since len(['D', 'E']) > 1, find_lca('D', 'E') => ['A']
+
+
+class DictParentsProvider(object):
+ """A parents provider for Graph objects."""
+
+ def __init__(self, ancestry):
+ self.ancestry = ancestry
+
+ def __repr__(self):
+ return 'DictParentsProvider(%r)' % self.ancestry
+
+ # Note: DictParentsProvider does not implement get_cached_parent_map
+ # Arguably, the data is clearly cached in memory. However, this class
+ # is mostly used for testing, and it keeps the tests clean to not
+ # change it.
+
+ def get_parent_map(self, keys):
+ """See StackedParentsProvider.get_parent_map"""
+ ancestry = self.ancestry
+ return dict([(k, ancestry[k]) for k in keys if k in ancestry])
+
+
+class StackedParentsProvider(object):
+ """A parents provider which stacks (or unions) multiple providers.
+
+ The providers are queries in the order of the provided parent_providers.
+ """
+
+ def __init__(self, parent_providers):
+ self._parent_providers = parent_providers
+
+ def __repr__(self):
+ return "%s(%r)" % (self.__class__.__name__, self._parent_providers)
+
+ def get_parent_map(self, keys):
+ """Get a mapping of keys => parents
+
+ A dictionary is returned with an entry for each key present in this
+ source. If this source doesn't have information about a key, it should
+ not include an entry.
+
+ [NULL_REVISION] is used as the parent of the first user-committed
+ revision. Its parent list is empty.
+
+ :param keys: An iterable returning keys to check (eg revision_ids)
+ :return: A dictionary mapping each key to its parents
+ """
+ found = {}
+ remaining = set(keys)
+ # This adds getattr() overhead to each get_parent_map call. However,
+ # this is StackedParentsProvider, which means we're dealing with I/O
+ # (either local indexes, or remote RPCs), so CPU overhead should be
+ # minimal.
+ for parents_provider in self._parent_providers:
+ get_cached = getattr(parents_provider, 'get_cached_parent_map',
+ None)
+ if get_cached is None:
+ continue
+ new_found = get_cached(remaining)
+ found.update(new_found)
+ remaining.difference_update(new_found)
+ if not remaining:
+ break
+ if not remaining:
+ return found
+ for parents_provider in self._parent_providers:
+ new_found = parents_provider.get_parent_map(remaining)
+ found.update(new_found)
+ remaining.difference_update(new_found)
+ if not remaining:
+ break
+ return found
+
+
+class CachingParentsProvider(object):
+ """A parents provider which will cache the revision => parents as a dict.
+
+ This is useful for providers which have an expensive look up.
+
+ Either a ParentsProvider or a get_parent_map-like callback may be
+ supplied. If it provides extra un-asked-for parents, they will be cached,
+ but filtered out of get_parent_map.
+
+ The cache is enabled by default, but may be disabled and re-enabled.
+ """
+ def __init__(self, parent_provider=None, get_parent_map=None):
+ """Constructor.
+
+ :param parent_provider: The ParentProvider to use. It or
+ get_parent_map must be supplied.
+ :param get_parent_map: The get_parent_map callback to use. It or
+ parent_provider must be supplied.
+ """
+ self._real_provider = parent_provider
+ if get_parent_map is None:
+ self._get_parent_map = self._real_provider.get_parent_map
+ else:
+ self._get_parent_map = get_parent_map
+ self._cache = None
+ self.enable_cache(True)
+
+ def __repr__(self):
+ return "%s(%r)" % (self.__class__.__name__, self._real_provider)
+
+ def enable_cache(self, cache_misses=True):
+ """Enable cache."""
+ if self._cache is not None:
+ raise AssertionError('Cache enabled when already enabled.')
+ self._cache = {}
+ self._cache_misses = cache_misses
+ self.missing_keys = set()
+
+ def disable_cache(self):
+ """Disable and clear the cache."""
+ self._cache = None
+ self._cache_misses = None
+ self.missing_keys = set()
+
+ def get_cached_map(self):
+ """Return any cached get_parent_map values."""
+ if self._cache is None:
+ return None
+ return dict(self._cache)
+
+ def get_cached_parent_map(self, keys):
+ """Return items from the cache.
+
+ This returns the same info as get_parent_map, but explicitly does not
+ invoke the supplied ParentsProvider to search for uncached values.
+ """
+ cache = self._cache
+ if cache is None:
+ return {}
+ return dict([(key, cache[key]) for key in keys if key in cache])
+
+ def get_parent_map(self, keys):
+ """See StackedParentsProvider.get_parent_map."""
+ cache = self._cache
+ if cache is None:
+ cache = self._get_parent_map(keys)
+ else:
+ needed_revisions = set(key for key in keys if key not in cache)
+ # Do not ask for negatively cached keys
+ needed_revisions.difference_update(self.missing_keys)
+ if needed_revisions:
+ parent_map = self._get_parent_map(needed_revisions)
+ cache.update(parent_map)
+ if self._cache_misses:
+ for key in needed_revisions:
+ if key not in parent_map:
+ self.note_missing_key(key)
+ result = {}
+ for key in keys:
+ value = cache.get(key)
+ if value is not None:
+ result[key] = value
+ return result
+
+ def note_missing_key(self, key):
+ """Note that key is a missing key."""
+ if self._cache_misses:
+ self.missing_keys.add(key)
+
+
+class CallableToParentsProviderAdapter(object):
+ """A parents provider that adapts any callable to the parents provider API.
+
+ i.e. it accepts calls to self.get_parent_map and relays them to the
+ callable it was constructed with.
+ """
+
+ def __init__(self, a_callable):
+ self.callable = a_callable
+
+ def __repr__(self):
+ return "%s(%r)" % (self.__class__.__name__, self.callable)
+
+ def get_parent_map(self, keys):
+ return self.callable(keys)
+
+
+class Graph(object):
+ """Provide incremental access to revision graphs.
+
+ This is the generic implementation; it is intended to be subclassed to
+ specialize it for other repository types.
+ """
+
+ def __init__(self, parents_provider):
+ """Construct a Graph that uses several graphs as its input
+
+ This should not normally be invoked directly, because there may be
+ specialized implementations for particular repository types. See
+ Repository.get_graph().
+
+ :param parents_provider: An object providing a get_parent_map call
+ conforming to the behavior of
+ StackedParentsProvider.get_parent_map.
+ """
+ if getattr(parents_provider, 'get_parents', None) is not None:
+ self.get_parents = parents_provider.get_parents
+ if getattr(parents_provider, 'get_parent_map', None) is not None:
+ self.get_parent_map = parents_provider.get_parent_map
+ self._parents_provider = parents_provider
+
+ def __repr__(self):
+ return 'Graph(%r)' % self._parents_provider
+
+ def find_lca(self, *revisions):
+ """Determine the lowest common ancestors of the provided revisions
+
+ A lowest common ancestor is a common ancestor none of whose
+ descendants are common ancestors. In graphs, unlike trees, there may
+ be multiple lowest common ancestors.
+
+ This algorithm has two phases. Phase 1 identifies border ancestors,
+ and phase 2 filters border ancestors to determine lowest common
+ ancestors.
+
+ In phase 1, border ancestors are identified, using a breadth-first
+ search starting at the bottom of the graph. Searches are stopped
+ whenever a node or one of its descendants is determined to be common
+
+ In phase 2, the border ancestors are filtered to find the least
+ common ancestors. This is done by searching the ancestries of each
+ border ancestor.
+
+ Phase 2 is perfomed on the principle that a border ancestor that is
+ not an ancestor of any other border ancestor is a least common
+ ancestor.
+
+ Searches are stopped when they find a node that is determined to be a
+ common ancestor of all border ancestors, because this shows that it
+ cannot be a descendant of any border ancestor.
+
+ The scaling of this operation should be proportional to:
+
+ 1. The number of uncommon ancestors
+ 2. The number of border ancestors
+ 3. The length of the shortest path between a border ancestor and an
+ ancestor of all border ancestors.
+ """
+ border_common, common, sides = self._find_border_ancestors(revisions)
+ # We may have common ancestors that can be reached from each other.
+ # - ask for the heads of them to filter it down to only ones that
+ # cannot be reached from each other - phase 2.
+ return self.heads(border_common)
+
+ def find_difference(self, left_revision, right_revision):
+ """Determine the graph difference between two revisions"""
+ border, common, searchers = self._find_border_ancestors(
+ [left_revision, right_revision])
+ self._search_for_extra_common(common, searchers)
+ left = searchers[0].seen
+ right = searchers[1].seen
+ return (left.difference(right), right.difference(left))
+
+ def find_descendants(self, old_key, new_key):
+ """Find descendants of old_key that are ancestors of new_key."""
+ child_map = self.get_child_map(self._find_descendant_ancestors(
+ old_key, new_key))
+ graph = Graph(DictParentsProvider(child_map))
+ searcher = graph._make_breadth_first_searcher([old_key])
+ list(searcher)
+ return searcher.seen
+
+ def _find_descendant_ancestors(self, old_key, new_key):
+ """Find ancestors of new_key that may be descendants of old_key."""
+ stop = self._make_breadth_first_searcher([old_key])
+ descendants = self._make_breadth_first_searcher([new_key])
+ for revisions in descendants:
+ old_stop = stop.seen.intersection(revisions)
+ descendants.stop_searching_any(old_stop)
+ seen_stop = descendants.find_seen_ancestors(stop.step())
+ descendants.stop_searching_any(seen_stop)
+ return descendants.seen.difference(stop.seen)
+
+ def get_child_map(self, keys):
+ """Get a mapping from parents to children of the specified keys.
+
+ This is simply the inversion of get_parent_map. Only supplied keys
+ will be discovered as children.
+ :return: a dict of key:child_list for keys.
+ """
+ parent_map = self._parents_provider.get_parent_map(keys)
+ parent_child = {}
+ for child, parents in sorted(parent_map.items()):
+ for parent in parents:
+ parent_child.setdefault(parent, []).append(child)
+ return parent_child
+
+ def find_distance_to_null(self, target_revision_id, known_revision_ids):
+ """Find the left-hand distance to the NULL_REVISION.
+
+ (This can also be considered the revno of a branch at
+ target_revision_id.)
+
+ :param target_revision_id: A revision_id which we would like to know
+ the revno for.
+ :param known_revision_ids: [(revision_id, revno)] A list of known
+ revno, revision_id tuples. We'll use this to seed the search.
+ """
+ # Map from revision_ids to a known value for their revno
+ known_revnos = dict(known_revision_ids)
+ cur_tip = target_revision_id
+ num_steps = 0
+ NULL_REVISION = revision.NULL_REVISION
+ known_revnos[NULL_REVISION] = 0
+
+ searching_known_tips = list(known_revnos.keys())
+
+ unknown_searched = {}
+
+ while cur_tip not in known_revnos:
+ unknown_searched[cur_tip] = num_steps
+ num_steps += 1
+ to_search = set([cur_tip])
+ to_search.update(searching_known_tips)
+ parent_map = self.get_parent_map(to_search)
+ parents = parent_map.get(cur_tip, None)
+ if not parents: # An empty list or None is a ghost
+ raise errors.GhostRevisionsHaveNoRevno(target_revision_id,
+ cur_tip)
+ cur_tip = parents[0]
+ next_known_tips = []
+ for revision_id in searching_known_tips:
+ parents = parent_map.get(revision_id, None)
+ if not parents:
+ continue
+ next = parents[0]
+ next_revno = known_revnos[revision_id] - 1
+ if next in unknown_searched:
+ # We have enough information to return a value right now
+ return next_revno + unknown_searched[next]
+ if next in known_revnos:
+ continue
+ known_revnos[next] = next_revno
+ next_known_tips.append(next)
+ searching_known_tips = next_known_tips
+
+ # We reached a known revision, so just add in how many steps it took to
+ # get there.
+ return known_revnos[cur_tip] + num_steps
+
+ def find_lefthand_distances(self, keys):
+ """Find the distance to null for all the keys in keys.
+
+ :param keys: keys to lookup.
+ :return: A dict key->distance for all of keys.
+ """
+ # Optimisable by concurrent searching, but a random spread should get
+ # some sort of hit rate.
+ result = {}
+ known_revnos = []
+ ghosts = []
+ for key in keys:
+ try:
+ known_revnos.append(
+ (key, self.find_distance_to_null(key, known_revnos)))
+ except errors.GhostRevisionsHaveNoRevno:
+ ghosts.append(key)
+ for key in ghosts:
+ known_revnos.append((key, -1))
+ return dict(known_revnos)
+
+ def find_unique_ancestors(self, unique_revision, common_revisions):
+ """Find the unique ancestors for a revision versus others.
+
+ This returns the ancestry of unique_revision, excluding all revisions
+ in the ancestry of common_revisions. If unique_revision is in the
+ ancestry, then the empty set will be returned.
+
+ :param unique_revision: The revision_id whose ancestry we are
+ interested in.
+ (XXX: Would this API be better if we allowed multiple revisions on
+ to be searched here?)
+ :param common_revisions: Revision_ids of ancestries to exclude.
+ :return: A set of revisions in the ancestry of unique_revision
+ """
+ if unique_revision in common_revisions:
+ return set()
+
+ # Algorithm description
+ # 1) Walk backwards from the unique node and all common nodes.
+ # 2) When a node is seen by both sides, stop searching it in the unique
+ # walker, include it in the common walker.
+ # 3) Stop searching when there are no nodes left for the unique walker.
+ # At this point, you have a maximal set of unique nodes. Some of
+ # them may actually be common, and you haven't reached them yet.
+ # 4) Start new searchers for the unique nodes, seeded with the
+ # information you have so far.
+ # 5) Continue searching, stopping the common searches when the search
+ # tip is an ancestor of all unique nodes.
+ # 6) Aggregate together unique searchers when they are searching the
+ # same tips. When all unique searchers are searching the same node,
+ # stop move it to a single 'all_unique_searcher'.
+ # 7) The 'all_unique_searcher' represents the very 'tip' of searching.
+ # Most of the time this produces very little important information.
+ # So don't step it as quickly as the other searchers.
+ # 8) Search is done when all common searchers have completed.
+
+ unique_searcher, common_searcher = self._find_initial_unique_nodes(
+ [unique_revision], common_revisions)
+
+ unique_nodes = unique_searcher.seen.difference(common_searcher.seen)
+ if not unique_nodes:
+ return unique_nodes
+
+ (all_unique_searcher,
+ unique_tip_searchers) = self._make_unique_searchers(unique_nodes,
+ unique_searcher, common_searcher)
+
+ self._refine_unique_nodes(unique_searcher, all_unique_searcher,
+ unique_tip_searchers, common_searcher)
+ true_unique_nodes = unique_nodes.difference(common_searcher.seen)
+ if 'graph' in debug.debug_flags:
+ trace.mutter('Found %d truly unique nodes out of %d',
+ len(true_unique_nodes), len(unique_nodes))
+ return true_unique_nodes
+
+ def _find_initial_unique_nodes(self, unique_revisions, common_revisions):
+ """Steps 1-3 of find_unique_ancestors.
+
+ Find the maximal set of unique nodes. Some of these might actually
+ still be common, but we are sure that there are no other unique nodes.
+
+ :return: (unique_searcher, common_searcher)
+ """
+
+ unique_searcher = self._make_breadth_first_searcher(unique_revisions)
+ # we know that unique_revisions aren't in common_revisions, so skip
+ # past them.
+ unique_searcher.next()
+ common_searcher = self._make_breadth_first_searcher(common_revisions)
+
+ # As long as we are still finding unique nodes, keep searching
+ while unique_searcher._next_query:
+ next_unique_nodes = set(unique_searcher.step())
+ next_common_nodes = set(common_searcher.step())
+
+ # Check if either searcher encounters new nodes seen by the other
+ # side.
+ unique_are_common_nodes = next_unique_nodes.intersection(
+ common_searcher.seen)
+ unique_are_common_nodes.update(
+ next_common_nodes.intersection(unique_searcher.seen))
+ if unique_are_common_nodes:
+ ancestors = unique_searcher.find_seen_ancestors(
+ unique_are_common_nodes)
+ # TODO: This is a bit overboard, we only really care about
+ # the ancestors of the tips because the rest we
+ # already know. This is *correct* but causes us to
+ # search too much ancestry.
+ ancestors.update(common_searcher.find_seen_ancestors(ancestors))
+ unique_searcher.stop_searching_any(ancestors)
+ common_searcher.start_searching(ancestors)
+
+ return unique_searcher, common_searcher
+
+ def _make_unique_searchers(self, unique_nodes, unique_searcher,
+ common_searcher):
+ """Create a searcher for all the unique search tips (step 4).
+
+ As a side effect, the common_searcher will stop searching any nodes
+ that are ancestors of the unique searcher tips.
+
+ :return: (all_unique_searcher, unique_tip_searchers)
+ """
+ unique_tips = self._remove_simple_descendants(unique_nodes,
+ self.get_parent_map(unique_nodes))
+
+ if len(unique_tips) == 1:
+ unique_tip_searchers = []
+ ancestor_all_unique = unique_searcher.find_seen_ancestors(unique_tips)
+ else:
+ unique_tip_searchers = []
+ for tip in unique_tips:
+ revs_to_search = unique_searcher.find_seen_ancestors([tip])
+ revs_to_search.update(
+ common_searcher.find_seen_ancestors(revs_to_search))
+ searcher = self._make_breadth_first_searcher(revs_to_search)
+ # We don't care about the starting nodes.
+ searcher._label = tip
+ searcher.step()
+ unique_tip_searchers.append(searcher)
+
+ ancestor_all_unique = None
+ for searcher in unique_tip_searchers:
+ if ancestor_all_unique is None:
+ ancestor_all_unique = set(searcher.seen)
+ else:
+ ancestor_all_unique = ancestor_all_unique.intersection(
+ searcher.seen)
+ # Collapse all the common nodes into a single searcher
+ all_unique_searcher = self._make_breadth_first_searcher(
+ ancestor_all_unique)
+ if ancestor_all_unique:
+ # We've seen these nodes in all the searchers, so we'll just go to
+ # the next
+ all_unique_searcher.step()
+
+ # Stop any search tips that are already known as ancestors of the
+ # unique nodes
+ stopped_common = common_searcher.stop_searching_any(
+ common_searcher.find_seen_ancestors(ancestor_all_unique))
+
+ total_stopped = 0
+ for searcher in unique_tip_searchers:
+ total_stopped += len(searcher.stop_searching_any(
+ searcher.find_seen_ancestors(ancestor_all_unique)))
+ if 'graph' in debug.debug_flags:
+ trace.mutter('For %d unique nodes, created %d + 1 unique searchers'
+ ' (%d stopped search tips, %d common ancestors'
+ ' (%d stopped common)',
+ len(unique_nodes), len(unique_tip_searchers),
+ total_stopped, len(ancestor_all_unique),
+ len(stopped_common))
+ return all_unique_searcher, unique_tip_searchers
+
+ def _step_unique_and_common_searchers(self, common_searcher,
+ unique_tip_searchers,
+ unique_searcher):
+ """Step all the searchers"""
+ newly_seen_common = set(common_searcher.step())
+ newly_seen_unique = set()
+ for searcher in unique_tip_searchers:
+ next = set(searcher.step())
+ next.update(unique_searcher.find_seen_ancestors(next))
+ next.update(common_searcher.find_seen_ancestors(next))
+ for alt_searcher in unique_tip_searchers:
+ if alt_searcher is searcher:
+ continue
+ next.update(alt_searcher.find_seen_ancestors(next))
+ searcher.start_searching(next)
+ newly_seen_unique.update(next)
+ return newly_seen_common, newly_seen_unique
+
+ def _find_nodes_common_to_all_unique(self, unique_tip_searchers,
+ all_unique_searcher,
+ newly_seen_unique, step_all_unique):
+ """Find nodes that are common to all unique_tip_searchers.
+
+ If it is time, step the all_unique_searcher, and add its nodes to the
+ result.
+ """
+ common_to_all_unique_nodes = newly_seen_unique.copy()
+ for searcher in unique_tip_searchers:
+ common_to_all_unique_nodes.intersection_update(searcher.seen)
+ common_to_all_unique_nodes.intersection_update(
+ all_unique_searcher.seen)
+ # Step all-unique less frequently than the other searchers.
+ # In the common case, we don't need to spider out far here, so
+ # avoid doing extra work.
+ if step_all_unique:
+ tstart = time.clock()
+ nodes = all_unique_searcher.step()
+ common_to_all_unique_nodes.update(nodes)
+ if 'graph' in debug.debug_flags:
+ tdelta = time.clock() - tstart
+ trace.mutter('all_unique_searcher step() took %.3fs'
+ 'for %d nodes (%d total), iteration: %s',
+ tdelta, len(nodes), len(all_unique_searcher.seen),
+ all_unique_searcher._iterations)
+ return common_to_all_unique_nodes
+
+ def _collapse_unique_searchers(self, unique_tip_searchers,
+ common_to_all_unique_nodes):
+ """Combine searchers that are searching the same tips.
+
+ When two searchers are searching the same tips, we can stop one of the
+ searchers. We also know that the maximal set of common ancestors is the
+ intersection of the two original searchers.
+
+ :return: A list of searchers that are searching unique nodes.
+ """
+ # Filter out searchers that don't actually search different
+ # nodes. We already have the ancestry intersection for them
+ unique_search_tips = {}
+ for searcher in unique_tip_searchers:
+ stopped = searcher.stop_searching_any(common_to_all_unique_nodes)
+ will_search_set = frozenset(searcher._next_query)
+ if not will_search_set:
+ if 'graph' in debug.debug_flags:
+ trace.mutter('Unique searcher %s was stopped.'
+ ' (%s iterations) %d nodes stopped',
+ searcher._label,
+ searcher._iterations,
+ len(stopped))
+ elif will_search_set not in unique_search_tips:
+ # This searcher is searching a unique set of nodes, let it
+ unique_search_tips[will_search_set] = [searcher]
+ else:
+ unique_search_tips[will_search_set].append(searcher)
+ # TODO: it might be possible to collapse searchers faster when they
+ # only have *some* search tips in common.
+ next_unique_searchers = []
+ for searchers in unique_search_tips.itervalues():
+ if len(searchers) == 1:
+ # Searching unique tips, go for it
+ next_unique_searchers.append(searchers[0])
+ else:
+ # These searchers have started searching the same tips, we
+ # don't need them to cover the same ground. The
+ # intersection of their ancestry won't change, so create a
+ # new searcher, combining their histories.
+ next_searcher = searchers[0]
+ for searcher in searchers[1:]:
+ next_searcher.seen.intersection_update(searcher.seen)
+ if 'graph' in debug.debug_flags:
+ trace.mutter('Combining %d searchers into a single'
+ ' searcher searching %d nodes with'
+ ' %d ancestry',
+ len(searchers),
+ len(next_searcher._next_query),
+ len(next_searcher.seen))
+ next_unique_searchers.append(next_searcher)
+ return next_unique_searchers
+
+ def _refine_unique_nodes(self, unique_searcher, all_unique_searcher,
+ unique_tip_searchers, common_searcher):
+ """Steps 5-8 of find_unique_ancestors.
+
+ This function returns when common_searcher has stopped searching for
+ more nodes.
+ """
+ # We step the ancestor_all_unique searcher only every
+ # STEP_UNIQUE_SEARCHER_EVERY steps.
+ step_all_unique_counter = 0
+ # While we still have common nodes to search
+ while common_searcher._next_query:
+ (newly_seen_common,
+ newly_seen_unique) = self._step_unique_and_common_searchers(
+ common_searcher, unique_tip_searchers, unique_searcher)
+ # These nodes are common ancestors of all unique nodes
+ common_to_all_unique_nodes = self._find_nodes_common_to_all_unique(
+ unique_tip_searchers, all_unique_searcher, newly_seen_unique,
+ step_all_unique_counter==0)
+ step_all_unique_counter = ((step_all_unique_counter + 1)
+ % STEP_UNIQUE_SEARCHER_EVERY)
+
+ if newly_seen_common:
+ # If a 'common' node is an ancestor of all unique searchers, we
+ # can stop searching it.
+ common_searcher.stop_searching_any(
+ all_unique_searcher.seen.intersection(newly_seen_common))
+ if common_to_all_unique_nodes:
+ common_to_all_unique_nodes.update(
+ common_searcher.find_seen_ancestors(
+ common_to_all_unique_nodes))
+ # The all_unique searcher can start searching the common nodes
+ # but everyone else can stop.
+ # This is the sort of thing where we would like to not have it
+ # start_searching all of the nodes, but only mark all of them
+ # as seen, and have it search only the actual tips. Otherwise
+ # it is another get_parent_map() traversal for it to figure out
+ # what we already should know.
+ all_unique_searcher.start_searching(common_to_all_unique_nodes)
+ common_searcher.stop_searching_any(common_to_all_unique_nodes)
+
+ next_unique_searchers = self._collapse_unique_searchers(
+ unique_tip_searchers, common_to_all_unique_nodes)
+ if len(unique_tip_searchers) != len(next_unique_searchers):
+ if 'graph' in debug.debug_flags:
+ trace.mutter('Collapsed %d unique searchers => %d'
+ ' at %s iterations',
+ len(unique_tip_searchers),
+ len(next_unique_searchers),
+ all_unique_searcher._iterations)
+ unique_tip_searchers = next_unique_searchers
+
+ def get_parent_map(self, revisions):
+ """Get a map of key:parent_list for revisions.
+
+ This implementation delegates to get_parents, for old parent_providers
+ that do not supply get_parent_map.
+ """
+ result = {}
+ for rev, parents in self.get_parents(revisions):
+ if parents is not None:
+ result[rev] = parents
+ return result
+
+ def _make_breadth_first_searcher(self, revisions):
+ return _BreadthFirstSearcher(revisions, self)
+
+ def _find_border_ancestors(self, revisions):
+ """Find common ancestors with at least one uncommon descendant.
+
+ Border ancestors are identified using a breadth-first
+ search starting at the bottom of the graph. Searches are stopped
+ whenever a node or one of its descendants is determined to be common.
+
+ This will scale with the number of uncommon ancestors.
+
+ As well as the border ancestors, a set of seen common ancestors and a
+ list of sets of seen ancestors for each input revision is returned.
+ This allows calculation of graph difference from the results of this
+ operation.
+ """
+ if None in revisions:
+ raise errors.InvalidRevisionId(None, self)
+ common_ancestors = set()
+ searchers = [self._make_breadth_first_searcher([r])
+ for r in revisions]
+ active_searchers = searchers[:]
+ border_ancestors = set()
+
+ while True:
+ newly_seen = set()
+ for searcher in searchers:
+ new_ancestors = searcher.step()
+ if new_ancestors:
+ newly_seen.update(new_ancestors)
+ new_common = set()
+ for revision in newly_seen:
+ if revision in common_ancestors:
+ # Not a border ancestor because it was seen as common
+ # already
+ new_common.add(revision)
+ continue
+ for searcher in searchers:
+ if revision not in searcher.seen:
+ break
+ else:
+ # This is a border because it is a first common that we see
+ # after walking for a while.
+ border_ancestors.add(revision)
+ new_common.add(revision)
+ if new_common:
+ for searcher in searchers:
+ new_common.update(searcher.find_seen_ancestors(new_common))
+ for searcher in searchers:
+ searcher.start_searching(new_common)
+ common_ancestors.update(new_common)
+
+ # Figure out what the searchers will be searching next, and if
+ # there is only 1 set being searched, then we are done searching,
+ # since all searchers would have to be searching the same data,
+ # thus it *must* be in common.
+ unique_search_sets = set()
+ for searcher in searchers:
+ will_search_set = frozenset(searcher._next_query)
+ if will_search_set not in unique_search_sets:
+ # This searcher is searching a unique set of nodes, let it
+ unique_search_sets.add(will_search_set)
+
+ if len(unique_search_sets) == 1:
+ nodes = unique_search_sets.pop()
+ uncommon_nodes = nodes.difference(common_ancestors)
+ if uncommon_nodes:
+ raise AssertionError("Somehow we ended up converging"
+ " without actually marking them as"
+ " in common."
+ "\nStart_nodes: %s"
+ "\nuncommon_nodes: %s"
+ % (revisions, uncommon_nodes))
+ break
+ return border_ancestors, common_ancestors, searchers
+
+ def heads(self, keys):
+ """Return the heads from amongst keys.
+
+ This is done by searching the ancestries of each key. Any key that is
+ reachable from another key is not returned; all the others are.
+
+ This operation scales with the relative depth between any two keys. If
+ any two keys are completely disconnected all ancestry of both sides
+ will be retrieved.
+
+ :param keys: An iterable of keys.
+ :return: A set of the heads. Note that as a set there is no ordering
+ information. Callers will need to filter their input to create
+ order if they need it.
+ """
+ candidate_heads = set(keys)
+ if revision.NULL_REVISION in candidate_heads:
+ # NULL_REVISION is only a head if it is the only entry
+ candidate_heads.remove(revision.NULL_REVISION)
+ if not candidate_heads:
+ return set([revision.NULL_REVISION])
+ if len(candidate_heads) < 2:
+ return candidate_heads
+ searchers = dict((c, self._make_breadth_first_searcher([c]))
+ for c in candidate_heads)
+ active_searchers = dict(searchers)
+ # skip over the actual candidate for each searcher
+ for searcher in active_searchers.itervalues():
+ searcher.next()
+ # The common walker finds nodes that are common to two or more of the
+ # input keys, so that we don't access all history when a currently
+ # uncommon search point actually meets up with something behind a
+ # common search point. Common search points do not keep searches
+ # active; they just allow us to make searches inactive without
+ # accessing all history.
+ common_walker = self._make_breadth_first_searcher([])
+ while len(active_searchers) > 0:
+ ancestors = set()
+ # advance searches
+ try:
+ common_walker.next()
+ except StopIteration:
+ # No common points being searched at this time.
+ pass
+ for candidate in active_searchers.keys():
+ try:
+ searcher = active_searchers[candidate]
+ except KeyError:
+ # rare case: we deleted candidate in a previous iteration
+ # through this for loop, because it was determined to be
+ # a descendant of another candidate.
+ continue
+ try:
+ ancestors.update(searcher.next())
+ except StopIteration:
+ del active_searchers[candidate]
+ continue
+ # process found nodes
+ new_common = set()
+ for ancestor in ancestors:
+ if ancestor in candidate_heads:
+ candidate_heads.remove(ancestor)
+ del searchers[ancestor]
+ if ancestor in active_searchers:
+ del active_searchers[ancestor]
+ # it may meet up with a known common node
+ if ancestor in common_walker.seen:
+ # some searcher has encountered our known common nodes:
+ # just stop it
+ ancestor_set = set([ancestor])
+ for searcher in searchers.itervalues():
+ searcher.stop_searching_any(ancestor_set)
+ else:
+ # or it may have been just reached by all the searchers:
+ for searcher in searchers.itervalues():
+ if ancestor not in searcher.seen:
+ break
+ else:
+ # The final active searcher has just reached this node,
+ # making it be known as a descendant of all candidates,
+ # so we can stop searching it, and any seen ancestors
+ new_common.add(ancestor)
+ for searcher in searchers.itervalues():
+ seen_ancestors =\
+ searcher.find_seen_ancestors([ancestor])
+ searcher.stop_searching_any(seen_ancestors)
+ common_walker.start_searching(new_common)
+ return candidate_heads
+
+ def find_merge_order(self, tip_revision_id, lca_revision_ids):
+ """Find the order that each revision was merged into tip.
+
+ This basically just walks backwards with a stack, and walks left-first
+ until it finds a node to stop.
+ """
+ if len(lca_revision_ids) == 1:
+ return list(lca_revision_ids)
+ looking_for = set(lca_revision_ids)
+ # TODO: Is there a way we could do this "faster" by batching up the
+ # get_parent_map requests?
+ # TODO: Should we also be culling the ancestry search right away? We
+ # could add looking_for to the "stop" list, and walk their
+ # ancestry in batched mode. The flip side is it might mean we walk a
+ # lot of "stop" nodes, rather than only the minimum.
+ # Then again, without it we may trace back into ancestry we could have
+ # stopped early.
+ stack = [tip_revision_id]
+ found = []
+ stop = set()
+ while stack and looking_for:
+ next = stack.pop()
+ stop.add(next)
+ if next in looking_for:
+ found.append(next)
+ looking_for.remove(next)
+ if len(looking_for) == 1:
+ found.append(looking_for.pop())
+ break
+ continue
+ parent_ids = self.get_parent_map([next]).get(next, None)
+ if not parent_ids: # Ghost, nothing to search here
+ continue
+ for parent_id in reversed(parent_ids):
+ # TODO: (performance) We see the parent at this point, but we
+ # wait to mark it until later to make sure we get left
+ # parents before right parents. However, instead of
+ # waiting until we have traversed enough parents, we
+ # could instead note that we've found it, and once all
+ # parents are in the stack, just reverse iterate the
+ # stack for them.
+ if parent_id not in stop:
+ # this will need to be searched
+ stack.append(parent_id)
+ stop.add(parent_id)
+ return found
+
+ def find_lefthand_merger(self, merged_key, tip_key):
+ """Find the first lefthand ancestor of tip_key that merged merged_key.
+
+ We do this by first finding the descendants of merged_key, then
+ walking through the lefthand ancestry of tip_key until we find a key
+ that doesn't descend from merged_key. Its child is the key that
+ merged merged_key.
+
+ :return: The first lefthand ancestor of tip_key to merge merged_key.
+ merged_key if it is a lefthand ancestor of tip_key.
+ None if no ancestor of tip_key merged merged_key.
+ """
+ descendants = self.find_descendants(merged_key, tip_key)
+ candidate_iterator = self.iter_lefthand_ancestry(tip_key)
+ last_candidate = None
+ for candidate in candidate_iterator:
+ if candidate not in descendants:
+ return last_candidate
+ last_candidate = candidate
+
+ def find_unique_lca(self, left_revision, right_revision,
+ count_steps=False):
+ """Find a unique LCA.
+
+ Find lowest common ancestors. If there is no unique common
+ ancestor, find the lowest common ancestors of those ancestors.
+
+ Iteration stops when a unique lowest common ancestor is found.
+ The graph origin is necessarily a unique lowest common ancestor.
+
+ Note that None is not an acceptable substitute for NULL_REVISION.
+ in the input for this method.
+
+ :param count_steps: If True, the return value will be a tuple of
+ (unique_lca, steps) where steps is the number of times that
+ find_lca was run. If False, only unique_lca is returned.
+ """
+ revisions = [left_revision, right_revision]
+ steps = 0
+ while True:
+ steps += 1
+ lca = self.find_lca(*revisions)
+ if len(lca) == 1:
+ result = lca.pop()
+ if count_steps:
+ return result, steps
+ else:
+ return result
+ if len(lca) == 0:
+ raise errors.NoCommonAncestor(left_revision, right_revision)
+ revisions = lca
+
+ def iter_ancestry(self, revision_ids):
+ """Iterate the ancestry of this revision.
+
+ :param revision_ids: Nodes to start the search
+ :return: Yield tuples mapping a revision_id to its parents for the
+ ancestry of revision_id.
+ Ghosts will be returned with None as their parents, and nodes
+ with no parents will have NULL_REVISION as their only parent. (As
+ defined by get_parent_map.)
+ There will also be a node for (NULL_REVISION, ())
+ """
+ pending = set(revision_ids)
+ processed = set()
+ while pending:
+ processed.update(pending)
+ next_map = self.get_parent_map(pending)
+ next_pending = set()
+ for item in next_map.iteritems():
+ yield item
+ next_pending.update(p for p in item[1] if p not in processed)
+ ghosts = pending.difference(next_map)
+ for ghost in ghosts:
+ yield (ghost, None)
+ pending = next_pending
+
+ def iter_lefthand_ancestry(self, start_key, stop_keys=None):
+ if stop_keys is None:
+ stop_keys = ()
+ next_key = start_key
+ def get_parents(key):
+ try:
+ return self._parents_provider.get_parent_map([key])[key]
+ except KeyError:
+ raise errors.RevisionNotPresent(next_key, self)
+ while True:
+ if next_key in stop_keys:
+ return
+ parents = get_parents(next_key)
+ yield next_key
+ if len(parents) == 0:
+ return
+ else:
+ next_key = parents[0]
+
+ def iter_topo_order(self, revisions):
+ """Iterate through the input revisions in topological order.
+
+ This sorting only ensures that parents come before their children.
+ An ancestor may sort after a descendant if the relationship is not
+ visible in the supplied list of revisions.
+ """
+ from bzrlib import tsort
+ sorter = tsort.TopoSorter(self.get_parent_map(revisions))
+ return sorter.iter_topo_order()
+
+ def is_ancestor(self, candidate_ancestor, candidate_descendant):
+ """Determine whether a revision is an ancestor of another.
+
+ We answer this using heads() as heads() has the logic to perform the
+ smallest number of parent lookups to determine the ancestral
+ relationship between N revisions.
+ """
+ return set([candidate_descendant]) == self.heads(
+ [candidate_ancestor, candidate_descendant])
+
+ def is_between(self, revid, lower_bound_revid, upper_bound_revid):
+ """Determine whether a revision is between two others.
+
+ returns true if and only if:
+ lower_bound_revid <= revid <= upper_bound_revid
+ """
+ return ((upper_bound_revid is None or
+ self.is_ancestor(revid, upper_bound_revid)) and
+ (lower_bound_revid is None or
+ self.is_ancestor(lower_bound_revid, revid)))
+
+ def _search_for_extra_common(self, common, searchers):
+ """Make sure that unique nodes are genuinely unique.
+
+ After _find_border_ancestors, all nodes marked "common" are indeed
+ common. Some of the nodes considered unique are not, due to history
+ shortcuts stopping the searches early.
+
+ We know that we have searched enough when all common search tips are
+ descended from all unique (uncommon) nodes because we know that a node
+ cannot be an ancestor of its own ancestor.
+
+ :param common: A set of common nodes
+ :param searchers: The searchers returned from _find_border_ancestors
+ :return: None
+ """
+ # Basic algorithm...
+ # A) The passed in searchers should all be on the same tips, thus
+ # they should be considered the "common" searchers.
+ # B) We find the difference between the searchers, these are the
+ # "unique" nodes for each side.
+ # C) We do a quick culling so that we only start searching from the
+ # more interesting unique nodes. (A unique ancestor is more
+ # interesting than any of its children.)
+ # D) We start searching for ancestors common to all unique nodes.
+ # E) We have the common searchers stop searching any ancestors of
+ # nodes found by (D)
+ # F) When there are no more common search tips, we stop
+
+ # TODO: We need a way to remove unique_searchers when they overlap with
+ # other unique searchers.
+ if len(searchers) != 2:
+ raise NotImplementedError(
+ "Algorithm not yet implemented for > 2 searchers")
+ common_searchers = searchers
+ left_searcher = searchers[0]
+ right_searcher = searchers[1]
+ unique = left_searcher.seen.symmetric_difference(right_searcher.seen)
+ if not unique: # No unique nodes, nothing to do
+ return
+ total_unique = len(unique)
+ unique = self._remove_simple_descendants(unique,
+ self.get_parent_map(unique))
+ simple_unique = len(unique)
+
+ unique_searchers = []
+ for revision_id in unique:
+ if revision_id in left_searcher.seen:
+ parent_searcher = left_searcher
+ else:
+ parent_searcher = right_searcher
+ revs_to_search = parent_searcher.find_seen_ancestors([revision_id])
+ if not revs_to_search: # XXX: This shouldn't be possible
+ revs_to_search = [revision_id]
+ searcher = self._make_breadth_first_searcher(revs_to_search)
+ # We don't care about the starting nodes.
+ searcher.step()
+ unique_searchers.append(searcher)
+
+ # possible todo: aggregate the common searchers into a single common
+ # searcher, just make sure that we include the nodes into the .seen
+ # properties of the original searchers
+
+ ancestor_all_unique = None
+ for searcher in unique_searchers:
+ if ancestor_all_unique is None:
+ ancestor_all_unique = set(searcher.seen)
+ else:
+ ancestor_all_unique = ancestor_all_unique.intersection(
+ searcher.seen)
+
+ trace.mutter('Started %s unique searchers for %s unique revisions',
+ simple_unique, total_unique)
+
+ while True: # If we have no more nodes we have nothing to do
+ newly_seen_common = set()
+ for searcher in common_searchers:
+ newly_seen_common.update(searcher.step())
+ newly_seen_unique = set()
+ for searcher in unique_searchers:
+ newly_seen_unique.update(searcher.step())
+ new_common_unique = set()
+ for revision in newly_seen_unique:
+ for searcher in unique_searchers:
+ if revision not in searcher.seen:
+ break
+ else:
+ # This is a border because it is a first common that we see
+ # after walking for a while.
+ new_common_unique.add(revision)
+ if newly_seen_common:
+ # These are nodes descended from one of the 'common' searchers.
+ # Make sure all searchers are on the same page
+ for searcher in common_searchers:
+ newly_seen_common.update(
+ searcher.find_seen_ancestors(newly_seen_common))
+ # We start searching the whole ancestry. It is a bit wasteful,
+ # though. We really just want to mark all of these nodes as
+ # 'seen' and then start just the tips. However, it requires a
+ # get_parent_map() call to figure out the tips anyway, and all
+ # redundant requests should be fairly fast.
+ for searcher in common_searchers:
+ searcher.start_searching(newly_seen_common)
+
+ # If a 'common' node is an ancestor of all unique searchers, we
+ # can stop searching it.
+ stop_searching_common = ancestor_all_unique.intersection(
+ newly_seen_common)
+ if stop_searching_common:
+ for searcher in common_searchers:
+ searcher.stop_searching_any(stop_searching_common)
+ if new_common_unique:
+ # We found some ancestors that are common
+ for searcher in unique_searchers:
+ new_common_unique.update(
+ searcher.find_seen_ancestors(new_common_unique))
+ # Since these are common, we can grab another set of ancestors
+ # that we have seen
+ for searcher in common_searchers:
+ new_common_unique.update(
+ searcher.find_seen_ancestors(new_common_unique))
+
+ # We can tell all of the unique searchers to start at these
+ # nodes, and tell all of the common searchers to *stop*
+ # searching these nodes
+ for searcher in unique_searchers:
+ searcher.start_searching(new_common_unique)
+ for searcher in common_searchers:
+ searcher.stop_searching_any(new_common_unique)
+ ancestor_all_unique.update(new_common_unique)
+
+ # Filter out searchers that don't actually search different
+ # nodes. We already have the ancestry intersection for them
+ next_unique_searchers = []
+ unique_search_sets = set()
+ for searcher in unique_searchers:
+ will_search_set = frozenset(searcher._next_query)
+ if will_search_set not in unique_search_sets:
+ # This searcher is searching a unique set of nodes, let it
+ unique_search_sets.add(will_search_set)
+ next_unique_searchers.append(searcher)
+ unique_searchers = next_unique_searchers
+ for searcher in common_searchers:
+ if searcher._next_query:
+ break
+ else:
+ # All common searcher have stopped searching
+ return
+
+ def _remove_simple_descendants(self, revisions, parent_map):
+ """remove revisions which are children of other ones in the set
+
+ This doesn't do any graph searching, it just checks the immediate
+ parent_map to find if there are any children which can be removed.
+
+ :param revisions: A set of revision_ids
+ :return: A set of revision_ids with the children removed
+ """
+ simple_ancestors = revisions.copy()
+ # TODO: jam 20071214 we *could* restrict it to searching only the
+ # parent_map of revisions already present in 'revisions', but
+ # considering the general use case, I think this is actually
+ # better.
+
+ # This is the same as the following loop. I don't know that it is any
+ # faster.
+ ## simple_ancestors.difference_update(r for r, p_ids in parent_map.iteritems()
+ ## if p_ids is not None and revisions.intersection(p_ids))
+ ## return simple_ancestors
+
+ # Yet Another Way, invert the parent map (which can be cached)
+ ## descendants = {}
+ ## for revision_id, parent_ids in parent_map.iteritems():
+ ## for p_id in parent_ids:
+ ## descendants.setdefault(p_id, []).append(revision_id)
+ ## for revision in revisions.intersection(descendants):
+ ## simple_ancestors.difference_update(descendants[revision])
+ ## return simple_ancestors
+ for revision, parent_ids in parent_map.iteritems():
+ if parent_ids is None:
+ continue
+ for parent_id in parent_ids:
+ if parent_id in revisions:
+ # This node has a parent present in the set, so we can
+ # remove it
+ simple_ancestors.discard(revision)
+ break
+ return simple_ancestors
+
+
+class HeadsCache(object):
+ """A cache of results for graph heads calls."""
+
+ def __init__(self, graph):
+ self.graph = graph
+ self._heads = {}
+
+ def heads(self, keys):
+ """Return the heads of keys.
+
+ This matches the API of Graph.heads(), specifically the return value is
+ a set which can be mutated, and ordering of the input is not preserved
+ in the output.
+
+ :see also: Graph.heads.
+ :param keys: The keys to calculate heads for.
+ :return: A set containing the heads, which may be mutated without
+ affecting future lookups.
+ """
+ keys = frozenset(keys)
+ try:
+ return set(self._heads[keys])
+ except KeyError:
+ heads = self.graph.heads(keys)
+ self._heads[keys] = heads
+ return set(heads)
+
+
+class FrozenHeadsCache(object):
+ """Cache heads() calls, assuming the caller won't modify them."""
+
+ def __init__(self, graph):
+ self.graph = graph
+ self._heads = {}
+
+ def heads(self, keys):
+ """Return the heads of keys.
+
+ Similar to Graph.heads(). The main difference is that the return value
+ is a frozen set which cannot be mutated.
+
+ :see also: Graph.heads.
+ :param keys: The keys to calculate heads for.
+ :return: A frozenset containing the heads.
+ """
+ keys = frozenset(keys)
+ try:
+ return self._heads[keys]
+ except KeyError:
+ heads = frozenset(self.graph.heads(keys))
+ self._heads[keys] = heads
+ return heads
+
+ def cache(self, keys, heads):
+ """Store a known value."""
+ self._heads[frozenset(keys)] = frozenset(heads)
+
+
+class _BreadthFirstSearcher(object):
+ """Parallel search breadth-first the ancestry of revisions.
+
+ This class implements the iterator protocol, but additionally
+ 1. provides a set of seen ancestors, and
+ 2. allows some ancestries to be unsearched, via stop_searching_any
+ """
+
+ def __init__(self, revisions, parents_provider):
+ self._iterations = 0
+ self._next_query = set(revisions)
+ self.seen = set()
+ self._started_keys = set(self._next_query)
+ self._stopped_keys = set()
+ self._parents_provider = parents_provider
+ self._returning = 'next_with_ghosts'
+ self._current_present = set()
+ self._current_ghosts = set()
+ self._current_parents = {}
+
+ def __repr__(self):
+ if self._iterations:
+ prefix = "searching"
+ else:
+ prefix = "starting"
+ search = '%s=%r' % (prefix, list(self._next_query))
+ return ('_BreadthFirstSearcher(iterations=%d, %s,'
+ ' seen=%r)' % (self._iterations, search, list(self.seen)))
+
+ def get_state(self):
+ """Get the current state of this searcher.
+
+ :return: Tuple with started keys, excludes and included keys
+ """
+ if self._returning == 'next':
+ # We have to know the current nodes children to be able to list the
+ # exclude keys for them. However, while we could have a second
+ # look-ahead result buffer and shuffle things around, this method
+ # is typically only called once per search - when memoising the
+ # results of the search.
+ found, ghosts, next, parents = self._do_query(self._next_query)
+ # pretend we didn't query: perhaps we should tweak _do_query to be
+ # entirely stateless?
+ self.seen.difference_update(next)
+ next_query = next.union(ghosts)
+ else:
+ next_query = self._next_query
+ excludes = self._stopped_keys.union(next_query)
+ included_keys = self.seen.difference(excludes)
+ return self._started_keys, excludes, included_keys
+
+ def _get_result(self):
+ """Get a SearchResult for the current state of this searcher.
+
+ :return: A SearchResult for this search so far. The SearchResult is
+ static - the search can be advanced and the search result will not
+ be invalidated or altered.
+ """
+ from bzrlib.vf_search import SearchResult
+ (started_keys, excludes, included_keys) = self.get_state()
+ return SearchResult(started_keys, excludes, len(included_keys),
+ included_keys)
+
+ def step(self):
+ try:
+ return self.next()
+ except StopIteration:
+ return ()
+
+ def next(self):
+ """Return the next ancestors of this revision.
+
+ Ancestors are returned in the order they are seen in a breadth-first
+ traversal. No ancestor will be returned more than once. Ancestors are
+ returned before their parentage is queried, so ghosts and missing
+ revisions (including the start revisions) are included in the result.
+ This can save a round trip in LCA style calculation by allowing
+ convergence to be detected without reading the data for the revision
+ the convergence occurs on.
+
+ :return: A set of revision_ids.
+ """
+ if self._returning != 'next':
+ # switch to returning the query, not the results.
+ self._returning = 'next'
+ self._iterations += 1
+ else:
+ self._advance()
+ if len(self._next_query) == 0:
+ raise StopIteration()
+ # We have seen what we're querying at this point as we are returning
+ # the query, not the results.
+ self.seen.update(self._next_query)
+ return self._next_query
+
+ def next_with_ghosts(self):
+ """Return the next found ancestors, with ghosts split out.
+
+ Ancestors are returned in the order they are seen in a breadth-first
+ traversal. No ancestor will be returned more than once. Ancestors are
+ returned only after asking for their parents, which allows us to detect
+ which revisions are ghosts and which are not.
+
+ :return: A tuple with (present ancestors, ghost ancestors) sets.
+ """
+ if self._returning != 'next_with_ghosts':
+ # switch to returning the results, not the current query.
+ self._returning = 'next_with_ghosts'
+ self._advance()
+ if len(self._next_query) == 0:
+ raise StopIteration()
+ self._advance()
+ return self._current_present, self._current_ghosts
+
+ def _advance(self):
+ """Advance the search.
+
+ Updates self.seen, self._next_query, self._current_present,
+ self._current_ghosts, self._current_parents and self._iterations.
+ """
+ self._iterations += 1
+ found, ghosts, next, parents = self._do_query(self._next_query)
+ self._current_present = found
+ self._current_ghosts = ghosts
+ self._next_query = next
+ self._current_parents = parents
+ # ghosts are implicit stop points, otherwise the search cannot be
+ # repeated when ghosts are filled.
+ self._stopped_keys.update(ghosts)
+
+ def _do_query(self, revisions):
+ """Query for revisions.
+
+ Adds revisions to the seen set.
+
+ :param revisions: Revisions to query.
+ :return: A tuple: (set(found_revisions), set(ghost_revisions),
+ set(parents_of_found_revisions), dict(found_revisions:parents)).
+ """
+ found_revisions = set()
+ parents_of_found = set()
+ # revisions may contain nodes that point to other nodes in revisions:
+ # we want to filter them out.
+ seen = self.seen
+ seen.update(revisions)
+ parent_map = self._parents_provider.get_parent_map(revisions)
+ found_revisions.update(parent_map)
+ for rev_id, parents in parent_map.iteritems():
+ if parents is None:
+ continue
+ new_found_parents = [p for p in parents if p not in seen]
+ if new_found_parents:
+ # Calling set.update() with an empty generator is actually
+ # rather expensive.
+ parents_of_found.update(new_found_parents)
+ ghost_revisions = revisions - found_revisions
+ return found_revisions, ghost_revisions, parents_of_found, parent_map
+
+ def __iter__(self):
+ return self
+
+ def find_seen_ancestors(self, revisions):
+ """Find ancestors of these revisions that have already been seen.
+
+ This function generally makes the assumption that querying for the
+ parents of a node that has already been queried is reasonably cheap.
+ (eg, not a round trip to a remote host).
+ """
+ # TODO: Often we might ask one searcher for its seen ancestors, and
+ # then ask another searcher the same question. This can result in
+ # searching the same revisions repeatedly if the two searchers
+ # have a lot of overlap.
+ all_seen = self.seen
+ pending = set(revisions).intersection(all_seen)
+ seen_ancestors = set(pending)
+
+ if self._returning == 'next':
+ # self.seen contains what nodes have been returned, not what nodes
+ # have been queried. We don't want to probe for nodes that haven't
+ # been searched yet.
+ not_searched_yet = self._next_query
+ else:
+ not_searched_yet = ()
+ pending.difference_update(not_searched_yet)
+ get_parent_map = self._parents_provider.get_parent_map
+ while pending:
+ parent_map = get_parent_map(pending)
+ all_parents = []
+ # We don't care if it is a ghost, since it can't be seen if it is
+ # a ghost
+ for parent_ids in parent_map.itervalues():
+ all_parents.extend(parent_ids)
+ next_pending = all_seen.intersection(all_parents).difference(seen_ancestors)
+ seen_ancestors.update(next_pending)
+ next_pending.difference_update(not_searched_yet)
+ pending = next_pending
+
+ return seen_ancestors
+
+ def stop_searching_any(self, revisions):
+ """
+ Remove any of the specified revisions from the search list.
+
+ None of the specified revisions are required to be present in the
+ search list.
+
+ It is okay to call stop_searching_any() for revisions which were seen
+ in previous iterations. It is the callers responsibility to call
+ find_seen_ancestors() to make sure that current search tips that are
+ ancestors of those revisions are also stopped. All explicitly stopped
+ revisions will be excluded from the search result's get_keys(), though.
+ """
+ # TODO: does this help performance?
+ # if not revisions:
+ # return set()
+ revisions = frozenset(revisions)
+ if self._returning == 'next':
+ stopped = self._next_query.intersection(revisions)
+ self._next_query = self._next_query.difference(revisions)
+ else:
+ stopped_present = self._current_present.intersection(revisions)
+ stopped = stopped_present.union(
+ self._current_ghosts.intersection(revisions))
+ self._current_present.difference_update(stopped)
+ self._current_ghosts.difference_update(stopped)
+ # stopping 'x' should stop returning parents of 'x', but
+ # not if 'y' always references those same parents
+ stop_rev_references = {}
+ for rev in stopped_present:
+ for parent_id in self._current_parents[rev]:
+ if parent_id not in stop_rev_references:
+ stop_rev_references[parent_id] = 0
+ stop_rev_references[parent_id] += 1
+ # if only the stopped revisions reference it, the ref count will be
+ # 0 after this loop
+ for parents in self._current_parents.itervalues():
+ for parent_id in parents:
+ try:
+ stop_rev_references[parent_id] -= 1
+ except KeyError:
+ pass
+ stop_parents = set()
+ for rev_id, refs in stop_rev_references.iteritems():
+ if refs == 0:
+ stop_parents.add(rev_id)
+ self._next_query.difference_update(stop_parents)
+ self._stopped_keys.update(stopped)
+ self._stopped_keys.update(revisions)
+ return stopped
+
+ def start_searching(self, revisions):
+ """Add revisions to the search.
+
+ The parents of revisions will be returned from the next call to next()
+ or next_with_ghosts(). If next_with_ghosts was the most recently used
+ next* call then the return value is the result of looking up the
+ ghost/not ghost status of revisions. (A tuple (present, ghosted)).
+ """
+ revisions = frozenset(revisions)
+ self._started_keys.update(revisions)
+ new_revisions = revisions.difference(self.seen)
+ if self._returning == 'next':
+ self._next_query.update(new_revisions)
+ self.seen.update(new_revisions)
+ else:
+ # perform a query on revisions
+ revs, ghosts, query, parents = self._do_query(revisions)
+ self._stopped_keys.update(ghosts)
+ self._current_present.update(revs)
+ self._current_ghosts.update(ghosts)
+ self._next_query.update(query)
+ self._current_parents.update(parents)
+ return revs, ghosts
+
+
+def invert_parent_map(parent_map):
+ """Given a map from child => parents, create a map of parent=>children"""
+ child_map = {}
+ for child, parents in parent_map.iteritems():
+ for p in parents:
+ # Any given parent is likely to have only a small handful
+ # of children, many will have only one. So we avoid mem overhead of
+ # a list, in exchange for extra copying of tuples
+ if p not in child_map:
+ child_map[p] = (child,)
+ else:
+ child_map[p] = child_map[p] + (child,)
+ return child_map
+
+
+def collapse_linear_regions(parent_map):
+ """Collapse regions of the graph that are 'linear'.
+
+ For example::
+
+ A:[B], B:[C]
+
+ can be collapsed by removing B and getting::
+
+ A:[C]
+
+ :param parent_map: A dictionary mapping children to their parents
+ :return: Another dictionary with 'linear' chains collapsed
+ """
+ # Note: this isn't a strictly minimal collapse. For example:
+ # A
+ # / \
+ # B C
+ # \ /
+ # D
+ # |
+ # E
+ # Will not have 'D' removed, even though 'E' could fit. Also:
+ # A
+ # | A
+ # B => |
+ # | C
+ # C
+ # A and C are both kept because they are edges of the graph. We *could* get
+ # rid of A if we wanted.
+ # A
+ # / \
+ # B C
+ # | |
+ # D E
+ # \ /
+ # F
+ # Will not have any nodes removed, even though you do have an
+ # 'uninteresting' linear D->B and E->C
+ children = {}
+ for child, parents in parent_map.iteritems():
+ children.setdefault(child, [])
+ for p in parents:
+ children.setdefault(p, []).append(child)
+
+ orig_children = dict(children)
+ removed = set()
+ result = dict(parent_map)
+ for node in parent_map:
+ parents = result[node]
+ if len(parents) == 1:
+ parent_children = children[parents[0]]
+ if len(parent_children) != 1:
+ # This is not the only child
+ continue
+ node_children = children[node]
+ if len(node_children) != 1:
+ continue
+ child_parents = result.get(node_children[0], None)
+ if len(child_parents) != 1:
+ # This is not its only parent
+ continue
+ # The child of this node only points at it, and the parent only has
+ # this as a child. remove this node, and join the others together
+ result[node_children[0]] = parents
+ children[parents[0]] = node_children
+ del result[node]
+ del children[node]
+ removed.add(node)
+
+ return result
+
+
+class GraphThunkIdsToKeys(object):
+ """Forwards calls about 'ids' to be about keys internally."""
+
+ def __init__(self, graph):
+ self._graph = graph
+
+ def topo_sort(self):
+ return [r for (r,) in self._graph.topo_sort()]
+
+ def heads(self, ids):
+ """See Graph.heads()"""
+ as_keys = [(i,) for i in ids]
+ head_keys = self._graph.heads(as_keys)
+ return set([h[0] for h in head_keys])
+
+ def merge_sort(self, tip_revision):
+ nodes = self._graph.merge_sort((tip_revision,))
+ for node in nodes:
+ node.key = node.key[0]
+ return nodes
+
+ def add_node(self, revision, parents):
+ self._graph.add_node((revision,), [(p,) for p in parents])
+
+
+_counters = [0,0,0,0,0,0,0]
+try:
+ from bzrlib._known_graph_pyx import KnownGraph
+except ImportError, e:
+ osutils.failed_to_load_extension(e)
+ from bzrlib._known_graph_py import KnownGraph