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| author | Georg Brandl <georg@python.org> | 2007-09-04 07:15:32 +0000 |
|---|---|---|
| committer | Georg Brandl <georg@python.org> | 2007-09-04 07:15:32 +0000 |
| commit | fdec8fd325ae9160e0dd245b775692f7e2716f3d (patch) | |
| tree | 9ae72a8fda9c8e6fd4f3be11881b32c43ab63a6c /Doc/library/difflib.rst | |
| parent | 8411d88883909df0d1228953ec79cc55f837f329 (diff) | |
| download | cpython-fdec8fd325ae9160e0dd245b775692f7e2716f3d.tar.gz | |
Convert all print statements in the docs.
Diffstat (limited to 'Doc/library/difflib.rst')
| -rw-r--r-- | Doc/library/difflib.rst | 16 |
1 files changed, 8 insertions, 8 deletions
diff --git a/Doc/library/difflib.rst b/Doc/library/difflib.rst index 8d130a1d1c..ee973bcb97 100644 --- a/Doc/library/difflib.rst +++ b/Doc/library/difflib.rst @@ -194,7 +194,7 @@ >>> diff = ndiff('one\ntwo\nthree\n'.splitlines(1), ... 'ore\ntree\nemu\n'.splitlines(1)) - >>> print ''.join(diff), + >>> print(''.join(diff), end="") - one ? ^ + ore @@ -219,11 +219,11 @@ >>> diff = ndiff('one\ntwo\nthree\n'.splitlines(1), ... 'ore\ntree\nemu\n'.splitlines(1)) >>> diff = list(diff) # materialize the generated delta into a list - >>> print ''.join(restore(diff, 1)), + >>> print(''.join(restore(diff, 1)), end="") one two three - >>> print ''.join(restore(diff, 2)), + >>> print(''.join(restore(diff, 2)), end="") ore tree emu @@ -412,8 +412,8 @@ use :meth:`set_seq2` to set the commonly used sequence once and call >>> b = "abycdf" >>> s = SequenceMatcher(None, a, b) >>> for tag, i1, i2, j1, j2 in s.get_opcodes(): - ... print ("%7s a[%d:%d] (%s) b[%d:%d] (%s)" % - ... (tag, i1, i2, a[i1:i2], j1, j2, b[j1:j2])) + ... print(("%7s a[%d:%d] (%s) b[%d:%d] (%s)" % + ... (tag, i1, i2, a[i1:i2], j1, j2, b[j1:j2]))) delete a[0:1] (q) b[0:0] () equal a[1:3] (ab) b[0:2] (ab) replace a[3:4] (x) b[2:3] (y) @@ -488,14 +488,14 @@ This example compares two strings, considering blanks to be "junk:" :: sequences. As a rule of thumb, a :meth:`ratio` value over 0.6 means the sequences are close matches:: - >>> print round(s.ratio(), 3) + >>> print(round(s.ratio(), 3)) 0.866 If you're only interested in where the sequences match, :meth:`get_matching_blocks` is handy:: >>> for block in s.get_matching_blocks(): - ... print "a[%d] and b[%d] match for %d elements" % block + ... print("a[%d] and b[%d] match for %d elements" % block) a[0] and b[0] match for 8 elements a[8] and b[17] match for 6 elements a[14] and b[23] match for 15 elements @@ -509,7 +509,7 @@ If you want to know how to change the first sequence into the second, use :meth:`get_opcodes`:: >>> for opcode in s.get_opcodes(): - ... print "%6s a[%d:%d] b[%d:%d]" % opcode + ... print("%6s a[%d:%d] b[%d:%d]" % opcode) equal a[0:8] b[0:8] insert a[8:8] b[8:17] equal a[8:14] b[17:23] |