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/* execv() function: Execute a program, replacing the current process.
Copyright (C) 2020 Free Software Foundation, Inc.
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation; either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <https://www.gnu.org/licenses/>. */
/* Written by Bruno Haible <bruno@clisp.org>, 2020. */
#include <config.h>
/* Specification. */
#include <unistd.h>
int
execv (const char *program, char * const *argv)
{
/* Pass the environment explicitly. This is needed if the program has
modified the environment using putenv() or [un]setenv(). On Windows,
processes have two environments, one in the "environment block" of the
process and managed through SetEnvironmentVariable(), and one inside the
process, in the location retrieved by the 'environ' macro. If we were
to pass NULL, the child process would inherit a copy of the environment
block - ignoring the effects of putenv() and [un]setenv(). */
return execve (program, argv, environ);
}
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