make every func literal expression allocate,

so that == on func means that the
functions originated in the same
execution of a func literal or definition.

before, there was an inconsistency:

	func() {x++} != func() {x++}

but

	func() {} == func() {}

this CL makes the second case != too,
just like

	make(map[int]int) != make(map[int]int)

R=r
DELTA=202  (71 added, 62 deleted, 69 changed)
OCL=32393
CL=32398

1 files changed, 12 insertions, 0 deletions

diff --git a/test/closure.go b/test/closure.go
index 97361a1df..8bb516d29 100644
--- a/test/closure.go
+++ b/test/closure.go
@@ -73,6 +73,10 @@ func h() {
 	f(500);
 }
 
+func newfunc() (func(int) int) {
+	return func(x int) int { return x }
+}
+
 
 func main() {
 	go f();
@@ -85,4 +89,12 @@ func main() {
 
 	go h();
 	check([]int{100,200,101,201,500,101,201,500});
+
+	x, y := newfunc(), newfunc();
+	if x == y {
+		panicln("newfunc returned same func");
+	}
+	if x(1) != 1 || y(2) != 2 {
+		panicln("newfunc returned broken funcs");
+	}
 }