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author | enge <enge@211d60ee-9f03-0410-a15a-8952a2c7a4e4> | 2010-06-17 17:40:38 +0000 |
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committer | enge <enge@211d60ee-9f03-0410-a15a-8952a2c7a4e4> | 2010-06-17 17:40:38 +0000 |
commit | 8f669fde281f3512784a5c53e3c8a1a87e5c283d (patch) | |
tree | 80af8ef84f59bcb51d8a51720b64edfc699035e5 /doc | |
parent | cdae67dc9bf52fd118eff5ea82462fef46691143 (diff) | |
download | mpc-8f669fde281f3512784a5c53e3c8a1a87e5c283d.tar.gz |
unified computation of pow_ui and pow_si in a function pow_usi, thereby
applying binary exponentiation in the case of negative exponent
git-svn-id: svn://scm.gforge.inria.fr/svn/mpc/trunk@788 211d60ee-9f03-0410-a15a-8952a2c7a4e4
Diffstat (limited to 'doc')
-rw-r--r-- | doc/algorithms.tex | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/doc/algorithms.tex b/doc/algorithms.tex index 4284ef6..6ca7454 100644 --- a/doc/algorithms.tex +++ b/doc/algorithms.tex @@ -1647,7 +1647,7 @@ on the real part and of on the imaginary part of the result. If we further assume that $(n-1) 2^{-p} \leq 1$, then -$(1 + 2^{-p})^{n-1} - 1 \leq (2 n - 2) 2^{-p}$, +$(1 + 2^{-p})^{n-1} - 1 \leq 2 (n - 1) 2^{-p}$, because $(1+\varepsilon)^m-1 = \exp(m \log(1+\varepsilon)) - 1 \leq \exp(\varepsilon m) - 1 \leq 2 \varepsilon m$ as long as $\varepsilon m \leq 1$. This gives the simplified bounds |