compiler.h: need to cast a (void *) to (char *) before adding

In the implementation of mempcpy():

Doing arithmetic on (void *) isn't permitted, so we need to cast it to
(char *); it then get automatically converted to void * by the return.

Signed-off-by: H. Peter Anvin <hpa@zytor.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/include/compiler.h b/include/compiler.h
index 25aeea1e..643e04c2 100644
--- a/include/compiler.h
+++ b/include/compiler.h
@@ -223,7 +223,7 @@ size_t strnlen(const char *s, size_t maxlen);
 #ifndef HAVE_MEMPCPY
 static inline void *mempcpy(void *dst, const void *src, size_t n)
 {
-    return memcpy(dst, src, n) + n;
+    return (char *)memcpy(dst, src, n) + n;
 }
 #endif