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# Copyright 2013 Red Hat, Inc.
# All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the "License"); you may
# not use this file except in compliance with the License. You may obtain
# a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS, WITHOUT
# WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the
# License for the specific language governing permissions and limitations
# under the License.
from ironic import api
def build_url(resource, resource_args, bookmark=False, base_url=None):
if base_url is None:
base_url = api.request.public_url
template = '%(url)s/%(res)s' if bookmark else '%(url)s/v1/%(res)s'
# FIXME(lucasagomes): I'm getting a 404 when doing a GET on
# a nested resource that the URL ends with a '/'.
# https://groups.google.com/forum/#!topic/pecan-dev/QfSeviLg5qs
template += '%(args)s' if resource_args.startswith('?') else '/%(args)s'
return template % {'url': base_url, 'res': resource, 'args': resource_args}
def make_link(rel_name, url, resource, resource_args,
bookmark=False, type=None):
"""Build a dict representing a link"""
href = build_url(resource, resource_args,
bookmark=bookmark, base_url=url)
l = {
'href': href,
'rel': rel_name
}
if type:
l['type'] = type
return l
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