Add __ne__ built-in function

In Python 3 __ne__ by default delegates to __eq__ and inverts the
result, but in Python 2 they urge you to define __ne__ when you
define __eq__ for it to work properly [1].There are no implied
relationships among the comparison operators. The truth of x==y
does not imply that x!=y is false. Accordingly, when defining
__eq__(), one should also define __ne__() so that the operators
will behave as expected.
[1]https://docs.python.org/2/reference/datamodel.html#object.__ne__
Also fixes spelling errors:resoruces.

Change-Id: Iae4ce0fe84fae810711cc8c3fdb94eb9ca1d772e
Closes-Bug: #1586268

2 files changed, 19 insertions, 3 deletions

diff --git a/keystoneclient/base.py b/keystoneclient/base.py
index d028d97..3f13a6c 100644
--- a/keystoneclient/base.py
+++ b/keystoneclient/base.py
@@ -523,6 +523,10 @@ class Resource(object):
             return False
         return self._info == other._info
 
+    def __ne__(self, other):
+        """Define inequality for resources."""
+        return not self == other
+
     def is_loaded(self):
         return self._loaded
 
diff --git a/keystoneclient/tests/unit/test_base.py b/keystoneclient/tests/unit/test_base.py
index 7a43619..9814d3d 100644
--- a/keystoneclient/tests/unit/test_base.py
+++ b/keystoneclient/tests/unit/test_base.py
@@ -58,25 +58,37 @@ class BaseTest(utils.TestCase):
         r1 = base.Resource(None, {'id': 1, 'name': 'hi'})
         r2 = base.Resource(None, {'id': 1, 'name': 'hello'})
         self.assertNotEqual(r1, r2)
+        self.assertTrue(r1 != r2)
 
         # Two resources with same ID: equal if their info is equal
+        # The truth of r1==r2 does not imply that r1!=r2 is false in PY2.
+        # Test that inequality operator is defined and that comparing equal
+        # items returns False
         r1 = base.Resource(None, {'id': 1, 'name': 'hello'})
         r2 = base.Resource(None, {'id': 1, 'name': 'hello'})
-        self.assertEqual(r1, r2)
+        self.assertTrue(r1 == r2)
+        self.assertFalse(r1 != r2)
 
-        # Two resoruces of different types: never equal
+        # Two resources of different types: never equal
         r1 = base.Resource(None, {'id': 1})
         r2 = roles.Role(None, {'id': 1})
         self.assertNotEqual(r1, r2)
+        self.assertTrue(r1 != r2)
 
         # Two resources with no ID: equal if their info is equal
+        # The truth of r1==r2 does not imply that r1!=r2 is false in PY2.
+        # Test that inequality operator is defined and that comparing equal
+        # items returns False.
         r1 = base.Resource(None, {'name': 'joe', 'age': 12})
         r2 = base.Resource(None, {'name': 'joe', 'age': 12})
-        self.assertEqual(r1, r2)
+        self.assertTrue(r1 == r2)
+        self.assertFalse(r1 != r2)
 
         r1 = base.Resource(None, {'id': 1})
         self.assertNotEqual(r1, object())
+        self.assertTrue(r1 != object())
         self.assertNotEqual(r1, {'id': 1})
+        self.assertTrue(r1 != {'id': 1})
 
     def test_human_id(self):
         r = base.Resource(None, {"name": "1 of !"})