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authorZhao Lei <zhaolei@cn.fujitsu.com>2015-09-23 18:49:26 +0800
committerZhao Lei <zhaolei@cn.fujitsu.com>2015-09-23 18:49:26 +0800
commitc7c9647a0b0bbcf6115b885895207af3343d4835 (patch)
tree1f8a59c3603817d8f4499bedafd28d5d4e5c8a55 /tools
parent6a42f662e2a474734e89a3a1dfa8a14519a81e75 (diff)
downloadtaskflow-c7c9647a0b0bbcf6115b885895207af3343d4835.tar.gz
Remove quotes from subshell call in bash script
Always no quotes for $() statement. We don't need quotes to hold blanks in result: # i=$(echo 1 2 3) # echo $i 1 2 3 # These quotes can make something wrong in some case: # i=$(echo '!') # # i="$(echo '!')" -bash: !: event not found # No real problem for current code, only to use a better code style. Change-Id: I0f43bb936f956c99603dc15aaad9db851ecf0acd Signed-off-by: Zhao Lei <zhaolei@cn.fujitsu.com>
Diffstat (limited to 'tools')
-rwxr-xr-xtools/update_states.sh2
1 files changed, 1 insertions, 1 deletions
diff --git a/tools/update_states.sh b/tools/update_states.sh
index 60ca3d4..61b54e8 100755
--- a/tools/update_states.sh
+++ b/tools/update_states.sh
@@ -12,7 +12,7 @@ if [ ! -d "$PWD/.diagram-tools" ]; then
git clone "https://github.com/vidarh/diagram-tools.git" "$PWD/.diagram-tools"
fi
-script_dir="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"
+script_dir=$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )
img_dir="$script_dir/../doc/source/img"
echo "---- Updating task state diagram ----"